Coding Projects
Channel specialized for advanced concepts and projects to master: * Python programming * Web development * Java programming * Artificial Intelligence * Machine Learning Managed by: @love_data
显示更多📈 Telegram 频道 Coding Projects 的分析概览
频道 Coding Projects (@programming_experts) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 65 997 名订阅者,在 技术与应用 类别中位列第 1 980,并在 印度 地区排名第 5 218 位。
📊 受众指标与增长动态
自 невідомо 创建以来,项目保持高速增长,吸引了 65 997 名订阅者。
根据 11 六月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 716,过去 24 小时变化为 20,整体触达仍然可观。
- 认证状态: 未认证
- 互动率 (ER): 平均受众互动率为 4.00%。内容发布后 24 小时内通常能获得 1.25% 的反应,占订阅者总量。
- 帖子覆盖: 每篇帖子平均可获得 2 637 次浏览,首日通常累积 823 次浏览。
- 互动与反馈: 受众积极参与,单帖平均反应数为 9。
- 主题关注点: 内容集中在 |--, algorithm, array, framework, javascript 等核心主题上。
📝 描述与内容策略
作者将该频道定位为表达主观观点的平台:
“Channel specialized for advanced concepts and projects to master:
* Python programming
* Web development
* Java programming
* Artificial Intelligence
* Machine Learning
Managed by: @love_data”
凭借高频更新(最新数据采集于 12 六月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 技术与应用 类别中的关键影响点。
Why type emails when Python can do it for you? Work smarter, not harder... unless you’re debugging. 😅💻
DISTINCT keyword in a SELECT statement to retrieve unique records. For example: SELECT DISTINCT column1, column2 FROM table;
5. Question: What is a subquery in SQL?
Answer: A subquery is a query nested inside another query. It can be used to retrieve data that will be used in the main query as a condition to further restrict the data to be retrieved.
6. Question: Explain the purpose of the GROUP BY clause.
Answer: The GROUP BY clause is used to group rows that have the same values in specified columns into summary rows, like when using aggregate functions such as COUNT, SUM, AVG, etc.
7. Question: How can you add a new record to a table?
Answer: Use the INSERT INTO statement. For example: INSERT INTO table_name (column1, column2) VALUES (value1, value2);
8. Question: What is the purpose of the HAVING clause?
Answer: The HAVING clause is used in combination with the GROUP BY clause to filter the results of aggregate functions based on a specified condition.
9. Question: Explain the concept of normalization in databases.
Answer: Normalization is the process of organizing data in a database to reduce redundancy and improve data integrity. It involves breaking down tables into smaller, related tables.
10. Question: How do you update data in a table in SQL?
Answer: Use the UPDATE statement to modify existing records in a table. For example: UPDATE table_name SET column1 = value1 WHERE condition;
Here is an amazing resources to learn & practice SQL: https://bit.ly/3FxxKPz
Share with credits: https://t.me/sqlspecialist
Hope it helps :)scipy.stats, statsmodels, pandas
Visualization: seaborn, matplotlib
💡 Quick tip: Use these formulas to crush interviews and build solid ML foundations!
💬 Tap ❤️ for moredef bubble_sort(arr):
for i in range(len(arr)):
for j in range(len(arr)-i-1):
if arr[j] > arr[j+1]:
arr[j], arr[j+1] = arr[j+1], arr[j]
*C++*void bubbleSort(int arr[], int n) {
for(int i=0; i<n-1; i++)
for(int j=0; j<n-i-1; j++)
if(arr[j] > arr[j+1])
swap(arr[j], arr[j+1]);
}
*Java*void bubbleSort(int[] arr) {
for(int i = 0; i < arr.length - 1; i++)
for(int j = 0; j < arr.length - i - 1; j++)
if(arr[j] > arr[j+1]) {
int temp = arr[j]; arr[j] = arr[j+1]; arr[j+1] = temp;
}
}
🟡 2. Binary Search – Searching Algorithm
👉 Efficiently searches a sorted array in O(log n) time.
*Python*def binary_search(arr, target):
low, high = 0, len(arr)-1
while low <= high:
mid = (low + high) // 2
if arr[mid] == target: return mid
elif arr[mid] < target: low = mid + 1
else: high = mid - 1
return -1
🟠 3. Recursion – Factorial Example
👉 Function calls itself to solve smaller subproblems.
*C++*int factorial(int n) {
if(n == 0) return 1;
return n * factorial(n - 1);
}
🔵 4. Dynamic Programming – Fibonacci (Bottom-Up)
👉 Stores previous results to avoid repeated work.
*Python*def fib(n):
dp = [0, 1]
for i in range(2, n+1):
dp.append(dp[i-1] + dp[i-2])
return dp[n]
🟣 5. Sliding Window – Max Sum Subarray of Size K
👉 Finds max sum in a subarray of fixed length in O(n) time.
*Java*int maxSum(int[] arr, int k) {
int sum = 0, max = 0;
for(int i = 0; i < k; i++) sum += arr[i];
max = sum;
for(int i = k; i < arr.length; i++) {
sum += arr[i] - arr[i - k];
if(sum > max) max = sum;
}
return max;
}
🧠 6. BFS (Breadth-First Search) – Graph Traversal
👉 Explores all neighbors before going deeper.
*Python*from collections import deque
def bfs(graph, start):
visited = set([start])
queue = deque([start])
while queue:
node = queue.popleft()
print(node)
for neighbor in graph[node]:
if neighbor not in visited:
visited.add(neighbor)
queue.append(neighbor)
👍 Tap ❤️ for more! #coding #algorithms #interviews #programming #datastructures
Note: I've addedaround code snippets to format them correctly in Telegram.
现已上线!2025 年 Telegram 研究 — 年度关键洞察 
