C Programming Codes
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频道 C Programming Codes (@c_programming_codes) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 13 433 名订阅者,在 技术与应用 类别中位列第 9 525,并在 印度 地区排名第 32 112 位。
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- 主题关注点: 内容集中在 input, string, scanf("%d, array, element 等核心主题上。
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“C Programming Codes || Quizzes || DSA
Learn along with the community
Any queries
admin - @Pradeep_saii”
凭借高频更新(最新数据采集于 11 六月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 技术与应用 类别中的关键影响点。
13 433
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13 433
💻 Command Line Arguments Processing
#include <stdio.h>
#include <stdlib.h>
int main(int argc, char *argv[]) {
int num_args = argc;
if (num_args == 1) {
printf("No command-line arguments provided.n");
} else {
printf("Number of command-line arguments: %dn", num_args);
printf("Program name: %sn", argv[0]);
// Dynamically allocate memory to store the arguments
char **args = (char **)malloc((num_args - 1) * sizeof(char *));
if (args == NULL) {
printf("Memory allocation failed.n");
return 1;
}
printf("Other arguments:n");
for (int i = 1; i < num_args; i++) {
int arg_len = 0;
while (argv[i][arg_len] != '0') {
arg_len++;
}
args[i - 1] = (char *)malloc((arg_len + 1) * sizeof(char));
if (args[i - 1] == NULL) {
printf("Memory allocation failed.n");
// Free previously allocated memory
for(int j = 0; j < i - 1; j++) {
free(args[j]);
}
free(args);
return 1;
}
int j = 0;
while (argv[i][j] != '0') {
args[i - 1][j] = argv[i][j];
j++;
}
args[i - 1][j] = '0';
printf("Argument %d: %sn", i, args[i - 1]);
}
// Free the dynamically allocated memory
for (int i = 0; i < num_args - 1; i++) {
free(args[i]);
}
free(args);
}
return 0;
}
📤 Output:
Number of command-line arguments: 4 Program name: ./program Other arguments: Argument 1: hello Argument 2: world Argument 3: 123
13 433
💻 Array of Dynamic Strings
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main() {
int numStrings;
printf("Enter the number of strings: ");
scanf("%d", &numStrings);
getchar();
char **stringArray = (char **)malloc(numStrings * sizeof(char *));
if (stringArray == NULL) {
printf("Memory allocation failed.n");
return 1;
}
for (int i = 0; i < numStrings; i++) {
int stringLength;
printf("Enter the length of string %d: ", i + 1);
scanf("%d", &stringLength);
getchar();
stringArray[i] = (char *)malloc((stringLength + 1) * sizeof(char));
if (stringArray[i] == NULL) {
printf("Memory allocation failed for string %d.n", i + 1);
for (int j = 0; j < i; j++) {
free(stringArray[j]);
}
free(stringArray);
return 1;
}
printf("Enter string %d: ", i + 1);
fgets(stringArray[i], stringLength + 1, stdin);
stringArray[i][strcspn(stringArray[i], "n")] = 0;
}
printf("nEntered strings:n");
for (int i = 0; i < numStrings; i++) {
printf("String %d: %sn", i + 1, stringArray[i]);
}
for (int i = 0; i < numStrings; i++) {
free(stringArray[i]);
}
free(stringArray);
return 0;
}
📤 Output:
Input: 2 Input: 5 Input: hello Input: 3 Input: bye Output: Enter the number of strings: Enter the length of string 1: Enter string 1: Enter the length of string 2: Enter string 2: Entered strings: String 1: hello String 2: bye
13 433
💻 Dynamic Structure Allocation
#include <stdio.h>
#include <stdlib.h>
struct Person {
char name[50];
int age;
};
int main() {
struct Person *personPtr;
personPtr = (struct Person *)malloc(sizeof(struct Person));
if (personPtr == NULL) {
printf("Memory allocation failed!n");
return 1;
}
printf("Enter name: ");
scanf("%s", personPtr->name);
printf("Enter age: ");
scanf("%d", &personPtr->age);
printf("Name: %s, Age: %dn", personPtr->name, personPtr->age);
free(personPtr);
return 0;
}
📤 Output:
Input: John Input: 30 Output: Enter name: Enter age: Name: John, Age: 30
13 433
💻 Memory Pool Implementation
#include <stdio.h>
#include <stdlib.h>
#include <stdbool.h>
#define POOL_SIZE 1024
#define BLOCK_SIZE 32
typedef struct Block {
bool is_free;
struct Block *next;
} Block;
char memory_pool[POOL_SIZE];
Block *free_list;
void initialize_pool() {
int num_blocks = POOL_SIZE / BLOCK_SIZE;
Block *current_block = (Block *)memory_pool;
for (int i = 0; i < num_blocks; i++) {
current_block->is_free = true;
current_block->next = (Block *)((char *)current_block + BLOCK_SIZE);
current_block = current_block->next;
}
((Block *)((char *)current_block - BLOCK_SIZE))->next = NULL;
free_list = (Block *)memory_pool;
}
void *allocate_memory() {
if (free_list == NULL) {
printf("Memory pool is empty.n");
return NULL;
}
Block *allocated_block = free_list;
free_list = free_list->next;
allocated_block->is_free = false;
return (void *)((char *)allocated_block + sizeof(Block));
}
void deallocate_memory(void *ptr) {
if (ptr == NULL) return;
Block *block_to_free = (Block *)((char *)ptr - sizeof(Block));
block_to_free->is_free = true;
block_to_free->next = free_list;
free_list = block_to_free;
}
int main() {
initialize_pool();
int *num1 = (int *)allocate_memory();
if (num1 != NULL) {
*num1 = 42;
printf("Allocated memory: %dn", *num1);
}
int *num2 = (int *)allocate_memory();
if (num2 != NULL) {
*num2 = 99;
printf("Allocated memory: %dn", *num2);
}
deallocate_memory(num1);
deallocate_memory(num2);
return 0;
}
📤 Output:
Allocated memory: 42 Allocated memory: 99
13 433
💻 Custom Memory Allocator
#include <stdio.h>
#include <stdlib.h>
#include <stdbool.h>
#define MEMORY_SIZE 1024
static char memory[MEMORY_SIZE];
static bool memory_map[MEMORY_SIZE];
void* my_malloc(size_t size) {
if (size <= 0 || size > MEMORY_SIZE) {
return NULL;
}
for (int i = 0; i <= MEMORY_SIZE - size; i++) {
bool found = true;
for (int j = 0; j < size; j++) {
if (memory_map[i + j]) {
found = false;
break;
}
}
if (found) {
for (int j = 0; j < size; j++) {
memory_map[i + j] = true;
}
return (void*)&memory[i];
}
}
return NULL;
}
void my_free(void* ptr, size_t size) {
if (ptr == NULL) {
return;
}
char* start = (char*)memory;
char* current = (char*)ptr;
if (current < start || current >= start + MEMORY_SIZE) {
return;
}
size_t offset = current - start;
for (int i = 0; i < size; i++) {
memory_map[offset + i] = false;
}
}
int main() {
int* ptr1 = (int*)my_malloc(sizeof(int) * 5);
if (ptr1 == NULL) {
printf("Memory allocation failed!n");
return 1;
}
for (int i = 0; i < 5; i++) {
ptr1[i] = i * 2;
}
printf("Allocated memory at: %pn", (void*)ptr1);
for (int i = 0; i < 5; i++) {
printf("ptr1[%d] = %dn", i, ptr1[i]);
}
my_free(ptr1, sizeof(int) * 5);
printf("Memory freed.n");
return 0;
}
📤 Output:
Allocated memory at: 0x602000000000 ptr1[0] = 0 ptr1[1] = 2 ptr1[2] = 4 ptr1[3] = 6 ptr1[4] = 8 Memory freed.
13 433
💻 Memory Leak Detection
#include <stdio.h>
#include <stdlib.h>
int main() {
int *ptr;
ptr = (int *)malloc(sizeof(int));
if (ptr == NULL) {
printf("Memory allocation failed!n");
return 1;
}
printf("Memory allocated at address: %pn", (void *)ptr);
printf("Enter an integer value: ");
scanf("%d", ptr);
printf("Value stored: %dn", *ptr);
// free(ptr); //Uncomment this to prevent memory leak
ptr = NULL; //Setting to NULL after free is a good practice
return 0;
}
📤 Output:
Memory allocated at address: 0x12345678 Enter an integer value: 10 Value stored: 10
13 433
💻 Dynamic Array Resizing
#include <stdio.h>
#include <stdlib.h>
int main() {
int *arr;
int size = 2;
int count = 0;
int num;
arr = (int *)malloc(size * sizeof(int));
if (arr == NULL) {
printf("Memory allocation failed.n");
return 1;
}
printf("Enter numbers (enter -1 to stop):n");
while (1) {
scanf("%d", &num);
if (num == -1) {
break;
}
if (count == size) {
size *= 2;
arr = (int *)realloc(arr, size * sizeof(int));
if (arr == NULL) {
printf("Memory reallocation failed.n");
return 1;
}
}
arr[count] = num;
count++;
}
printf("The numbers you entered are:n");
for (int i = 0; i < count; i++) {
printf("%d ", arr[i]);
}
printf("n");
free(arr);
return 0;
}
📤 Output:
Input: 1 Input: 2 Input: 3 Input: 4 Input: 5 Input: -1 Output: Enter numbers (enter -1 to stop): The numbers you entered are: 1 2 3 4 5
13 433
💻 Binary Tree Implementation
#include <stdio.h>
#include <stdlib.h>
struct Node {
int data;
struct Node *left;
struct Node *right;
};
struct Node *createNode(int data) {
struct Node *newNode = (struct Node *)malloc(sizeof(struct Node));
newNode->data = data;
newNode->left = NULL;
newNode->right = NULL;
return newNode;
}
void inorderTraversal(struct Node *root) {
if (root != NULL) {
inorderTraversal(root->left);
printf("%d ", root->data);
inorderTraversal(root->right);
}
}
int main() {
struct Node *root = createNode(1);
root->left = createNode(2);
root->right = createNode(3);
root->left->left = createNode(4);
root->left->right = createNode(5);
printf("Inorder traversal of the binary tree is: ");
inorderTraversal(root);
printf("n");
return 0;
}
📤 Output:
Inorder traversal of the binary tree is: 4 2 5 1 3
13 433
💻 Queue Implementation using Dynamic Memory
#include <stdio.h>
#include <stdlib.h>
typedef struct {
int *data;
int front;
int rear;
int capacity;
} Queue;
Queue* createQueue(int capacity) {
Queue* queue = (Queue*)malloc(sizeof(Queue));
queue->capacity = capacity;
queue->front = 0;
queue->rear = -1;
queue->data = (int*)malloc(queue->capacity * sizeof(int));
return queue;
}
int isFull(Queue* queue) {
return (queue->rear == queue->capacity - 1);
}
int isEmpty(Queue* queue) {
return (queue->front > queue->rear);
}
void enqueue(Queue* queue, int item) {
if (isFull(queue)) {
printf("Queue is fulln");
return;
}
queue->rear = queue->rear + 1;
queue->data[queue->rear] = item;
printf("%d enqueued to queuen", item);
}
int dequeue(Queue* queue) {
if (isEmpty(queue)) {
printf("Queue is emptyn");
return -1;
}
int item = queue->data[queue->front];
queue->front = queue->front + 1;
return item;
}
int main() {
Queue* queue = createQueue(5);
enqueue(queue, 10);
enqueue(queue, 20);
enqueue(queue, 30);
enqueue(queue, 40);
enqueue(queue, 50);
printf("%d dequeued from queuen", dequeue(queue));
printf("%d dequeued from queuen", dequeue(queue));
printf("%d dequeued from queuen", dequeue(queue));
free(queue->data);
free(queue);
return 0;
}
📤 Output:
10 enqueued to queue 20 enqueued to queue 30 enqueued to queue 40 enqueued to queue 50 enqueued to queue 10 dequeued from queue 20 dequeued from queue 30 dequeued from queue
13 433
💻 Stack Implementation using Dynamic Memory
#include <stdio.h>
#include <stdlib.h>
struct Stack {
int *array;
int top;
unsigned capacity;
};
struct Stack* createStack(unsigned capacity) {
struct Stack* stack = (struct Stack*)malloc(sizeof(struct Stack));
stack->capacity = capacity;
stack->top = -1;
stack->array = (int*)malloc(stack->capacity * sizeof(int));
return stack;
}
int isFull(struct Stack* stack) {
return stack->top == stack->capacity - 1;
}
int isEmpty(struct Stack* stack) {
return stack->top == -1;
}
void push(struct Stack* stack, int item) {
if (isFull(stack))
return;
stack->array[++stack->top] = item;
printf("%d pushed to stackn", item);
}
int pop(struct Stack* stack) {
if (isEmpty(stack))
return -1;
return stack->array[stack->top--];
}
int peek(struct Stack* stack) {
if (isEmpty(stack))
return -1;
return stack->array[stack->top];
}
int main() {
struct Stack* stack = createStack(10);
push(stack, 10);
push(stack, 20);
push(stack, 30);
printf("%d popped from stackn", pop(stack));
printf("Top element is %dn", peek(stack));
return 0;
}
📤 Output:
10 pushed to stack 20 pushed to stack 30 pushed to stack 30 popped from stack Top element is 20
13 433
💻 Linked List Implementation
#include <stdio.h>
#include <stdlib.h>
struct Node {
int data;
struct Node *next;
};
int main() {
struct Node *head = NULL;
struct Node *temp = NULL;
int choice, value;
while (1) {
printf("1. Insert at beginningn");
printf("2. Displayn");
printf("3. Exitn");
printf("Enter your choice: ");
scanf("%d", &choice);
if (choice == 1) {
printf("Enter the value to insert: ");
scanf("%d", &value);
struct Node *newNode = (struct Node*)malloc(sizeof(struct Node));
newNode->data = value;
newNode->next = head;
head = newNode;
} else if (choice == 2) {
temp = head;
printf("Linked List: ");
while (temp != NULL) {
printf("%d ", temp->data);
temp = temp->next;
}
printf("n");
} else if (choice == 3) {
break;
} else {
printf("Invalid choice.n");
}
}
temp = head;
while (temp != NULL) {
struct Node *next = temp->next;
free(temp);
temp = next;
}
head = NULL;
return 0;
}
📤 Output:
1. Insert at beginning 2. Display 3. Exit Enter your choice: 1 Enter the value to insert: 10 1. Insert at beginning 2. Display 3. Exit Enter your choice: 1 Enter the value to insert: 20 1. Insert at beginning 2. Display 3. Exit Enter your choice: 2 Linked List: 20 10 1. Insert at beginning 2. Display 3. Exit Enter your choice: 1 Enter the value to insert: 30 1. Insert at beginning 2. Display 3. Exit Enter your choice: 2 Linked List: 30 20 10 1. Insert at beginning 2. Display 3. Exit Enter your choice: 3
13 433
💻 String Operations with Dynamic Memory
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main() {
char *str1 = NULL, *str2 = NULL, *combinedStr = NULL;
int len1, len2;
printf("Enter the length of the first string: ");
scanf("%d", &len1);
str1 = (char *)malloc((len1 + 1) * sizeof(char));
if (str1 == NULL) {
printf("Memory allocation failedn");
return 1;
}
printf("Enter the first string: ");
scanf(" %[^n]", str1);
printf("Enter the length of the second string: ");
scanf("%d", &len2);
str2 = (char *)malloc((len2 + 1) * sizeof(char));
if (str2 == NULL) {
printf("Memory allocation failedn");
free(str1);
return 1;
}
printf("Enter the second string: ");
scanf(" %[^n]", str2);
combinedStr = (char *)malloc((len1 + len2 + 1) * sizeof(char));
if (combinedStr == NULL) {
printf("Memory allocation failedn");
free(str1);
free(str2);
return 1;
}
strcpy(combinedStr, str1);
strcat(combinedStr, str2);
printf("Combined string: %sn", combinedStr);
free(str1);
free(str2);
free(combinedStr);
return 0;
}
📤 Output:
Input: 5 Input: Hello Input: 3 Input: World Output: Enter the length of the first string: Enter the first string: Enter the length of the second string: Enter the second string: Combined string: HelloWorld
13 433
💻 Matrix Operations with Dynamic Allocation
#include <stdio.h>
#include <stdlib.h>
int main() {
int rows, cols;
int i, j;
printf("Enter the number of rows: ");
scanf("%d", &rows);
printf("Enter the number of columns: ");
scanf("%d", &cols);
int **matrix = (int **)malloc(rows * sizeof(int *));
if (matrix == NULL) {
printf("Memory allocation failed.n");
return 1;
}
for (i = 0; i < rows; i++) {
matrix[i] = (int *)malloc(cols * sizeof(int));
if (matrix[i] == NULL) {
printf("Memory allocation failed.n");
// Free previously allocated memory
for (j = 0; j < i; j++) {
free(matrix[j]);
}
free(matrix);
return 1;
}
}
printf("Enter the elements of the matrix:n");
for (i = 0; i < rows; i++) {
for (j = 0; j < cols; j++) {
scanf("%d", &matrix[i][j]);
}
}
printf("The matrix is:n");
for (i = 0; i < rows; i++) {
for (j = 0; j < cols; j++) {
printf("%d ", matrix[i][j]);
}
printf("n");
}
// Free the allocated memory
for (i = 0; i < rows; i++) {
free(matrix[i]);
}
free(matrix);
return 0;
}
📤 Output:
Input: 2 Input: 3 Input: 1 Input: 2 Input: 3 Input: 4 Input: 5 Input: 6 Output: Enter the number of rows: Enter the number of columns: Enter the elements of the matrix: The matrix is: 1 2 3 4 5 6
13 433
💻 Dynamic 2D Array Operations
#include <stdio.h>
#include <stdlib.h>
int main() {
int rows, cols, i, j;
int **arr;
printf("Enter number of rows: ");
scanf("%d", &rows);
printf("Enter number of columns: ");
scanf("%d", &cols);
arr = (int **)malloc(rows * sizeof(int *));
if (arr == NULL) {
printf("Memory allocation failedn");
return 1;
}
for (i = 0; i < rows; i++) {
arr[i] = (int *)malloc(cols * sizeof(int));
if (arr[i] == NULL) {
printf("Memory allocation failedn");
for (j = 0; j < i; j++) {
free(arr[j]);
}
free(arr);
return 1;
}
}
printf("Enter elements of the array:n");
for (i = 0; i < rows; i++) {
for (j = 0; j < cols; j++) {
scanf("%d", &arr[i][j]);
}
}
printf("The array is:n");
for (i = 0; i < rows; i++) {
for (j = 0; j < cols; j++) {
printf("%d ", arr[i][j]);
}
printf("n");
}
for (i = 0; i < rows; i++) {
free(arr[i]);
}
free(arr);
return 0;
}
📤 Output:
Input: 2 Input: 3 Input: 1 Input: 2 Input: 3 Input: 4 Input: 5 Input: 6 Output: Enter number of rows: Enter number of columns: Enter elements of the array: The array is: 1 2 3 4 5 6
13 433
💻 Dynamic 1D Array Operations
#include <stdio.h>
#include <stdlib.h>
int main() {
int *arr;
int size, i;
printf("Enter the size of the array: ");
scanf("%d", &size);
arr = (int *)malloc(size * sizeof(int));
if (arr == NULL) {
printf("Memory allocation failed!n");
return 1;
}
printf("Enter the elements of the array:n");
for (i = 0; i < size; i++) {
scanf("%d", &arr[i]);
}
printf("The elements of the array are:n");
for (i = 0; i < size; i++) {
printf("%d ", arr[i]);
}
printf("n");
free(arr);
return 0;
}
📤 Output:
Input: 5 Input: 10 Input: 20 Input: 30 Input: 40 Input: 50 Output: Enter the size of the array: Enter the elements of the array: The elements of the array are: 10 20 30 40 50
13 433
💻 Find Maximum Element in Array Using Recursion
#include <stdio.h>
int findMaxRecursive(int arr[], int size) {
if (size == 1) {
return arr[0];
} else {
int maxRest = findMaxRecursive(arr, size - 1);
if (arr[size - 1] > maxRest) {
return arr[size - 1];
} else {
return maxRest;
}
}
}
int main() {
int size, i;
printf("Enter the size of the array: ");
scanf("%d", &size);
int arr[size];
printf("Enter the elements of the array:n");
for (i = 0; i < size; i++) {
scanf("%d", &arr[i]);
}
int max = findMaxRecursive(arr, size);
printf("Maximum element in the array is: %dn", max);
return 0;
}
📤 Output:
Input: 5 Input: 10 Input: 5 Input: 20 Input: 15 Input: 25 Output: Maximum element in the array is: 25 Input: 3 Input: -5 Input: 0 Input: 5 Output: Maximum element in the array is: 5 Input: 1 Input: 100 Output: Maximum element in the array is: 100
13 433
💻 Tower of Hanoi
#include <stdio.h>
void towerOfHanoi(int n, char from_rod, char to_rod, char aux_rod) {
if (n == 1) {
printf("Move disk 1 from rod %c to rod %cn", from_rod, to_rod);
return;
}
towerOfHanoi(n - 1, from_rod, aux_rod, to_rod);
printf("Move disk %d from rod %c to rod %cn", n, from_rod, to_rod);
towerOfHanoi(n - 1, aux_rod, to_rod, from_rod);
}
int main() {
int num_disks;
printf("Enter the number of disks: ");
scanf("%d", &num_disks);
towerOfHanoi(num_disks, 'A', 'C', 'B'); // A, B and C are names of rods
return 0;
}
📤 Output:
Input: 3 Output: Enter the number of disks: Move disk 1 from rod A to rod C Move disk 2 from rod A to rod B Move disk 1 from rod C to rod B Move disk 3 from rod A to rod C Move disk 1 from rod B to rod A Move disk 2 from rod B to rod C Move disk 1 from rod A to rod C
13 433
💻 Count Digits Using Recursion
#include <stdio.h>
int countDigits(int n) {
if (n == 0) {
return 0;
} else {
return 1 + countDigits(n / 10);
}
}
int main() {
int num;
printf("Enter an integer: ");
scanf("%d", &num);
int digitCount = countDigits(num);
printf("Number of digits: %dn", digitCount);
return 0;
}
📤 Output:
Input: 12345 Output: Enter an integer: Number of digits: 5 Input: 0 Output: Enter an integer: Number of digits: 0 Input: 99 Output: Enter an integer: Number of digits: 2 Input: -123 Output: Enter an integer: Number of digits: 3
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