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Hi guys if you know any student who is good in any subject PCM/CS/English and he/she can Solve the doubts in my group please message
@venomousptr I will promote them to admin whol will Sol more doubts.
Msg before 28/07/2023
No of members in that group 2k
📚Notes on Trigonometric Equations and Identities📚
A function f(x) is said to be periodic if there exists some T > 0 such that f(x+T) = f(x) for all x in the domain of f(x).
In case, the T in the definition of period of f(x) is the smallest positive real number then this ‘T’ is called the period of f(x).
Periods of various trigonometric functions are listed below:
1) sin x has period 2π
2) cos x has period 2π
3) tan x has period π
4) sin(ax+b), cos (ax+b), sec(ax+b), cosec (ax+b) all are of period 2π/a
5) tan (ax+b) and cot (ax+b) have π/a as their period
6) |sin (ax+b)|, |cos (ax+b)|, |sec(ax+b)|, |cosec (ax+b)| all are of period π/a
7) |tan (ax+b)| and |cot (ax+b)| have π/2a as their period
➖Sum and Difference Formulae of Trigonometric Ratios
1) sin(a + ß) = sin(a)cos(ß) + cos(a)sin(ß)
2) sin(a – ß) = sin(a)cos(ß) – cos(a)sin(ß)
3) cos(a + ß) = cos(a)cos(ß) – sin(a)sin(ß)
4) cos(a – ß) = cos(a)cos(ß) + sin(a)sin(ß)
5) tan(a + ß) = [tan(a) + tan (ß)]/ [1 - tan(a)tan (ß)]
6)tan(a - ß) = [tan(a) - tan (ß)]/ [1 + tan (a) tan (ß)]
7) tan (π/4 + θ) = (1 + tan θ)/(1 - tan θ)
8) tan (π/4 - θ) = (1 - tan θ)/(1 + tan θ)
9) cot (a + ß) = [cot(a) . cot (ß) - 1]/ [cot (a) +cot (ß)]
10) cot (a - ß) = [cot(a) . cot (ß) + 1]/ [cot (ß) - cot (a)]
➖Double or Triple -Angle Identities
1) sin 2x = 2sin x cos x
2) cos2x = cos2x – sin2x = 1 – 2sin2x = 2cos2x – 1
3) tan 2x = 2 tan x / (1-tan 2x)
4) sin 3x = 3 sin x – 4 sin3x
5) cos3x = 4 cos3x – 3 cosx
6) tan 3x = (3 tan x - tan3x) / (1- 3tan 2x)
➖For angles A, B and C, we have
1) sin (A + B +C) = sinAcosBcosC + cosAsinBcosC + cosAcosBsinC - sinAsinBsinC
2) cos (A + B +C) = cosAcosBcosC- cosAsinBsinC - sinAcosBsinC - sinAsinBcosC
3) tan (A + B +C) = [tan A + tan B + tan C –tan A tan B tan C]/ [1- tan Atan B - tan B tan C –tan A tan C
4) cot (A + B +C) = [cot A cot B cot C – cotA - cot B - cot C]/ [cot A cot B + cot Bcot C + cot A cotC–1]
➖List of some other trigonometric formulas:
1) 2sinAcosB = sin(A + B) + sin (A - B)
2) 2cosAsinB = sin(A + B) - sin (A - B)
3) 2cosAcosB = cos(A + B) + cos(A - B)
4) 2sinAsinB = cos(A - B) - cos (A + B)
5) sin A + sin B = 2 sin [(A+B)/2] cos [(A-B)/2]
6) sin A - sin B = 2 sin [(A-B)/2] cos [(A+B)/2]
7) cosA + cos B = 2 cos [(A+B)/2] cos [(A-B)/2]
8) cosA - cos B = 2 sin [(A+B)/2] sin [(B-A)/2]
9) tanA ± tanB = sin (A ± B)/ cos A cos B
10)cot A ± cot B = sin (B ± A)/ sin A sin B
➖Method of solving a trigonometric equation:
1) If possible, reduce the equation in terms of any one variable, preferably x. Then solve the equation as you used to in case of a single variable.
2) Try to derive the linear/algebraic simultaneous equations from the given trigonometric equations and solve them as algebraic simultaneous equations.
3) At times, you might be required to make certain substitutions. It would be beneficial when the system has only two trigonometric functions.
➖Some results which are useful for solving trigonometric equations:
1) sin θ = sina and cosθ = cosa ⇒ θ = 2nπ + a
2) sin θ = 0 ⇒ θ = nπ
3) cosθ = 0 ⇒ θ = (2n + 1)π/2
4) tan θ = 0 ⇒ θ = nπ
5) sinθ = sina⇒ θ = nπ + (-1)na where a ∈ [–π/2, π/2]
6) cosθ= cos a ⇒ θ = 2nπ ± a, where a ∈[0,π]
7) tanθ = tana⇒ θ = nπ+ a, where a ∈[–π/2, π/2]
8) sinθ = 1 ⇒ θ= (4n + 1)π/2
9) sin θ = -1 ⇒ θ = (4n - 1) π /2
10) sin θ = -1 ⇒ θ = (2n +1) π /2
11) |sinθ| = 1⇒ θ =2nπ
12) cosθ = 1 ⇒ θ =(2n + 1)
13) |cosθ| = 1⇒ θ =nπ
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✨ Powered By : @TeamPWians
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🔥Increasings or Decreasing Order🔥
🔴 01. Melting point=
Li > Na > K > Rb > Cs
🔴 02. Colour of the flame=
Li-Red, Na-Golden, K-Violet, Rb-Red, Cs-Blue, Ca-Brick red, Sr-Blood red, Ba-Apple green
🔴 03. Stability of hydrides =
LiH > NaH > KH > RbH> CsH
🔴 04. Basic nature of hydroxides=
LIOH < NaOH < KOH < RbOH < CsOH
🔴 05. Hydration energy=
Li> Na > K> Rb > Cs
🔴 06. Reducing character=
Li > Cs > Rb > K > Na
🔴 07. Stability of +3 oxidation state=
B> Al > Ga > In > T1
🔴 08. Stability of +1 oxidation state= Ga < In < TI
🔴 09. Basic nature of the oxides and hydroxides=
B< Al< Ga < In < TI
🔴 10. Relative strength of Lewis acid= BF3 < BCl3 < BBr3 < BI3
🔴 11. Ionisation energy=
B> Al <Ga > In <TI
🔴 12. Reactivity=
C<Si< Ge < Sn <Pb
🔴 13. Metallic character=
C< Si < Ge < Sn < Pb
🔴 14. Acidic character of the oxides=
Co2 > SiO2 > Ge02 > SnO2 > PbO2
🔴 15. Reducing nature of hydrides=
CH4 < SiH4 < GeH4 < SnH4 < PbH4
🔴 16. Thermal stability of tetrahalides=
CCl4> SiCl4> GeCl4> SnCl4 > PbCl4
🔴 17. Oxidising character of M+4 species=
GeCl4 < SnCl4 < PbCl4
🔴 18. Ease of hydrolysis of tetrahalides=
SiCl4 < GeCl4 < SnCl4 < PbCI4
🔴 19. Acidic strength of trioxides=
N203 > P2O3 > As2O3
🔴 20. Acidic strength of pentoxides=
N2O2 > P2O2> As202 > Sb2O2 > Bi̟202
🔴 21. Acidic strength of oxides of nitrogen=
N2O < NO <N2O3 <N2O4 < N2O5
🔴 22. Basic nature/ bond angle/ thermal stability and dipole moment of hydrides=
NH3 > PH3 > AsH3 > SbH3 > BiH3
🔴 23. Stability of trihalides of nitrogen=
NF3 > NCl3 > NBr3
🔴 24.Lewis base strength=
NF3 <NCl3 <NBr3 < NI3
🔴 25. Ease of hydrolysis of trichlorides=
NCl3 > PCI3 > AsCl3 > SbCl3 > BiCl3
🔴 26. Lewis acid strength of trihalides of P, As, and Sb=
PCl3 > ASCl3 > SbCl3
🔴 27. Lewis acid strength among phosphorus trihalides
PF3 > PCl3 > PBr3 > PI3
🔴 28. Melting and boiling point of hydrides=
H2O > H2Te > H2Se >H2S
🔴 29. Volatility of hydrides=
H2O < H2Te < H2Se < H2S
🔴 30. Reducing nature of hydrides=
H2S < H2Se < H2Te
🔴 31. Covalent character of hydrides=
H2O < H2S < H2Se < H2Te
🔴 32. The acidic character of oxides (elements in the same oxidation state)=
SO2 > SeO2 > TeO2 > PoO2
SO3 > SeO3 > TeO3
🔴 33. Acidic character of oxide of a particular element (e.g. S)=
SO < SO2 < SO3
SO2 > TeO2 > SeO2 > PoO2
🔴 34. Bond energy of halogens=
Cl2 > Br2 > F2 > I2
🔴 35. Solubility of halogen in water =
F2 > Cl2 > Br2 > I2
🔴 36. Oxidising power=
F2 > Cl2 > Br2 > I2
🔴 37. Enthalpy of hydration of X ion=
F- > Cl- > Br- >I-
🔴 38. Reactivity of halogens:=
F> Cl> Br > I
🔴 39. Ionic character of M-X bond in halides
= M-F > M-Cl > MBr > M-I
🔴 40. Reducing character of X ion:=
I- > Br- > Cl- > F-
🔴 41. Acidic strength of halogen acids=
HI > HBr > HCI > HF
🔴 42. Reducing property of hydrogen halides
= HF < HCL < HBr < HI
🔴 43. Oxidising power of oxides of chlorine
= Cl2O > ClO2 > Cl206 > Cl2O7
🔴 44. Decreasing ionic size=
02- > F- > Na+ > Mg2+
🔴 45. Increasing acidic property=
Na2O3 < MgO < ZnO< P205
🔴 46. Increasing bond length=
N2 <02 < F2 < CL2
🔴 47. Increasing size=
Ca2+ < Cl- < S2-
🔴 48. Increasing acid strength=
HClO < HClO2 < HClO3 < HClO4
🔴 49. Increasing oxidation number of iodine=
HI< I2 <ICl <HIO4
🔴 50. Increasing thermal stability=
HOCl < HOClO < HOClO2 < HOClO3
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