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Diamond schoolxiva Biology

⭕ Abituriyentlar va ustozlar uchun ⚫ Eng yangi testlar ⚫ Murakkab masalalar ⚫ Noodatiy #biosavollar ⚫ Olimpiada savollari ⏳ Kanal yaratilgan sana : 28.11.2020 t.me/Diamond_schoolXiva 📲 Aloqa : @Musobekyusupov @Khorezm_Bio_bot

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Fan: Majburiy fanlar Kimyo Biologiya #NobelRM 1b2a3a4b5c6c7c8d9a10a11b12d13d14b15d16c17c18b19d20c21c22a23d24b25b26c27a28d29d30d31a32b33b34b35b36c37a38d39a40d41d42b43a44a45a46b47b48d49b50c51a52d53d54b55d56d57b58a59a60c61d62b63d64b65c66c67a68b69d70b71c72c73d74b75a76d77d78b79d80a81a82d83a84c85b86b87c88c89a90b
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Blok test 28.04.24 Biologiya kimyo Biologiya ona tili adabiyot
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- O'g'lim, hamisha to'g'ri yo'ldan yur!-- dedi ota. - Otajon, yuravering, sizning izingizdan ketyabman-dedi bola👌
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Bir tip (a) va bir sinf (b) ga kiruvchilarni aniqlang. 1) dresena-bitiniya; 2) ustritsa-bedapoya shillig`i; 3) krab-krevetka; 4) zaxkash-langust. A) a-1,3; b-3,4 B) a-1,4; b-2,3 C) a-2,4; b-1,3 D) a-3,4; b-1,2
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Mean Median Mode Ranga tushunchalari darsi
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‘’MEDIAN’’ bu bizga bir nechta sonlar berilganda, dastlab ularni o’sish yoki kamayish tartibida yozib olgandan so’ng hosil bo’lgan ketma-ketlikdagi eng o’rtadagi sondir, agar o’rtada 2 ta son bo’lsa, ularni o’rta arifmetigidir Sizga tushunarli bo’lishi uchun quyidagi 2 ta savolda har birining ‘’median’’ ini topamiz: 1) 2, 4, 7, 1, 9, 3, 11 sonlarining ‘’median’’ ini topish uchun ularni o’sish tartibida yozib olamiz: 1, 2, 3, 4, 7, 9, 11 bu yerda 4 soni eng o’rtadagi son bo’lgani uchun bu sonlarning ‘’median’’ i 4 ga teng bo’ladi Javob: 4 2) 4, 1, 3, 10, 6, 9 sonlarining ‘’median’’ ini topish uchun ularni o’sish tartibida yozib olamiz: 1, 3, 4, 6, 9, 10 bu yerda 4 va 6 sonlari eng o’rtada joylashgan, shuning uchun qoida bo’yicha ikkita bo’lgani uchun ularning o’rta arifmetigini topib olamiz: (4+6):2=5 Javob: 5 Shunday qilib agar eng o’rtada 1 ta son bo’lsa o’sha son ‘’median’’ hisoblanadi agar 2 ta son bo’lsa, ularning o’rta arifmetigi hisoblanadi
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‘’MEAN’’ bu o’zimizning tilda ‘’o’rta arifmetik qiymat” degani Yani bir nechta sonlarning “MEAN” ini topish uchun, ularni hammasni qo’shib, nechta son bo’lsa shunga bo’lish kerak. Misol uchun: 5, 8, 9, 4, 14 sonlarining “mean” ini topish uchun (5+8+9+4+14):5=40:5=8 Demak bu 5 ta sonning “mean” i 8 ga teng
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“Range” bu bizga bir nechta sonlar berilganda, shu sonlar orasidagi eng katta son va eng kichik sonni orasidagi farq tushuniladi Misol uchun: 47, 38, 72, 35, 49, 52 sonlarining “range” ini topish uchun ular orasidagi eng katta son bu 72 eng kichik son esa 35, demak ularni ayirishimiz kerak 72-35=37 Javob: yuqoridagi sonlarning “range” i 37 ga teng
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,,MODE’’ bu sonlar ichida eng ko’p ishtirok etgani. Sizga tushunarli bo’lishi uchun quyidagi 3 ta savolda har birining ‘’mode’’ ni topamz: 1) 3, 7, 1, 3, 4, 8, 3 sonlarining ‘’mode’’ bu 3 ga teng chunki 3 soni eng ko’p marta ishtirok etgan Javob: 3 2) 2, 7, 2, 1, 4, 7, 3 sonlarining ‘’mode’’ bu 2 va 7 sonlari, chunki 2 dan 2 ta bor, 7 dan ham 2 ta bor, qolganlardan esa 1 ta Javob: 2 va 7 3) 1, 4, 2, 5, 3, 6 sonlarining ‘’mode’’ i mavjud emas, chunki har bir sondan faqat bir martadan ishtirok etgan Shunday qilib ‘mode’ da 1 ta javob, 2 ta yoki undan ortiq, yoki bo’lmasam javob yo’q bo’lishi ham mumkin ekan
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#Matematika “Range” bu bizga bir nechta sonlar berilganda, shu sonlar orasidagi eng katta son va eng kichik sonni orasidagi farq tushuniladi Misol uchun: 47, 38, 72, 35, 49, 52 sonlarining “range” ini topish uchun ular orasidagi eng katta son bu 72 eng kichik son esa 35, demak ularni ayirishimiz kerak 72-35=37 Javob: yuqoridagi sonlarning “range” i 37 ga teng
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Chigirtkalarda  rangining yashil bo'lishi A_B_ genlariga bog'liq, qora bo'lishi esa qolgan  barcha hollarda yuzaga chiqadi. Uchinchi juft  noallel D geni rangni yuzaga chiqishiga yordam beradi. Uning retsessiv alleli esa ingibitorlik vazifasini bajarib oq rangni yuzaga chiqaradi. Trigeterozigota  genotipli chigirtkalar tahliliy chatishtirilishi natijasida olingan avlodning necha % i qora rangli bo'ladi ?           A) 50% B) 62,5% C) 37,5%✅  D) 25%    
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Tarix tayyorlanadiganlar uchun kanal
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⚡️ @tarix_innavatsion. Siz ushbu kanalga qo'shilishingiz orqali tarixga doir bepul testlar va innavatsion qo'llanmalarga ega bo'lishingiz mumkin. Ushbu kanal yangi ochilgan bo'lishiga qaramay tarix fanidan ko'p yillik tajribaga ega repetitorlar tomonidan yuritiladi va tarix faniga doir 100% sifatli materiallar tashlab boriladi. Qisqasi qo'shilganingiz uchun pushaymon bo'lmaysiz) Imkoniyat muzqaymoqqa o'xshaydi, erib ketmasidan oldin yeb qolish kerak (Sharl Bodler) 👉 Manzil: @Tarix_innavatsion
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❗️1878. Ovogenez jarayonining o‘sish davrida (1) va birinchi meyozdan keyin (2) qanday hujayralar hosil bo‘ladi va ularda xromosomalarning qanday to‘plami bo‘ladi? A) 1. birlamchi ovotsit, 2n; 2. bitta ikkilamchi ovotsit va bitta yo‘naltiruvchi tanacha, 1n B) 1. bitta tuxum hujayra, 1n; 2. bitta yo‘naltiruvchi tanacha, 2n C) 1. birlamchi ovotsit va uchta yo‘naltiruvchi tanachalar, 1n; 2. bitta tuxum hujayra, 1n D) 1. ovogoniyalar, 2n; 2. birlamchi ovotsitlar, 1n @Muallif: Doniyor_Muxtorjonovich
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👋Assalomu aleykum👋 ❗️🇩 🇮 🇶 🇶 🇦 🇹 𝗘'𝗹𝗼𝗻❗️ 𝗕𝗶𝗼𝗹𝗼𝗴𝗶𝘆𝗮𝗱𝗮𝗻 𝘁𝗲𝘀𝘁 𝗯𝗶𝘇𝗱𝗮 𝘁𝗮𝘆𝘆𝗼𝗿 〰〰〰〰〰〰〰〰〰〰〰〰 𝗕𝘂 𝘁𝗲𝘀𝘁 𝗾𝗮𝗻𝗱𝗮𝘆 𝘃𝗮 𝗸𝗶𝗺𝗹𝗮𝗿 𝘂𝗰𝗵𝘂𝗻 𝗳𝗼𝘆𝗱𝗮𝗹𝗶 ❓𝘋𝘦𝘺𝘴𝘪𝘻𝘮𝘪? 𝘉𝘶 𝘵𝘦𝘴𝘵 𝘢𝘺𝘯𝘢𝘯 𝘴𝘪𝘻 𝙐𝘾𝙃𝙐𝙉 🔘𝙎𝙚𝙧𝙩𝙞𝙛𝙞𝙠𝙖𝙩𝙜𝙖 𝙩𝙖𝙮𝙮𝙤𝙧𝙡𝙖𝙣𝙪𝙫𝙘𝙝𝙞 🔘𝙎𝙚𝙧𝙩𝙞𝙛𝙞𝙠𝙖𝙩𝙜𝙖 𝙩𝙖𝙮𝙮𝙤𝙧𝙡𝙤𝙫𝙘𝙝𝙞✔️ 🔘𝘿𝙏𝙈(𝘉𝘔𝘉) 𝙩𝙤𝙥𝙨𝙝𝙞𝙧𝙪𝙫𝙘𝙝𝙞✔️ 🔘𝙊𝙡𝙞𝙢𝙥𝙞𝙖𝙙𝙖𝙜𝙖 𝙩𝙖𝙮𝙮𝙤𝙧𝙡𝙖𝙣𝙪𝙫𝙘𝙝𝙞 🔘𝘼𝙩𝙚𝙨𝙩𝙖𝙩𝙨𝙞𝙮𝙖𝙜𝙖 𝙩𝙖𝙮𝙤𝙧𝙡𝙖𝙣𝙪𝙫𝙘𝙝𝙞 ↪️𝙊'𝙦𝙞𝙩𝙪𝙫𝙘𝙝𝙞 𝙫𝙖 𝙤'𝙦𝙪𝙫𝙘𝙝𝙤𝙞𝙡𝙖𝙧 𝙪𝙘𝙝𝙪𝙣 𝙩𝙖𝙫𝙨𝙞𝙮𝙖 𝙚𝙩𝙞𝙡𝙖𝙙𝙞↩️ ↘️↘️↘️↘️↘️⬇️⬇️↙️↙️↙️↙️↙️ 𝙍𝙚𝙥𝙞𝙩𝙞𝙩𝙤𝙧 𝙤'𝙦𝙞𝙩𝙪𝙫𝙘𝙝𝙞𝙡𝙖𝙧𝙞𝙢𝙞𝙯 𝙪𝙘𝙝𝙪𝙣 𝙟𝙪𝙙𝙖 𝙛𝙤𝙮𝙙𝙖𝙡𝙞✔️✔️✔️ 𝙏𝙚𝙨𝙩 𝙦𝙖𝙣𝙙𝙖𝙮 𝙨𝙖𝙫𝙤𝙡𝙡𝙖𝙧𝙙𝙖𝙣 𝙞𝙗𝙤𝙧𝙖𝙩 𝙨𝙖𝙫𝙤𝙡𝙡𝙖𝙧 𝙨𝙤𝙣𝙞 𝙣𝙚𝙘𝙝𝙩𝙖 𝙙𝙚𝙮𝙨𝙞𝙯𝙢𝙞❓ 𝙅𝙖𝙢𝙞 𝘴𝘢𝘷𝘰𝘭𝘭𝘢𝘳 𝘴𝘰𝘯𝘪 850 𝘵𝘢 𝙈𝙖𝙨𝙖𝙡𝙖𝙡𝙖𝙧𝙣𝙞𝙣𝙜 𝙗𝙖'𝙯𝙞𝙡𝙖𝙧𝙞𝙣𝙞 𝗬𝗲𝗰𝗵𝗶𝗺𝗶 𝙗𝙞𝙡𝙖𝙣 𝙠𝙤'𝙨𝙖𝙩𝙞𝙡𝙜𝙖𝙣 𝙨𝙞𝙯 𝙗𝙪 𝙩𝙪𝙛𝙖𝙮𝙡𝙞 𝙣𝙖𝙛𝙖𝙦𝙖𝙩 𝙩𝙚𝙨𝙩 𝙮𝙚𝙘𝙝𝙞𝙨𝙝 𝙢𝙚𝙩𝙤𝙙𝙞𝙯𝙣𝙞 𝙗𝙖𝙡𝙠𝙞 𝙢𝙖𝙨𝙖𝙡𝙖 𝙮𝙚𝙘𝙝𝙞𝙨𝙝𝙣𝙞 𝙝𝙖𝙢 𝙤'𝙧𝙜𝙖𝙣𝙞𝙨𝙝𝙞𝙣𝙜𝙞𝙯 𝙢𝙪𝙢𝙠𝙞𝙣💯 𝑺𝒊𝒛 𝒕𝒂𝒍𝒂𝒃𝒂𝒍𝒂𝒓 𝒖𝒄𝒉𝒖𝒏 𝙌𝙐𝙇𝘼𝙔 𝙏𝙚𝙨𝙩𝙙𝙖𝙣 𝙛𝙤𝙮𝙙𝙖𝙡𝙖𝙣𝙪𝙫𝙘𝙝𝙞 𝙗𝙤'𝙡𝙜𝙖𝙣𝙡𝙖𝙧 𝙎𝙝𝙪 𝙡𝙞𝙣𝙠𝙜𝙖 𝙢𝙪𝙧𝙤𝙟𝙖𝙖𝙩 𝙦𝙞𝙡𝙨𝙞𝙣 〰〰〰〰〰〰〰〰〰〰〰〰@Biologiyadan_testlar_me 〰〰〰〰〰〰〰〰〰〰〰〰
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📍Biologiyadan masalalar #Javobli
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Blok test 28.04.24 Biologiya kimyo Biologiya ona tili adabiyot
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- O'g'lim, hamisha to'g'ri yo'ldan yur!-- dedi ota. - Otajon, yuravering, sizning izingizdan ketyabman-dedi bola👌
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Bir tip (a) va bir sinf (b) ga kiruvchilarni aniqlang. 1) dresena-bitiniya; 2) ustritsa-bedapoya shillig`i; 3) krab-krevetka; 4) zaxkash-langust. A) a-1,3; b-3,4 B) a-1,4; b-2,3 C) a-2,4; b-1,3 D) a-3,4; b-1,2
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Mean Median Mode Ranga tushunchalari darsi
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‘’MEDIAN’’ bu bizga bir nechta sonlar berilganda, dastlab ularni o’sish yoki kamayish tartibida yozib olgandan so’ng hosil bo’lgan ketma-ketlikdagi eng o’rtadagi sondir, agar o’rtada 2 ta son bo’lsa, ularni o’rta arifmetigidir Sizga tushunarli bo’lishi uchun quyidagi 2 ta savolda har birining ‘’median’’ ini topamiz: 1) 2, 4, 7, 1, 9, 3, 11 sonlarining ‘’median’’ ini topish uchun ularni o’sish tartibida yozib olamiz: 1, 2, 3, 4, 7, 9, 11 bu yerda 4 soni eng o’rtadagi son bo’lgani uchun bu sonlarning ‘’median’’ i 4 ga teng bo’ladi Javob: 4 2) 4, 1, 3, 10, 6, 9 sonlarining ‘’median’’ ini topish uchun ularni o’sish tartibida yozib olamiz: 1, 3, 4, 6, 9, 10 bu yerda 4 va 6 sonlari eng o’rtada joylashgan, shuning uchun qoida bo’yicha ikkita bo’lgani uchun ularning o’rta arifmetigini topib olamiz: (4+6):2=5 Javob: 5 Shunday qilib agar eng o’rtada 1 ta son bo’lsa o’sha son ‘’median’’ hisoblanadi agar 2 ta son bo’lsa, ularning o’rta arifmetigi hisoblanadi
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‘’MEAN’’ bu o’zimizning tilda ‘’o’rta arifmetik qiymat” degani Yani bir nechta sonlarning “MEAN” ini topish uchun, ularni hammasni qo’shib, nechta son bo’lsa shunga bo’lish kerak. Misol uchun: 5, 8, 9, 4, 14 sonlarining “mean” ini topish uchun (5+8+9+4+14):5=40:5=8 Demak bu 5 ta sonning “mean” i 8 ga teng
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