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Deloitte | COGNIZANT | IBM | CAPGEMINI

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Deloitte | COGNIZANT | IBM | CAPGEMINI
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SELECT c.customer_id, CONCAT(c.first_name, ' ', c.last_name) AS full_name, COUNT(r.rental_id) AS rental_count FROM customer c JOIN rental r ON c.customer_id = r.customer_id GROUP BY c.customer_id, c.first_name, c.last_name HAVING COUNT(r.rental_id) > 2 ORDER BY c.customer_id ASC; SQL✅ //Accenture
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def count_vowel_substring(input1): #write your code here v=set("aeiou") c=0 i=0 while i<len(input1): if input1[i] in v: j=i+1 while j<len(input1) and input1[j] not in v: j+=1 if j<len(input1): c+=1 i=j+1 else: break else: i+=1 return c Accenture✅
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