Python learning
π Analytical overview of Telegram channel Python learning
Channel Python learning (@python3learning) in the English language segment is an active participant. Currently, the community unites 23 279 subscribers, ranking 8 465 in the Education category and 18 081 in the India region.
π Audience metrics and dynamics
Since its creation on Π½Π΅Π²ΡΠ΄ΠΎΠΌΠΎ, the project has demonstrated rapid growth, gathering an audience of 23 279 subscribers.
According to the latest data from 13 July, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -279 over the last 30 days and by -18 over the last 24 hours, overall reach remains high.
- Verification status: Not verified
- Engagement rate (ER): The average audience engagement rate is 8.45%. Within the first 24 hours after publication, content typically collects N/A% reactions from the total number of subscribers.
- Post reach: On average, each post receives 0 views. Within the first day, a publication typically gains 0 views.
- Reactions and interaction: The audience actively supports content: the average number of reactions per post is 0.
π Description and content policy
The author describes the resource as a platform for expressing subjective opinions:
βLearn pythonπ₯β
Thanks to the high frequency of updates (latest data received on 14 July, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.
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If you enjoy Python, AI & Dev content, follow me on Medium β€οΈnums = [3, 5, 7, 9, 12, 17, 20, 21]*Question:* Find and print all numbers in the list that are prime. *Expected Output:*
[3, 5, 7, 17]*Python Code:*
def is_prime(n):
if n < 2:
return False
for i in range(2, int(n**0.5) + 1):
if n % i == 0:
return False
return True
prime_nums = [n for n in nums if is_prime(n)]
print(prime_nums)
*Explanation:*
β Checks each number with is_prime() logic
β Uses list comprehension for concise filtering
β Prints list of all prime numbers
π¬ *Tap β€οΈ for more logic-building questions!*numbers = [1, 2, 3, 2, 4, 1, 5, 2]*Question:* Find the number that appears most frequently in the list. *Expected Output:*
2*Python Code:*
from collections import Counter
most_common_num = Counter(numbers).most_common(1)[0][0]
print(most_common_num)
*Explanation:*
β Counter() counts occurrences of each element
β most_common(1) returns the most frequent item
β Access [0][0] to get just the number
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Would you like the next one to be slightly more advanced (e.g., involving strings or list comprehensions)?