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allcoding1_official

allcoding1_official

前往频道在 Telegram

📈 Telegram 频道 allcoding1_official 的分析概览

频道 allcoding1_official (@allcoding1_official) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 85 467 名订阅者,在 技术与应用 类别中位列第 1 502,并在 印度 地区排名第 3 471

📊 受众指标与增长动态

невідомо 创建以来,项目保持高速增长,吸引了 85 467 名订阅者。

根据 25 六月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 -1 422,过去 24 小时变化为 -71,整体触达仍然可观。

  • 认证状态: 未认证
  • 互动率 (ER): 平均受众互动率为 2.42%。内容发布后 24 小时内通常能获得 0.88% 的反应,占订阅者总量。
  • 帖子覆盖: 每篇帖子平均可获得 2 071 次浏览,首日通常累积 749 次浏览。
  • 互动与反馈: 受众积极参与,单帖平均反应数为 4
  • 主题关注点: 内容集中在 dsa, stack, namaste, javascript, dev 等核心主题上。

📝 描述与内容策略

尚未提供频道描述。

凭借高频更新(最新数据采集于 26 六月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 技术与应用 类别中的关键影响点。

85 467
订阅者
-7124 小时
-3077
-1 42230
帖子存档
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def PowerLimit(a, b): current_resource, max_seconds = 1, 0 while a > 0 and b > 0: if a > b: current_resource, a, b = 1, a - 2
def PowerLimit(a, b):   current_resource, max_seconds = 1, 0   while a > 0 and b > 0:     if a > b:       current_resource, a, b = 1, a - 2, b + 1     else:       current_resource, b, a = 2, b - 2, a + 1     max_seconds += 1   max_seconds += a // 2 if current_resource == 1 else b // 2   return max_seconds power limit ✅

long long OneBlock(int N, vector Arr) {     vector one_indices;     for (int i = 0; i < N; ++i) {         if (Arr[i] == 1) {             one_indices.push_back(i);         }     }     if (one_indices.size() <= 1) {         return 1;     }     long long ways = 1;     for (int i = 1; i < one_indices.size(); ++i) {         int zeros_between_ones = one_indices[i] - one_indices[i - 1] - 1;         ways *= (zeros_between_ones + 1);     }     return ways; } //one block

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