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بايثون العرب | Python Arab 🇵🇸
...تعلم لغة برمجة بايثون ..... قنواتنا 》》 @Arab_Victory حسابي على github 》》https://github.com/DrDataYE . موقعنا علئ الويب 》》https://cyber1101.com
Show more📈 Analytical overview of Telegram channel بايثون العرب | Python Arab 🇵🇸
Channel بايثون العرب | Python Arab 🇵🇸 (@pythonarabe) in the Arabic language segment is an active participant. Currently, the community unites 12 746 subscribers, ranking 9 980 in the Technologies & Applications category and 6 051 in the Saudi Arabia region.
📊 Audience metrics and dynamics
Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 12 746 subscribers.
According to the latest data from 09 June, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -216 over the last 30 days and by -6 over the last 24 hours, overall reach remains high.
- Verification status: Not verified
- Engagement rate (ER): The average audience engagement rate is 0.65%. Within the first 24 hours after publication, content typically collects N/A% reactions from the total number of subscribers.
- Post reach: On average, each post receives 83 views. Within the first day, a publication typically gains 0 views.
- Reactions and interaction: The audience actively supports content: the average number of reactions per post is 2.
- Thematic interests: Content is focused on key topics such as ذَات, قَنَاة, إِنتِرنِت, بُرمُجَة, تَجمِيعَة.
📝 Description and content policy
The author describes the resource as a platform for expressing subjective opinions:
“...تعلم لغة برمجة بايثون .....
قنواتنا 》》 @Arab_Victory
حسابي على github 》》https://github.com/DrDataYE
.
موقعنا علئ الويب 》》https://cyber1101.com”
Thanks to the high frequency of updates (latest data received on 10 June, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Technologies & Applications category.
print(' Welcome ')if input('Enter >> : ') in ["الرياض" , "عمان" , "صنعاء" , "القاهرة" , "القاهره"] else print('error')
ثاني اجابة من @Hhhhhhhikku
print("Welcome" if input("Your Caty : ") =='Oman' and 'Cairo' and 'Riyad' and 'sanaa' else "Error")num1 ,num2 = 1 ,1
for f in range (12):
for I in range (12):
print(num1,' × ',num2," = ",num1*num2)
num2+=1
num1+=1
num2 = 1
print('\n'*2)
ثاني اجابة من @Hhhhhhhikku
for i in range(1,13):
print("\n")
for o in range(1,13):
print(i,"×",o,"=",i*o)
i=i+1+1