allcoding1_official
前往频道在 Telegram
📈 Telegram 频道 allcoding1_official 的分析概览
频道 allcoding1_official (@allcoding1_official) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 78 714 名订阅者，在 技术与应用 类别中位列第 1 622，并在 印度 地区排名第 3 757 位。
📊 受众指标与增长动态
自 невідомо 创建以来，项目保持高速增长，吸引了 78 714 名订阅者。
根据 30 十月, 2026 的最新数据，频道保持稳定运转。过去 30 天订阅人数变化为 -1 600，过去 24 小时变化为 -27，整体触达仍然可观。
- 认证状态： 未认证
- 互动率 (ER)： 平均受众互动率为 1.38%。内容发布后 24 小时内通常能获得 0.62% 的反应，占订阅者总量。
- 帖子覆盖： 每篇帖子平均可获得 1 091 次浏览，首日通常累积 486 次浏览。
- 互动与反馈： 受众积极参与，单帖平均反应数为 0。
- 主题关注点： 内容集中在 dsa, stack, namaste, javascript, dev 等核心主题上。
📝 描述与内容策略
尚未提供频道描述。
凭借高频更新（最新数据采集于 31 十月, 2026），频道始终保持新鲜度与高覆盖。分析显示受众积极互动，使其成为 技术与应用 类别中的关键影响点。
78 714
订阅者
-2724 小时
-3217 天
-1 60030 天
帖子存档
78 714
long getMaxProfit(vector p, vector pr) {
int n = p.size();
long m=-1
for (int~j=1;j(pr[i]));
}
for (int~k=j+1;k p[j]) r = max(r, static_cast(pr[k]));
}
if(l>0~88~r>0) m = max(m, I + pr[j] + r);
}
return m;
}
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int
getMinlength(vector<int>a,int k)
{
int ans=1;
long long mul=1;
for(int i=0;i<a.size();i++){
if(mul*a[i]>k){
ans++;
mul=a[i];
}
else{
mul*=a[i];
}
}
return ans;
}
L&T
@allcoding1_official
Q) compressing array
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78 714
public class Solution {
public static int longestArraySegment(int array_length, List<Integer> arr) {
int maxLength = 1;
int currentLength = 1;
for (int i = 1; i < array_length; i++) {
if (arr.get(i) > arr.get(i - 1)) {
currentLength++;
} else {
currentLength = 1;
}
maxLength = Math.max(maxLength, currentLength);
}
currentLength = 1;
for (int i = 1; i < array_length; i++) {
if (arr.get(i) < arr.get(i - 1)) {
currentLength++;
} else {
currentLength = 1;
}
maxLength = Math.max(maxLength, currentLength);
}
return maxLength;
}
Ever increasing and ever decreasing - L&T
Java
Telegram:- @allcoding1_official
78 714
int solve(vector<int>& A) { int s = 0; for (const auto&n: A) { string sn = to_string(n); char md = *max_element(sn.begin().
sn.end());
s += md-'0';
}
return s;
}
C++
Telegram:- @allcoding1_official
L&t
Encryption by digits
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int solve(vector<int>& arr) { int narr.size(); if (n == 0) return 0;
int maxLen = 1;
int currLen = 1;
bool f = true;
for (int i = 1; i < n; ++i) { if ((arr[i] > arr[i-1] && f) || (arr[i] < arr[i-1] && !f)) { ++currLen; } else { maxLen = max(maxLen, currLen); currLen = 2;
f = arr[i] > arr[i-1]
}
}
maxLen = max(maxLen, currLen); return maxLen;
}
C++
Telegram:- @allcoding1_official
L&t
Q) Ever - increasing & ever decreasing array segments
78 714
+2int solve(vector& arr) { int n = arr.size(); if (n == 0) return 0;
int maxLen = 1; int currLen = 1; bool f = true;
for (int i = 1; i < n; ++i) { if ((arr[i] > arr[i-1] && f) II (arr[i] < arr[i-1] && !f)) { ++currLen; } else {
maxLen = max(maxLen, currLen); currLen = 2; f = arr[i] > arr[i-1]; }
maxLen = max(maxLen, currLen); return maxLen; }
C++
78 714
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78 714
Repost from allcoding1_official
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78 714
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78 714
Cognizant is hiring❤️
Apply link:
https://t.me/itjoblinks
Join our group for daily job posts
#paid promotion
78 714
Guys❤
👉 I am doing promotions (real Or fake) I don't know
👉I'm not forcing you. Your decision
👉I am not a responsible to you and money
👉 I need money that why I'm doing promotions try understand
78 714
Cognizant is hiring❤️
Apply link:
https://t.me/itjoblinks
Join our group for daily job posts
#paid promotion
