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allcoding1_official

allcoding1_official

前往频道在 Telegram

📈 Telegram 频道 allcoding1_official 的分析概览

频道 allcoding1_official (@allcoding1_official) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 85 523 名订阅者,在 技术与应用 类别中位列第 1 507,并在 印度 地区排名第 3 480

📊 受众指标与增长动态

невідомо 创建以来,项目保持高速增长,吸引了 85 523 名订阅者。

根据 24 六月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 -1 369,过去 24 小时变化为 -35,整体触达仍然可观。

  • 认证状态: 未认证
  • 互动率 (ER): 平均受众互动率为 2.60%。内容发布后 24 小时内通常能获得 0.55% 的反应,占订阅者总量。
  • 帖子覆盖: 每篇帖子平均可获得 2 222 次浏览,首日通常累积 474 次浏览。
  • 互动与反馈: 受众积极参与,单帖平均反应数为 3
  • 主题关注点: 内容集中在 dsa, stack, namaste, javascript, dev 等核心主题上。

📝 描述与内容策略

尚未提供频道描述。

凭借高频更新(最新数据采集于 25 六月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 技术与应用 类别中的关键影响点。

85 523
订阅者
-3524 小时
-2687
-1 36930
帖子存档
Repost from allcoding1
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All this 300 rupees only Contact:-  @meterials_available

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Amazon Off Campus Hiring 2024 : Recruitment for Freshers | Register Now Eligibility: Testing Associate, Device OS: Bachelor’s degree Knowledge of QA methodology and tools Preferred: B.E,B.Tech. , MSC IT and MCA Good Communication Testing Knowledge Apply:- https://www.allcoding1.com/2024/02/amazon-off-campus-hiring-2024.html Telegram:- @allcoding1_official

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int solve(int N, vector<int> A, int T) {     int xa = 0;     for(int i=0; i<N; i++) {         xa ^= A[i];     }     int d = xa ^ T;     if(d == 0) return 0;     int ops = 0;     while(d > 0) {         ops += d & 1;         d >>= 1;     }     return ops; } Flip or flop ✅ Telegram:- @meterials_available

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#include <bits/stdc++.h> using namespace std; int getMinimumMoves(string word) {     unordered_map<char, int> freq;     int moves = 0;     for (char c : word) {         freq[c]++;     }     for (auto& entry : freq) {         moves += entry.second / 2;     }     return moves; } Minimum length word ✅

#include <iostream> #include <vector> #include <unordered_map> #include <sstream> using namespace std; vector<string> computeParameterValue(vector<vector<string>>& sources) {     unordered_map<string, string> final_parameters;     vector<string> order_of_keys;     for (auto& source : sources) {         for (auto& pair : source) {             stringstream ss(pair);             string key, value;             getline(ss, key, ':');             getline(ss, value, ':');             if (final_parameters.find(key) == final_parameters.end()) {                 order_of_keys.push_back(key);             }             final_parameters[key] = value;         }     }     vector<string> final_parameters_list;     for (auto& key : order_of_keys) {         final_parameters_list.push_back(final_parameters[key]);     }     return final_parameters_list; } Stock Analysis ✅

static int getAnagramPeriod(String input_str) {         int n = input_str.length();                 for (int period = 1; period <= n; period++) {             if (n % period == 0) {                 String subString = input_str.substring(0, period);                 boolean valid = true;                 for (int i = 0; i < n; i += period) {                     if (!isAnagram(subString, input_str.substring(i, i + period))) {                         valid = false;                         break;                     }                 }                 if (valid) {                     return period;                 }             }         }         return -1;     }     static boolean isAnagram(String str1, String str2) {         char[] charArray1 = str1.toCharArray();         char[] charArray2 = str2.toCharArray();         Arrays.sort(charArray1);         Arrays.sort(charArray2);         return Arrays.equals(charArray1, charArray2);     } Anagram Period ✅

Repost from allcoding1
All this 300 rupees only Contact:- @meterials_available
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All this 300 rupees only Contact:-  @meterials_available

All this 300 rupees only Contact:- @meterials_available
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