ch
Feedback
allcoding1_official

allcoding1_official

前往频道在 Telegram

📈 Telegram 频道 allcoding1_official 的分析概览

频道 allcoding1_official (@allcoding1_official) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 84 853 名订阅者,在 技术与应用 类别中位列第 1 498,并在 印度 地区排名第 3 495

📊 受众指标与增长动态

невідомо 创建以来,项目保持高速增长,吸引了 84 853 名订阅者。

根据 05 七月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 -1 533,过去 24 小时变化为 -100,整体触达仍然可观。

  • 认证状态: 未认证
  • 互动率 (ER): 平均受众互动率为 3.06%。内容发布后 24 小时内通常能获得 0.93% 的反应,占订阅者总量。
  • 帖子覆盖: 每篇帖子平均可获得 2 596 次浏览,首日通常累积 790 次浏览。
  • 互动与反馈: 受众积极参与,单帖平均反应数为 1
  • 主题关注点: 内容集中在 dsa, stack, namaste, javascript, dev 等核心主题上。

📝 描述与内容策略

尚未提供频道描述。

凭借高频更新(最新数据采集于 06 七月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 技术与应用 类别中的关键影响点。

84 853
订阅者
-10024 小时
-3817
-1 53330
帖子存档
Cognizant at 10 am Exam Telegram:- @allcoding1
+1
Cognizant at 10 am Exam Telegram:- @allcoding1

COGNIZANT GENC, BOSCH & ZOHO EXAM ANS GROUP @allcoding1 @allcoding1 @allcoding1 @allcoding1 @allcoding1 @allcoding1

🎯 Qualys Off Campus Drive Degree : Any Graduate Batch: 2018/ 2019/ 2020/ 2021/ 2022 Salary :- 7 LPA Apply Now:- http://www.allcoding1.com/2022/08/qualys-off-campus-drive-freshers-any.html Telegram:- @allcoding1_official

🎯Oracle Post Name ORMB Developer Degree Any Graduate Branch Any Stream Batch 2018 / 2021 / 2020 / 2021 / 2022 Salary ₹ 5 LPA* ( Expected ) Experience Fresher ( 0 – 2 years* ) Location Hyderabad India Apply Now:- http://www.allcoding1.com/2022/08/oracle-off-campus-hiring-for-ormb.html Telegram:- @allcoding1_official

🎯Oracle Post Name ORMB Developer Degree Any Graduate Branch Any Stream Batch 2018 / 2021 / 2020 / 2021 / 2022 Salary ₹ 5 LPA* ( Expected ) Experience Fresher ( 0 – 2 years* ) Location Hyderabad India Apply Now:- http://www.allcoding1.com/2022/08/oracle-off-campus-hiring-for-ormb.html Telegram:- @allcoding1_official

🎯IBM Kyndryl Hiring for Freshers as Associate – Technical Engineer | 4.2 LPA Job Role : Associate – Technical Engineer Qualification : B.E/ B.Tech/ M.E/ MTech/ B.Sc/ M.Sc/ BCA/ MCA/ Diploma Salary : 4.2 LPA Apply Now:- https://www.allcoding1.com/2022/08/ibm-kyndryl-off-campus-drive-hiring-for.html?m=1 Telegram:- @allcoding1_official

🎯 Zoho Off Campus Drive Degree : Any Graduation Batch: 2019/ 2020/ 2021/ 2022 Salary :- 5 LPA Expected Apply Now:- http://www.allcoding1.com/2022/08/zoho-off-campus-drive-freshers-any.html Telegram:- @allcoding1_official

🎯Atos Syntel Off Campus Drive | BE/ B.Tech/ B.Sc/ BCS/ MCA Job Role : Trainee Engine Education : BE/BTech/BSc/BCS/MCA CTC : 3.5 LPA+ Apply Now:- http://www.allcoding1.com/2022/08/atos-syntel-off-campus-drive-be-btech.html Telegram:- @allcoding1_official

DXC-Technology Recruitment 2022 Details Job Role: Associate Professional – Data Analyst Qualification: BE/B.Tech/BCA/MCA Batch: 2020/2021/2020/2019 Job Location: Bangalore Salary: 3.6 LPA Apply Now:- http://www.allcoding1.com/2022/08/dxc-technology-off-campus-drive-2022.html Telegram:- @allcoding1_official

🎯Cognizant Hiring 2022 Drive | For Programmer Analyst Degree: Any Graduate Batch : 2018, 2019, 2020, 2021, 2022 Salary: ₹ 3.8 LPA* Apply NOW:- http://www.allcoding1.com/2022/08/cognizant-hiring-2022-drive-for.html Telegram:- @allcoding1_official

🎯Global Edge Hiring | 2022 graduates CTC - 4LPA Direct Link :- https://www.allcoding1.com/2022/08/global-edge-hiring-2022-graduatesctc.html Telegram :- @allcoding1_official

🎯Accenture Associate Software Engineer Hiring | 4.5 LPA Job Role : Associate Software Engineer Qualification : BE/BTech/ME/MTech/MCA/MSc Batch : 2022 Salary : 4.5 LPA Apply Now:- http://www.allcoding1.com/2022/08/accenture-associate-software-engineer.html Telegram:- @allcoding1_official

bool isPrime(int n) { if (n <= 1) return false; for (int i = 2; i <= sqrt(n); i++) if (n % i == 0) return false; return true; } long calculateSumOfPrime(int inputArray_count, int *inputArray) { long ans = 0; for (int i = 0; i < inputArray_count; i++) { if (isPrime(inputArray[i])) ans += inputArray[i]; } return ans; } C++ Telegram:- @allcoding1_official

photo content
+1

// Word Subset class Solution: def wordSubsets(self, words1: List[str], words2: List[str]) -> List[str]: ans = set(words1) letters = {} for i in words2: for j in i: count = i.count(j) if j not in letters or count > letters[j]: letters[j] = count for i in words1: for j in letters: if i.count(j) < letters[j]: ans.remove(i) break return list(ans) Python 3 Telegram:- @allcoding1_official

#include using namespace std; #define ll long long int ll solve(ll n) { ll position = 1; ll m = 1; while (!(n &amp; m)) { m =
#include <bits/stdc++.h> using namespace std; #define ll long long int ll solve(ll n) { ll position = 1; ll m = 1; while (!(n & m)) { m = m << 1; position++; } return position; } int main() { // your code goes here ll n,p; cin>>n; vector<int> ans(n); for(int i=0;i<n;i++) { cin>>p; ans[i] = solve(p+1); } for(int i=0;i<n;i++) cout<<ans[i]<<"\n"; return 0; } C++ Telegram:-

class Solution { public: vector<int> frequncey(string s) { vector<int> freq(26, 0); for (int i = 0; i < s.length(); i++) freq[s[i] - 'a']++; return freq; } vector<string> wordSubsets(vector<string> &words1, vector<string> &words2) { vector<string> ans; vector<int> Freq(26, 0); for (auto &x : words2) { vector<int> freq1 = frequncey(x); for (int i = 0; i < 26; i++) Freq[i] = max(freq1[i], Freq[i]); } for (auto &x : words1) { vector<int> freq1 = frequncey(x); bool flag = true; for (int i = 0; i < 26; i++) { if (freq1[i] < Freq[i]) { flag = false; break; } } if (flag) ans.push_back(x); } return ans; } }; C++ Word Subsets Telegram:- @allcoding1_official

Total savings of year Python Telegram:-
Total savings of year Python Telegram:-

Only few tests case passed Total distan C++ language Telegram:-
Only few tests case passed Total distan C++ language Telegram:-