JavaScript
前往频道在 Telegram
A resourceful newsletter featuring the latest and most important news, articles, books and updates in the world of #javascript 🚀 Don't miss our Quizzes! Let's chat: @nairihar
显示更多📈 Telegram 频道 JavaScript 的分析概览
频道 JavaScript (@javascript) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 31 413 名订阅者,在 技术与应用 类别中位列第 4 370,并在 印度 地区排名第 13 353 位。
📊 受众指标与增长动态
自 невідомо 创建以来,项目保持高速增长,吸引了 31 413 名订阅者。
根据 20 六月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 -164,过去 24 小时变化为 -20,整体触达仍然可观。
- 认证状态: 未认证
- 互动率 (ER): 平均受众互动率为 5.88%。内容发布后 24 小时内通常能获得 2.24% 的反应,占订阅者总量。
- 帖子覆盖: 每篇帖子平均可获得 1 848 次浏览,首日通常累积 705 次浏览。
- 互动与反馈: 受众积极参与,单帖平均反应数为 6。
- 主题关注点: 内容集中在 javascript, console.log(gen.next().value, processdata, remix, acc 等核心主题上。
📝 描述与内容策略
作者将该频道定位为表达主观观点的平台:
“A resourceful newsletter featuring the latest and most important news, articles, books and updates in the world of #javascript 🚀 Don't miss our Quizzes!
Let's chat: @nairihar”
凭借高频更新(最新数据采集于 21 六月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 技术与应用 类别中的关键影响点。
31 413
订阅者
-2024 小时
-307 天
-16430 天
帖子存档
31 414
CHALLENGE
const arr = [1, 2, 3, 4, 5];
const sliced = arr.slice(1, 3);
const spliced = arr.splice(1, 3);
console.log(sliced, spliced, arr);31 414
CHALLENGE
const obj1 = { a: 1, b: { c: 2 } };
const obj2 = { ...obj1 };
obj1.b.c = 3;
console.log(obj2.b.c);31 414
CHALLENGE
const array = [1, 2, 3, 4, 5];
const result = array.some(n => n % 2 === 0) && array.every(n => n < 10);
console.log(result);31 414
CHALLENGE
const obj = {
a: 1,
b() {
return this.a;
}
};
const b = obj.b;
console.log(b.call({ a: 2 }));31 414
📊 Sliderland: A Minimalist Coding Playground
A slider control based visualization you can code with simple formulas. We last linked to this a few years ago, but it’s still a fun way to do some quick, visual JS math experimentation. Tixy.land is along similar lines, but based on a 2D grid.
blinry
31 414
CHALLENGE
const array = [1, 2, 3];
array[10] = 4;
console.log(array.length);
console.log(array.includes(undefined));31 414
✌️ How to Annul Promises in JavaScript
You can 'cancel' XHR and fetch requests, but can you cancel regular promises? Currently, no, but Zachary looks into doing the next best thing: telling a promise the game's up, and discarding/ignoring its eventual results.
Zachary Lee
31 414
CHALLENGE
const obj = { a: 1, b: 2 };
const proxy = new Proxy(obj, {
get(target, prop) {
return prop in target ? target[prop] : 0;
}
});
console.log(proxy.a, proxy.b, proxy.c);31 414
CHALLENGE
const array = [1, 2, 3, 4, 5];
const [first, ...rest] = array;
const modified = rest.map((n, i) => i % 2 === 0 ? n * 2 : n);
console.log(first, modified);
现已上线!2025 年 Telegram 研究 — 年度关键洞察 
