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Repost from ΠΠ»Π΅ΠΌΠ΅Π½ΡΠ°Ρ ΠΠ°ΡΠ΅ΠΌΠ°ΡΠΈΠΊΠ°
Yuqoridagi ikki hammualliflarning mana shu "Geometric Gems An Appreciation for Geometric Curiosities" turkumida 3 ta kitobi chiqqan ekan.
1. The Wonders of Triangles (175 ta)
2. The Wonders of Quadrilaterals (140 ta)
3. The Wonders of Circles (131 ta)
Geometriyaga qizquvchi barcha uchun haqiqiy zavq beradigan kitob.
@el_mat
2--π΅π'πππππ β π΅πππππ πβ
ππ₯ππππ ππππππ ππ’ππ‘ π¦π'ππ{0,2,4,6,8,}
ππ'ππ π ππ’ππππ¦ π πππππ 2ππ πππππππ ππ§
ππ'ππππππ.Β Masalan: 1354οΈβ£, 560οΈβ£
3--π΅π'πππππ β.π΅πππππ πβ
π
ππππππππ π¦ππ'πππππ πππ πππ£πππ 3ππ ππ'ππππ π ππ’ππππ¦ π ππ 3ππ πππππππ ππ§ ππ'ππππππ. Masalan: ππ
4581π4+5+8+1=18
18:3=9. ππ’πππ π 4581 3ππ ππ"πππππ
4--π΅π'πππππ β. π΅πππππ πβ
ππ₯ππππ 2π‘π ππππππ 00 ππ'ππ π.π¦πππ
ππ₯ππππ 2π‘π ππππππ 4ππ ππ'ππππ π ππ’ππππ¦ π ππ 4ππ πππππππ ππ§ ππ'ππππππ.
Masalan:700, 5728,79216
5-- ga boΚ»linish alomati β sonning oxirgi raqami 0 yoki 5 ga boΚ»linishi kerak. Masalan: 532425, 2170;
6--- ga boΚ»linish alomatiβ son 2ga va hamda 3ga boΚ»linishi kerak. Masalan: 126 β raqamlar yigindisi 9ga teng (3ga bolinadi), juft raqam bilan tugaydi (2ga bolinadi);
7--ga boΚ»linish alomati β sonning oxirgi raqamini hisobga olmaganimizdagi sondan oxirgi raqamini ikkilanganini ayirganimizdagi ayirma 0 bo'lishi yoki 7ga bo'linishi kerak. Masalan:
147:14β2β7=0
0 soni 7 soniga boΚ»linadi, demak 147 soni ham 7 soniga boΚ»linadi.
8-- ga boΚ»linish alomati β sonning oxirgi uchta raqami 000 boβlishi yoki 8 ga boΚ»linishi kerak. Masalan: 120000, 111120 (120:8Β = 15);
9--ga boΚ»linish alomati β sonning raqamlar yigΚ»indisi 9 ga boΚ»linishi kerak. Masalan: 2880
10---. ππ₯ππππ ππππππ 0ππ"ππππ ππππβπ π πππππ 10ππ πππππππ ππ§ ππ"ππππππ.
Masalan:100,40,52726360
13 --ga bo'linish alomati - sonning oxiridagi raqamini 4ga kopaytiramiz oxiridan oldingi raqamlardan tuzilgan songa natijani qoshamiz chiqgan natija 13ga bolinsa berilgan son 13ga bolinadi. Masalan: soni 16042 13ga qoldiqsiz bo'linadi yani 1604 +2*4=1604+8= 1612=13*124
16---bo'linish alomati - Agar natural son oxirgi 4 ta raqami 0000 boβlsa yoki 16 ga bo'linsa, berilgan son 16ga bo'linadi.
17--- ga bo'linish alomati - Sonning oxirgi raqami 5 ga ko'paytiramiz va oldindagi raqamlardan ayiramiz. Masalan:1003= 100-(5Γ3)= 85Γ·17=5
19--ga boΚ»linish qoidasi β sonning oxirgi raqamini 2 ga koβpaytirib oldindagi songa qo'shamiz. Masalan: 1691= 169 + (1Γ2) = 171 = 17 + (2Γ1) = 19:19= 1
23
ga bo'linish alomati - Berilgan sonning oxiridagi sonni 7 ga ko'paytiramiz va oldindagi songa qo'shamiz. Masalan:52952+(9Γ7)=11+(5Γ7)=46Γ·23=2
25- ga boΚ»linish alomati β sonning oxirgi ikki raqami 25ga bo'linishi kerak. Masalan: 1350 sonidagi 50 soni 25 ga boβlinadi.50:25=2.
1. C
2. B
3. D
4. A
5. A
6. A
7. B
8. A
9. C
10. D
11. C
12. B
13. A
14. B
15. C
16. A
17. C
18. B
19. A
20. D
21. 108β°
22. 7
23. 4
24. 675
25. 8
26. 75
27. 2
28. 18
29. 50
30. 135β°
