JavaScript
前往频道在 Telegram
A resourceful newsletter featuring the latest and most important news, articles, books and updates in the world of #javascript 🚀 Don't miss our Quizzes! Let's chat: @nairihar
显示更多📈 Telegram 频道 JavaScript 的分析概览
频道 JavaScript (@javascript) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 31 391 名订阅者,在 技术与应用 类别中位列第 4 368,并在 印度 地区排名第 13 234 位。
📊 受众指标与增长动态
自 невідомо 创建以来,项目保持高速增长,吸引了 31 391 名订阅者。
根据 22 六月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 -197,过去 24 小时变化为 -29,整体触达仍然可观。
- 认证状态: 未认证
- 互动率 (ER): 平均受众互动率为 5.70%。内容发布后 24 小时内通常能获得 1.95% 的反应,占订阅者总量。
- 帖子覆盖: 每篇帖子平均可获得 1 790 次浏览,首日通常累积 611 次浏览。
- 互动与反馈: 受众积极参与,单帖平均反应数为 6。
- 主题关注点: 内容集中在 javascript, console.log(gen.next().value, processdata, remix, acc 等核心主题上。
📝 描述与内容策略
作者将该频道定位为表达主观观点的平台:
“A resourceful newsletter featuring the latest and most important news, articles, books and updates in the world of #javascript 🚀 Don't miss our Quizzes!
Let's chat: @nairihar”
凭借高频更新(最新数据采集于 23 六月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 技术与应用 类别中的关键影响点。
31 391
订阅者
-2924 小时
-707 天
-19730 天
帖子存档
31 391
❓ CHALLENGE
const numbers = [1, 2, 3, 4, 5];
const result = numbers.filter(num => num % 2 === 0)
.map(num => num ** 2)
.reduce((acc, val) => acc + val, 0);
console.log(result);31 391
🤟 💚 The Node.js Valentine's Day Security Releases
Security releases had been expected to land in the past week for Node and they’re now here as v21.6.2 (Current), v20.11.1 (LTS), and v18.19.1 (LTS). They include fixes for a variety of vulnerabilities, including some high severity ones involving HTTP-based DoS attacks and privilege escalation.
RAFAEL GONZAGA AND MARCO IPPOLITO
31 391
❓ CHALLENGE *
const string = "Lorem ipsum dolor sit amet";
const result = string.split(" ")
.map(word => word.toLowerCase())
.reduce((acc, word) => {
acc[word] = (acc[word] || 0) + 1;
return acc;
}, {});
console.log(result);31 391
💥 Questions by roadmap.sh
roadmap.sh is the 6th most starred project on GitHub and is visited by hundreds of thousands of developers every month.
31 391
❓ CHALLENGE
function recursiveMaxSubarraySum(nums, startIndex = 0, currentSum = 0, maxSum = -Infinity) {
if (startIndex === nums.length) {
return maxSum;
}
currentSum = Math.max(nums[startIndex], currentSum + nums[startIndex]);
maxSum = Math.max(currentSum, maxSum);
return recursiveMaxSubarraySum(nums, startIndex + 1, currentSum, maxSum);
}
const result = recursiveMaxSubarraySum([-2, 1, -3, 4, -1, 2, 1, -5, 4]);
console.log(result);31 391
⭐️ Updates from the TC39 meeting in February 2024
Stage changes:
- Several proposals advanced to stage 1.
- Stage 2: “Promise.try”
- Stage 3: “Uint8Array to/from base64 and hex”
- Stage 4: “ArrayBuffer.prototype.transfer and friends”
- Several proposals became inactive.
New ECMAScript proposal stage: 2.7
🟨 “Stage 2.7 is equivalent to what we used to call Stage 3. It means that the design is considered complete, we have a full specification, and we need to write code (tests and non-polyfill implementations) to gain feedback and make progress. It’s a strong signal.”
🟨“Stage 3 has been strengthened and now also means that test262 conformance tests are ready. This is a useful signal to JS engines that a proposal is truly ready to be implemented.”
🟨“Why did we do this? We separated out the ‘Approved in Principle: Spec Ready’ stage from the later ‘Recommended for Implementation: Tests Ready’ stage to reduce wasted effort in writing tests before spec stability, whilst also clarifying the test readiness message to engines.”
TC39 member Jordan Harband comments: “[Stage 2.7 is] explicitly without the signal that it’s safe to ship unflagged, or use in production (which includes publishing polyfills). Stage 3 remains the signal for these things.”
ecmascript.new
31 391
❓ CHALLENGE
const numbers = [1, 2, 3, 4, 5];
const sum = numbers.reduce((acc, curr) => {
setTimeout(() => {
acc += curr;
}, 0);
return acc;
}, 0);
console.log(sum);31 391
❓ CHALLENGE
function recursiveNQueens(n) {
const board = Array.from({ length: n }, () => Array.from({ length: n }, () => "."));
const solutions = [];
const isSafe = (row, col) => {
for (let i = 0; i < row; i++) {
if (board[i][col] === "Q") return false;
const colOffset = row - i;
if (col - colOffset >= 0 && board[i][col - colOffset] === "Q") return false;
if (col + colOffset < n && board[i][col + colOffset] === "Q") return false;
}
return true;
};
const placeQueens = (row) => {
if (row === n) {
solutions.push(board.map(row => row.join("")));
return;
}
for (let col = 0; col < n; col++) {
if (isSafe(row, col)) {
board[row][col] = "Q";
placeQueens(row + 1);
board[row][col] = ".";
}
}
};
placeQueens(0);
return solutions;
}
const result = recursiveNQueens(4);
console.log(result);31 391
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31 391
❓ CHALLENGE
function recursivePascalTriangle(n, row = [1], triangle = []) {
triangle.push(row);
if (n === triangle.length) {
return triangle;
}
const nextRow = [1];
for (let i = 1; i < row.length; i++) {
nextRow.push(row[i] + row[i - 1]);
}
nextRow.push(1);
return recursivePascalTriangle(n, nextRow, triangle);
}
const result = recursivePascalTriangle(5);
console.log(result);31 391
❓ CHALLENGE
function* generatorQuiz() {
yield 1;
}
const generator = generatorQuiz();
setTimeout(() => console.log(generator.next().value), 0);
for (const value of generator) {
console.log(value);
}31 391
👀 Take a Qwik Break from React with Astro
Paul Scanlon compares React to Qwik using several examples and concludes that Qwik is at least worth exploring as a React alternative.
PAUL SCANLON
现已上线!2025 年 Telegram 研究 — 年度关键洞察 
