allcoding1_official
前往频道在 Telegram
📈 Telegram 频道 allcoding1_official 的分析概览
频道 allcoding1_official (@allcoding1_official) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 78 229 名订阅者,在 技术与应用 类别中位列第 1 638,并在 印度 地区排名第 3 778 位。
📊 受众指标与增长动态
自 невідомо 创建以来,项目保持高速增长,吸引了 78 229 名订阅者。
根据 09 十一月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 -1 517,过去 24 小时变化为 -25,整体触达仍然可观。
- 认证状态: 未认证
- 互动率 (ER): 平均受众互动率为 2.12%。内容发布后 24 小时内通常能获得 0.63% 的反应,占订阅者总量。
- 帖子覆盖: 每篇帖子平均可获得 1 658 次浏览,首日通常累积 495 次浏览。
- 互动与反馈: 受众积极参与,单帖平均反应数为 2。
- 主题关注点: 内容集中在 dsa, stack, namaste, javascript, dev 等核心主题上。
📝 描述与内容策略
尚未提供频道描述。
凭借高频更新(最新数据采集于 10 十一月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 技术与应用 类别中的关键影响点。
78 229
订阅者
-2524 小时
-3317 天
-1 51730 天
帖子存档
78 249
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INFOSYS CODEINE ANS
3PM (22/10/22)
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78 249
(Python3)
Total Number of possible pairs(a,b)
All test cases passes
Telegram:-
78 249
MAX = 10000
# prefix[i] is going to
# store count of primes
# till i (including i).
pt =[0]*(MAX + 1)
def abc():
prime = [1]*(MAX + 1)
p = 2
while(p * p <= MAX):
if (prime[p] == 1):
i = p * 2
while(i <= MAX):
prime[i] = 0
i += p
p+=1
for p in range(2,MAX+1):
pt[p] = pt[p - 1]
if (prime[p]==1):
pt[p]+=1
//@allcoding1
def query(a,b):
return pt[b]-pt[a-1]
n=int(input())
c=0
for i in range(n):
a,b=map(int,input().split())
abc()
c+=query(a,b)
mod=10**9+7
print(c%mod)
prime numbers in range[L,R]
All test cases passed
Telegram :- @allcoding1
