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C Programming Codes
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显示更多📈 Telegram 频道 C Programming Codes 的分析概览
频道 C Programming Codes (@c_programming_codes) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 13 365 名订阅者，在 技术与应用 类别中位列第 9 561，并在 印度 地区排名第 31 736 位。
📊 受众指标与增长动态
自 невідомо 创建以来，项目保持高速增长，吸引了 13 365 名订阅者。
根据 19 六月, 2026 的最新数据，频道保持稳定运转。过去 30 天订阅人数变化为 -224，过去 24 小时变化为 -6，整体触达仍然可观。
- 认证状态： 未认证
- 互动率 (ER)： 平均受众互动率为 9.82%。内容发布后 24 小时内通常能获得 N/A% 的反应，占订阅者总量。
- 帖子覆盖： 每篇帖子平均可获得 0 次浏览，首日通常累积 0 次浏览。
- 互动与反馈： 受众积极参与，单帖平均反应数为 0。
- 主题关注点： 内容集中在 input, string, scanf("%d, array, element 等核心主题上。
📝 描述与内容策略
作者将该频道定位为表达主观观点的平台：
“C Programming Codes || Quizzes || DSA
Learn along with the community
Any queries
admin - @Pradeep_saii”
凭借高频更新（最新数据采集于 20 六月, 2026），频道始终保持新鲜度与高覆盖。分析显示受众积极互动，使其成为 技术与应用 类别中的关键影响点。
13 365
订阅者
-624 小时
-537 天
-22430 天
帖子存档
13 365
+1Program that checks whether a number is prime or not using a for loop:
----------------------------
#include <stdio.h>
int main()
{
int n, i, flag = 0;
printf("Enter a positive integer: ");
scanf("%d", &n);
for(i = 2; i <= n/2; i++)
{
if(n % i == 0)
{
flag = 1;
break;
}
}
if (n == 1)
{
printf("1 is neither prime nor composite.\n");
}
else
{
if (flag == 0)
printf("%d is a prime number.\n", n);
else
printf("%d is not a prime number.\n", n);
}
return 0;
}
----------------------------
13 365
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13 365
+1Program to generate Fibonacci series.
-----------------------------
#include <stdio.h>
int main()
{
int n, i, t1 = 0, t2 = 1, nextTerm;
printf("Enter the number of terms: ");
scanf("%d", &n);
printf("Fibonacci Series: ");
for (i = 1; i <= n; ++i)
{
printf("%d, ", t1);
nextTerm = t1 + t2;
t1 = t2;
t2 = nextTerm;
}
return 0;
}
---------------------------------
13 365
+1Program to find the factorial of a number.
-----------------------------------
#include <stdio.h>
int main()
{
int i, num, fact=1;
printf("Enter a number: ");
scanf("%d", &num);
for(i=num; i>=1; i--)
{
fact *= i;
}
printf("Factorial of %d is: %d", num, fact);
return 0;
}
-------------------------------------
#for_loop
13 365
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13 365
+1Program to print Multiplication Table.
------------------------------
#include <stdio.h>
int main() {
int n;
printf("Enter a number: ");
scanf("%d", &n);
for(int i = 1; i <= 10; i++) {
printf("%d x %d = %d\n", n, i, n*i);
}
return 0;
}
-----------------------------
13 365
+1Program to add odd numbers from 1 to n using for loop.
-------------------------------
#include <stdio.h>
int main() {
int i,n,sum=0;
printf("Enter the value of n:");
scanf("%d",&n);
for(i=1; i<=n; i+=2)
{
printf("%d +%d =",sum,i);
sum=sum+i;
printf("%d\n",sum);
}
return 0;
}
------------------------------------
#for_loop
13 365
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13 365
+1Program to add even numbers from 1 to n using for loop.
-----------------------------------
#include <stdio.h>
int main() {
int i,n,sum=0;
printf("Enter the value of n:");
scanf("%d",&n);
for(i=0; i<=n; i+=2)
{
printf("%d +%d =",sum,i);
sum=sum+i;
printf("%d\n",sum);
}
return 0;
}
-------------------------------------
#for_loop
13 365
+1Program to add numbers from 1 to n using for loop.
---------------------------------
Program:
#include <stdio.h>
int main() {
int i,n,sum=0;
printf("Enter the value of n:");
scanf("%d",&n);
for(i=1; i<=n; i++)
{
printf("%d +%d =",sum,i);
sum=sum+i;
printf("%d\n",sum);
}
return 0;
}
-------------------------------
#for_loop
