allcoding1_official
前往频道在 Telegram
📈 Telegram 频道 allcoding1_official 的分析概览
频道 allcoding1_official (@allcoding1_official) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 78 624 名订阅者,在 技术与应用 类别中位列第 1 628,并在 印度 地区排名第 3 762 位。
📊 受众指标与增长动态
自 невідомо 创建以来,项目保持高速增长,吸引了 78 624 名订阅者。
根据 02 十一月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 -1 632,过去 24 小时变化为 -57,整体触达仍然可观。
- 认证状态: 未认证
- 互动率 (ER): 平均受众互动率为 1.85%。内容发布后 24 小时内通常能获得 0.60% 的反应,占订阅者总量。
- 帖子覆盖: 每篇帖子平均可获得 1 452 次浏览,首日通常累积 471 次浏览。
- 互动与反馈: 受众积极参与,单帖平均反应数为 0。
- 主题关注点: 内容集中在 dsa, stack, namaste, javascript, dev 等核心主题上。
📝 描述与内容策略
尚未提供频道描述。
凭借高频更新(最新数据采集于 03 十一月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 技术与应用 类别中的关键影响点。
78 624
订阅者
-5724 小时
-3377 天
-1 63230 天
帖子存档
78 590
🎯IBM Off Campus Drive 2023 | For Intern Software Engineer
Job Role:- Intern Software Engineer
Qualification:- Any Bachelor’s Or Master’s Degree
Branch:- Any Branches
Batch:- 2020, 2021, 2022, 2023 & 2024
Salary:- INR 8.4 LPA*
Experience:- Fresher
Location:- Bengaluru
Apply Now:- http://www.allcoding1.com
Telegram:- @allcoding1_official
78 590
🎯Accenture Bulk Hiring For Internship Program 2023 | Work From Home
Post Name:- Developer Program
Degree:- BE, B Tech, BA, B COM, BBA, BSC, BCA, ME, M Tech, MCA, MA, M COM, MSC, Any Graduate
Branch:- All Branches
Batch:- 2017, 2018, 2019, 2020, 2021, 2022, 2023, 2024, 2025
Salary:- Not Mention
Experience:- Fresher
Location:- Work From Home
Apply Now:- http://www.allcoding1.com
Telegram:- @allcoding1_official
78 590
🎯Canva Off Campus Drive 2023 Hiring Work From Home | Freelance Copywriter
Job Role:- Freelance Copywriter
Qualification:- 12th Pass Or Any Graduate
Branch:- Any Branches
Salary:- INR 30K PM*
Experience:- Fresher (0 – 2)
Location:- Work From Hom
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Telegram:- @allcoding1_official
78 590
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Job Role:- 2024 Summer Analyst Program
Qualification:- Bachelors or Masters degree
Branch:- Any Specialization
Batch:- 2022, 2023
Salary:- INR 6 – 9* LPA
Experience:-Freshers
Location:- Pan India.
Apply Now:- http://www.allcoding1.com
Telegram:- @allcoding1_official
78 590
🎯Zoho Bulk Hiring 2023 | For UI/UX Designers
Job role :- UI/UX Designers
Degree:- BE, B Tech, BA, B COM, BBA, BSC, BCA, ME, M Tech, MCA, MA, M COM, MSC, Any Graduate
Branch:- Any Branches
Batch:- 2016, 2017, 2018,2019, 2020, 2021, 2022, 2023
Salary:- INR 6 LPA*
Experience:- Fresher
Location:- Chennai, Salem, Coimbatore, Tirunelveli, and Madurai
Apply Now:- http://www.allcoding1.com
Telegram:- @allcoding1_official
78 590
🎯 Tech Mahindra Off Campus Drive 2023 Hiring For Associate Software Engineer | 3.25 & 5.5 LPA
Job Role:Associate Software Engineer
Degree:B.E/B.Tech/MCA/M.Sc
Batch:2022/2023
Salary:Rs 3.25 & 5.5 LPA
Apply Now:- http://www.allcoding1.com
Telegram:- @allcoding1_official
78 590
🎯DXC Technology is hiring for Associate Professional Finance
Company:- DXC Technology
PositionAssociate:- Professional Finance
Qualifications:- Bachelor’s degree Batch Any Batch
Experience:- Freshers & Experienced
Location:- Chennai, India
Apply Now:- http://www.allcoding1.com
Telegram:- @allcoding1_official
78 590
🎯Amazon is hiring for Data Associate I ML Role
Education qualifications:-
Any Graduate /Graduate/ Post Graduates
Job Role : Data Associate I ML
Location: work from home
Apply Now:- http://www.allcoding1.com
Telegram:- @allcoding1_official
78 590
Merge String code
def MergeStrings(str1, str2):
if str1 is None and str2 is None:
return None
if str1 is None:
return str2
if str2 is None:
return str1
len1 = len(str1)
len2 = len(str2)
merged = [''] * (len1 + len2)
for i in range(min(len1, len2)):
if str1[i] <= str2[i]:
merged[i] = str1[i]
merged[-(i+1)] = str2[i]
else:
merged[i] = str2[i]
merged[-(i+1)] = str1[i]
if len1 > len2:
for i in range(len2, len1):
merged[i] = str1[i]
elif len2 > len1:
for i in range(len1, len2):
merged[i] = str2[i]
return ''.join(merged)
Python
join this channel 👇
@allcoding1_official
@accenture_examAns
78 590
int LetteredNumberSum(char* str, int len) {
if (str == nullptr) {
return 0;
}
int sum = 0;
for (int i = 0; i < len; i++) {
char letter = str[i];
int ans = 0;
//@allcoding1
switch (letter) {
case 'A':
ans = 1;
break;
case 'B':
ans = 10;
break;
case 'C':
ans = 100;
break;
case 'D':
ans = 1000;
break;
case 'E':
ans = 10000;
break;
case 'F':
ans = 100000;
break;
case 'G':
ans = 1000000;
break;
default:
ans = 0;
break;
}
sum += ans;
}
return sum;
}
C++
78 590
🎯Amazon is hiring for Data Associate I ML Role
Education qualifications:-
Any Graduate /Graduate/ Post Graduates
Job Role : Data Associate I ML
Location: work from home
Apply Now:- http://www.allcoding1.com
Telegram:- @allcoding1_official
