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Nodes code in python Accenture Hackdiva Code

📌IT learning courses 📌All programing courses 📌Abdul bari courses 📌Ashok IT 📌Linux 📌Networking 📌Design patterns 📌Donet 📌Docker 📌Entity framework 📌Node.js 📌ASP. Net 📌Aps. Net cro 📌java 📌JavaScript 📌full stack developer Tutorials + Books + Courses + Trainings + Workshops + Educational Resources 🔹Data science 🔹Python 🔹Artificial Intelligence 🔹AWS Certified 🔹Cloud 🔹BIG DATA 🔹Data Analytics 🔹BI 🔹Google Cloud Platform 🔹IT Training 🔹MBA 🔹Machine Learning 🔹Deep Learning 🔹Ethical Hacking 🔹SPSS 🔹Statistics 🔹Data Base 🔹Learning language resources  English , 🇫🇷 𝐂𝐘𝐁𝐄𝐑 𝐒𝐄𝐂𝐔𝐑𝐈𝐓𝐘 𝐀𝐋𝐋  𝐂𝐎𝐔𝐑𝐒𝐄 ⚡️ Basics ⚡️ Reconnaissance and Footprinting ⚡️ Network Scanning ⚡️ Enumeration ⚡️ Firewalls HIDs Honeypot ⚡️ Malware and Threats ⚡️ Mobile Platform ⚡️ Pentesting ⚡️ Sql Injection ⚡️ System Hacking ⚡️ Web Application ⚡️ Wireless Network ⚡️ Cloud Computing ⚡️ Web Server ⚡️ Social Engineering ⚡️ Session Hijacking ⚡️ Sniffing ⚡️ BufferOverflow ⚡️ Cryptography ⚡️ Denial Of Service All courses (100 rupees) Contact:- @meterials_available

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LI.GCD code in another way of solving Infosys

LI Gcd Code in python Infosys

All codes are available To easily find out ur codes Once check it 👇👇 https://www.instagram.com/allcoding1_official?igsh=ZHJpNXdpeWh1d2No

def f(S): n = len(S) lf, rf = {}, {} ls, rs = set(), set() # Initialize the rf map and rs with the entire string S for c in S: rf[c] = rf.get(c, 0) + 1 rs.add(c) mx = 0 # Traverse the string and adjust the ls and rs sets and maps for i in range(n - 1): c = S[i] lf[c] = lf.get(c, 0) + 1 rf[c] -= 1 if rf[c] == 0: rs.remove(c) ls.add(c) cs = len(ls) + len(rs) mx = max(mx, cs) return n - mx // spilit screen

public static int solve(int N, int[] A) {         int t = 0;         for (int num : A) {             t += num;         }                 int x = 0;         int y = 0;                 for (int i = 0; i < N; i++) {             int res = t - x - A[i];             if (x == res) {                 y++;             }             x += A[i];         }                 return y;     } //Equilibrium Point

def GetAnswer(N, A, B, P):     dp = [0] * (N + 1)     max_d = 0         for i in range(N - 1, -1, -1):         max_p = P[i]         min_p = P[i]                 for j in range(1, B + 1):             if i + j <= N:                 max_p = max(max_p, P[i + j - 1])                 min_p = min(min_p, P[i + j - 1])                 max_d = max(max_d, max_p - min_p)                 if i + 1 == N:             dp[i] = max(dp[i], max_d)         else:             dp[i] = max(dp[i], max_d, dp[i + 1])         return dp[0] import sys input = sys.stdin.read data = input().split() N = int(data[0]) A = int(data[1]) B = int(data[2]) P = list(map(int, data[3:])) result = GetAnswer(N, A, B, P) print(result) // XOR formaating code

def main(): import sys input = sys.stdin.read data = input().split('\n') S = data[0].strip() N = int(data[1].strip()) W = [] for i in range(N): W.append(data[2 + i].strip()) freqS = get_frequency(S) count = 0 for w in W: if is_valid_anagram_subsequence(freqS, w): count += 1 print(count) def get_frequency(S): freq = [0] * 26 for c in S: freq[ord(c) - ord('a')] += 1 return freq def is_valid_anagram_subsequence(freqS, w): freqW = [0] * 26 for c in w: freqW[ord(c) - ord('a')] += 1 for i in range(26): if freqW[i] > freqS[i]: return False return True if name == "main": main() // MInimal subarray length

MOD = 10**9 + 7 def f(X, P, L, R): s = [(x, x + p) for x, p in zip(X, P)] s.sort() c = 0 i = 0 e = L f = L while e <= R: while i < len(s) and s[i][0] <= e: f = max(f, s[i][1]) i += 1 if f == e: return -1 c += 1 e = f + 1 return c def g(N, M, X, P, Q, Qs): t = 0 for L, R in Qs: r = f(X, P, L, R) t = (t + r) % MOD return t // Lighting lamp @allcoding1_official

def f(N, L, R, A): M = 10**9 + 7 dp = [0] * (N + 1) dp[0] = 1 # There's one way to partition an empty array for i in range(1, N + 1): xv = 0 for j in range(i, 0, -1): xv ^= A[j - 1] if L <= xv <= R: dp[i] = (dp[i] + dp[j - 1]) % M return dp[N] // divide the array @allcoding1_official

Maximum code are python