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allcoding1

allcoding1

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📈 Telegram 频道 allcoding1 的分析概览

频道 allcoding1 (@allcoding1) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 22 558 名订阅者,在 教育 类别中位列第 8 854,并在 印度 地区排名第 19 507

📊 受众指标与增长动态

невідомо 创建以来,项目保持高速增长,吸引了 22 558 名订阅者。

根据 14 六月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 -445,过去 24 小时变化为 -14,整体触达仍然可观。

  • 认证状态: 未认证
  • 互动率 (ER): 平均受众互动率为 6.31%。内容发布后 24 小时内通常能获得 1.25% 的反应,占订阅者总量。
  • 帖子覆盖: 每篇帖子平均可获得 1 423 次浏览,首日通常累积 282 次浏览。
  • 互动与反馈: 受众积极参与,单帖平均反应数为 2
  • 主题关注点: 内容集中在 dsa, stack, namaste, javascript, learning 等核心主题上。

📝 描述与内容策略

尚未提供频道描述。

凭借高频更新(最新数据采集于 15 六月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 教育 类别中的关键影响点。

22 558
订阅者
-1424 小时
-947
-44530
帖子存档
Repost from allcoding1
🎯Amazon Off Campus Hiring 2024 : Recruitment for Freshers | Register Now Eligibility: Testing Associate, Device OS: Bachelor’s degree Knowledge of QA methodology and tools Preferred: B.E,B.Tech. , MSC IT and MCA Good Communication Testing Knowledge Apply:- https://www.allcoding1.com/2024/02/amazon-off-campus-hiring-2024.html Telegram:- @allcoding1

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🎯EY is hiring for Data and Analytics Expected Salary: 5-10 LPA 🔗Apply here: https://eyglobal.yello.co/jobs/Zz403Fi4A5JV05N-0NtWSQ?job_board_id=c1riT--B2O-KySgYWsZO1Q

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🎯Tech Mahindra Off Campus drive Job Role Associate Software Engineer Qualification B.E/B.Tech/MCA/M.Sc Experience Freshers Batch 2022/2023 Salary Rs.3.25 LPA & 5.5LPA (for super coders) Job Location Across India Venue Location Virtual(Online) Last Date 4 February 2024 Apply now:- https://www.allcoding1.com/2024/02/tech-mahindra-off-campus-drive-2024.html?m=1 Telegram:- @allcoding1

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🎯 Microsoft Bulk Hiring 2024 | For Software Engineer Degree:- BE, B Tech, BA, B COM, BBA, BSC, BCA, ME, M Tech, MCA, MA, M COM, MSC, Any Graduate Batch:-  2018, 2019, 2020, 2021, 2022, 2023 ,2024 & 2025 Apply now:- https://www.allcoding1.com/2024/02/microsoft-bulk-hiring-2024-for-software.html Telegram:- @allcoding1

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🎯SAS Off Campus Drive 2024 – Associate Software Engineer – Freshers | Rs 4-8 LPA Job Role : Associate Software Developer Qualification : B.E/B/Tech/M.E. / M.Tech Experience : Freshers Job Location : Pune Package : Rs 4-8 LPA Apply Now:- https://www.allcoding1.com/2024/02/sas-off-campus-drive-2024-associate_9.html?m=1 Telegram:- @allcoding1

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🎯Atos Is Hiring Degree:- Any Graduate Batch:- 2019, 2020, 2021, 2022, 2023 & 2024 Apply Now:-  https://www.allcoding1.com/2024/02/atos-off-campus-drive-for-any-graduate.html Telegram:- @allcoding1

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🎯Position: Accountant Trainee Location: Coimbatore Experience: Fresher Qualification: B.Com. 2023 passed out https://careers.banfico.com/jobs/Careers/31483000015926001/Accountant-Trainee?source=CareerSite&t=807

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🎯Qualcomm Off Campus Recruitment Job Position:- IT Software Developer (UX/UI/Fullstack) Job ID: 3058496 Qualification:- B.Tech Batch:- 2019/2020/2021 Job Location:- Hyderabad, India Department: Software Engineering Salary Package:- As per Company Standards Job Type:- Full-time Last Date:- ASAP Apply Now:- https://www.allcoding1.com/2024/02/qualcomm-off-campus-recruitment-2024.html?m=1 Telegram:- @allcoding1

500 TB Tutorials + Books + Courses + Trainings + Workshops + Educational Resources 🔹Data science 🔹Python 🔹Artificial Intelligence 🔹AWS Certified 🔹Cloud 🔹BIG DATA 🔹Data Analytics 🔹BI 🔹Google Cloud Platform 🔹IT Training 🔹MBA 🔹Machine Learning 🔹Deep Learning 🔹Ethical Hacking 🔹SPSS 🔹Statistics 🔹Data Base 🔹Learning language resources ( English🏴󐁧󐁢󐁥󐁮󐁧󐁿 , French🇨🇵 , German🇩🇪 ) ₹50 Contact:- @meterials_available

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All this 300 rupees only Contact:- @meterials_available
+8
All this 300 rupees only Contact:-  @meterials_available

int main() { ll N; cin >> N; vector w(N); for(ll i = 0; i < N; ++i) { cin >> w[i]; } vector s(N, 15); for(ll i
int main() { ll N; cin >> N; vector<ll> w(N); for(ll i = 0; i < N; ++i) { cin >> w[i]; } vector<ll> s(N, 15); for(ll i = N-2; i >= 0; --i) { for(ll j = i+1; j < N; ++j) { if(w[i] < w[j]) { s[i] = 10; for(ll k = j+1; k < N; ++k) { if(w[j] > w[k]) { s[i] = 5; break; } } break; } } } ll g = 0; for(ll sc : s) { g += sc; } cout << g << endl; return 0; } chair manufacture @allcoding1

int main() { ll N; cin >> N; vector<ll> u(N); for(ll i = 0; i < N; ++i) { cin >> u[i]; } ll M, X; cin >> M >> X; vector<vector<ll>> a(N); for(ll i = 0; i < M; ++i) { ll x, y; cin >> x >> y; a[x].push_back(y); a[y].push_back(x); } vector<bool> v(N, false); queue<ll> q; q.push(0); v[0] = true; ll m = 0; while(!q.empty()) { ll s = q.size(); ll us = 0; for(ll i = 0; i < s; ++i) { ll n = q.front(); q.pop(); us += u[n]; for(ll nb : a[n]) { if(!v[nb]) { q.push(nb); v[nb] = true; } } } m = max(m, us); } cout << m << endl; return 0; } apartment @allcoding1

class TreeNode:     def init(self, val):         self.val = val         self.children = [] def build_tree(units, relationships):     nodes = {i: TreeNode(units[i]) for i in range(len(units))}     for rel in relationships:         parent, child = rel         nodes[parent].children.append(nodes[child])     return nodes[0]  def max_electricity_per_floor(root):     max_electricity = 0     floor_electricity = {}         def dfs(node, level):         nonlocal max_electricity         if level not in floor_electricity:             floor_electricity[level] = 0         floor_electricity[level] += node.val         max_electricity = max(max_electricity, floor_electricity[level])         for child in node.children:             dfs(child, level + 1)         dfs(root, 0)     return max_electricity num = int(input()) units = list(map(int, input().split())) numRel, memConnect = map(int, input().split()) relationships = [tuple(map(int, input().split())) for _ in range(numRel)] root = build_tree(units, relationships) result = max_electricity_per_floor(root) print(result) Apartment one @allcoding1

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All this 300 rupees only Contact:- @meterials_available
+8
All this 300 rupees only Contact:-  @meterials_available

Repost from allcoding1
All this 300 rupees only Contact:- @meterials_available
+8
All this 300 rupees only Contact:-  @meterials_available