JavaScript
前往频道在 Telegram
A resourceful newsletter featuring the latest and most important news, articles, books and updates in the world of #javascript 🚀 Don't miss our Quizzes! Let's chat: @nairihar
显示更多📈 Telegram 频道 JavaScript 的分析概览
频道 JavaScript (@javascript) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 31 090 名订阅者,在 技术与应用 类别中位列第 4 201,并在 印度 地区排名第 12 866 位。
📊 受众指标与增长动态
自 невідомо 创建以来,项目保持高速增长,吸引了 31 090 名订阅者。
根据 29 九月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 -171,过去 24 小时变化为 -15,整体触达仍然可观。
- 认证状态: 未认证
- 互动率 (ER): 平均受众互动率为 6.01%。内容发布后 24 小时内通常能获得 2.08% 的反应,占订阅者总量。
- 帖子覆盖: 每篇帖子平均可获得 1 869 次浏览,首日通常累积 646 次浏览。
- 互动与反馈: 受众积极参与,单帖平均反应数为 4。
- 主题关注点: 内容集中在 javascript, console.log(gen.next().value, processdata, remix, acc 等核心主题上。
📝 描述与内容策略
作者将该频道定位为表达主观观点的平台:
“A resourceful newsletter featuring the latest and most important news, articles, books and updates in the world of #javascript 🚀 Don't miss our Quizzes!
Let's chat: @nairihar”
凭借高频更新(最新数据采集于 30 九月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 技术与应用 类别中的关键影响点。
31 090
订阅者
-1524 小时
-417 天
-17130 天
帖子存档
31 090
❓ CHALLENGE
function recursiveReverseString(str) {
return str === "" ? str : recursiveReverseString(str.substr(1)) + str[0];
}
const result = recursiveReverseString("hello");
console.log(result);31 090
👀A Step-by-Step Tutorial on Deploying Node.js Apps on AWS EC2
Taking the manual, 'do it all by hand' approach. A good way to learn about all the pieces involved before automating it, perhaps.
SAM MEECH-WARD
31 090
❓ CHALLENGE
function recursiveBinarySearch(arr, target, start = 0, end = arr.length - 1) {
if (start > end) {
return -1;
}
const mid = Math.floor((start + end) / 2);
if (arr[mid] === target) {
return mid;
} else if (arr[mid] < target) {
return recursiveBinarySearch(arr, target, mid + 1, end);
} else {
return recursiveBinarySearch(arr, target, start, mid - 1);
}
}
const result = recursiveBinarySearch([1, 2, 3, 4, 5, 6, 7, 8, 9], 6);
console.log(result);31 090
❓ CHALLENGE
function recursivePalindromeCheck(str) {
if (str.length <= 1) {
return true;
}
return str[0] === str[str.length - 1] && recursivePalindromeCheck(str.slice(1, -1));
}
const result = recursivePalindromeCheck("radar");
console.log(result);31 090
❓ CHALLENGE
function recursiveFibonacci(n) {
return n <= 1 ? n : recursiveFibonacci(n - 1) + recursiveFibonacci(n - 2);
}
const result = recursiveFibonacci(6);
console.log(result);31 090
❓ CHALLENGE
const fetchData = async (id) => {
return new Promise((resolve) => {
setTimeout(() => resolve(`Data for ID ${id}`), 100);
});
};
const ids = [1, 2, 3];
async function complexAsyncFetch(ids) {
const result = await ids.reduce(async (acc, id) => {
const data = await fetchData(id);
const currentResult = await acc;
currentResult.push(data);
return currentResult;
}, Promise.resolve([]));
console.log(result);
}
complexAsyncFetch(ids);31 090
✌️🍊 Jint 3.0: A JavaScript Interpreter for .NET
Run JavaScript within a .NET app and expose .NET objects and functions to JavaScript code. v3 arrives after seven years of work and is the most standards-compliant JS engine running entirely within .NET.
SÉBASTIEN ROS
31 090
❓ CHALLENGE
async function asyncQuiz() {
console.log("Start");
const promise1 = new Promise((resolve) => {
setTimeout(() => resolve("Promise 1"), 1000);
});
const promise2 = new Promise((resolve) => {
setTimeout(() => resolve("Promise 2"), 500);
});
console.log(await promise1);
console.log(await promise2);
console.log("End");
}
asyncQuiz();31 090
☄️✌️ QuickJS: The Small, Embeddable JavaScript Engine
Several years ago, Fabrice Bellard, the genius behind FFMPEG and JSLinux, built a tiny and complete JavaScript engine in C. It now supports ES2023 and its latest release adds top-level
await in modules and its REPL, as well as support for some cutting edge JS features (changelog).
FABRICE BELLARD31 090
❓ CHALLENGE
const matrix = [
[1, 2, 3],
[4, 5, 6],
[7, 8, 9],
];
async function complexMatrixOperation(matrix) {
const result = await Promise.all(matrix.map(async row => {
return await Promise.all(row.map(async num => {
if (num % 2 === 0) {
return await new Promise(resolve => setTimeout(() => resolve(num * 3), 200));
} else {
return await new Promise(resolve => setTimeout(() => resolve(num * 2), 100));
}
}));
}));
console.log(result);
}
complexMatrixOperation(matrix);