allcoding1
前往频道在 Telegram
📈 Telegram 频道 allcoding1 的分析概览
频道 allcoding1 (@allcoding1) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 22 558 名订阅者,在 教育 类别中位列第 8 854,并在 印度 地区排名第 19 507 位。
📊 受众指标与增长动态
自 невідомо 创建以来,项目保持高速增长,吸引了 22 558 名订阅者。
根据 14 六月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 -445,过去 24 小时变化为 -14,整体触达仍然可观。
- 认证状态: 未认证
- 互动率 (ER): 平均受众互动率为 6.31%。内容发布后 24 小时内通常能获得 1.25% 的反应,占订阅者总量。
- 帖子覆盖: 每篇帖子平均可获得 1 423 次浏览,首日通常累积 282 次浏览。
- 互动与反馈: 受众积极参与,单帖平均反应数为 2。
- 主题关注点: 内容集中在 dsa, stack, namaste, javascript, learning 等核心主题上。
📝 描述与内容策略
尚未提供频道描述。
凭借高频更新(最新数据采集于 15 六月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 教育 类别中的关键影响点。
22 558
订阅者
-1424 小时
-947 天
-44530 天
帖子存档
22 558
🎯Mitsogo fresher hiring all batches
Apply:- https://www.mitsogo.com/career/opportunities-for-freshers/
Telegram:- @allcoding1_official
22 558
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22 558
500 TB Tutorials + Books + Courses + Trainings + Workshops + Educational Resources
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22 558
If people are buying 300 materials who can send screenshot and he will help in tests for free
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22 558
500 TB Tutorials + Books + Courses + Trainings + Workshops + Educational Resources
🔹Data science
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300 rupees
22 558
500 TB Tutorials + Books + Courses + Trainings + Workshops + Educational Resources
🔹Data science
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🔹Learning language resources ( English🏴 , French🇨🇵 , German🇩🇪 )
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22 558
If you want any promotions I don't take money but help my friends in exam then I will free promotion
22 558
Guys❤
👉 I am doing promotions (real Or fake) I don't know
👉I'm not forcing you. Your decision
👉I am not a responsible to you and money
22 558
500 TB Tutorials + Books + Courses + Trainings + Workshops + Educational Resources
🔹Data science
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22 558
#include <bits/stdc++.h>
using namespace std;
int main()
{
string s;
cin >> s;
int ans = 0;
map<char, int> m;
for (int i = 0; i < s.size(); i++)
{
m[s[i]]++;
}
for (auto x : m)
{
if (x.second == 1)
ans++;
}
cout << ans;
return 0;
}
Tech Mahindra
C++
22 558
#include <bits/stdc++.h>
using namespace std;
int main()
{
string s;
cin >> s;
int n;
cin >> n;
for (int i = n; i < s.size() + n; i++)
{
cout << s[i % s.size()];
}
return 0;
}
C++
22 558
char solve(string o, string r) {
string res = "";
int j = 0;
for (int i = 0; i < o.size(); i++) {
if (o[i] != r[j]) {
res += o[i];
} else {
j++;
}
}
return res[0];
}
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22 558
500 TB Tutorials + Books + Courses + Trainings + Workshops + Educational Resources
🔹Data science
🔹Python
🔹Artificial Intelligence
🔹AWS Certified
🔹Cloud
🔹BIG DATA
🔹Data Analytics
🔹BI
🔹Google Cloud Platform
🔹IT Training
🔹MBA
🔹Machine Learning
🔹Deep Learning
🔹Ethical Hacking
🔹SPSS
🔹Statistics
🔹Data Base
🔹Learning language resources ( English🏴 , French🇨🇵 , German🇩🇪 )
₹50
Contact:- @meterials_available
现已上线!2025 年 Telegram 研究 — 年度关键洞察 
