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不要被骗子欺骗!Telemetrio 会找到并标记这些频道 👉 如果想查看标记,请订阅

allcoding1_official

allcoding1_official

前往频道在 Telegram

📈 Telegram 频道 allcoding1_official 的分析概览

频道 allcoding1_official (@allcoding1_official) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 79 452 名订阅者,在 技术与应用 类别中位列第 1 590,并在 印度 地区排名第 3 856 位。

📊 受众指标与增长动态

自 невідомо 创建以来,项目保持高速增长,吸引了 79 452 名订阅者。

根据 17 十月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 -1 699,过去 24 小时变化为 -50,整体触达仍然可观。

  • 认证状态: 未认证
  • 互动率 (ER): 平均受众互动率为 0.85%。内容发布后 24 小时内通常能获得 0.65% 的反应,占订阅者总量。
  • 帖子覆盖: 每篇帖子平均可获得 678 次浏览,首日通常累积 517 次浏览。
  • 互动与反馈: 受众积极参与,单帖平均反应数为 0。
  • 主题关注点: 内容集中在 dsa, stack, namaste, javascript, dev 等核心主题上。

📝 描述与内容策略

尚未提供频道描述。

凭借高频更新(最新数据采集于 18 十月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 技术与应用 类别中的关键影响点。

79 452
订阅者
-5024 小时
-3417 天
-1 69930 天
帖子存档
Ashok IT AWS Devops Azure Devops 30 rupees Contact:- @meterials_available

photo content
+4

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Kill the enemy C++ Amazon 1.15 PM #include <vector> #include <algorithm> int solve(std::vector<int> &A, int B) { long long m1 = 0, m2 = 0; for (int val : A) { if (val > m1) { m2 = m1; m1 = val; } else if (val > m2) { m2 = val; } } long long b = B; long long s = m1 + m2; if (s == 0) { return b > 0 ? -1 : 0; } long long k = b / s; int ans = k * 2; long long rem = b % s; if (rem == 0) { return ans; } else if (rem <= m1) { return ans + 1; } else { return ans + 2; } }

M1: Encode sequential order T1: Regularization M16: Likelihood × Prior ML2: SGD can escape local minima due to its noisy updates ML3: Recursive Feature Elimination (RFE) ML4: Gini Index M4: It overfits the training data M7: 0 M2: Strong negative linear relationship S13: No real solution S17: Local minimum S23: Converges by Limit Comparison with 1/n² S30: Collect recent user data and evaluate model drift S31: Data leakage inflated model performance S39: 6/216 Amazon ML School MCQ Answers 1:15 PM

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S2: 4xy S7: 6 S12: 0 Q4: 1/2 S22: (2, 3) S28: Target/Mean Encoding S29: TimeSeriesSplit S38: 15 S43: 2/5 S59: Mode > Median > Mean ML - 2: The data has a Gaussian distribution ML - 7: Updating prior beliefs with observed data using Bayes' theorem ML - 12: The probability distribution over actions given states ML - 17: Internal covariate shift ML - 23: Boosting reduces bias, bagging reduces variance ML - 24: Binary Cross-Entropy S48: 30/84 S60: 150 S53: 2/3 S68: Prior × Likelihood

S2: 4xy S7: 6 S12: 0 Q4: 1/2 S22: (2, 3) S28: Target/Mean Encoding S29: TimeSeriesSplit S38: 15 S43: 2/5 S59: Mode > Median > Mean ML - 2: The data has a Gaussian distribution ML - 7: Updating prior beliefs with observed data using Bayes' theorem ML - 12: The probability distribution over actions given states ML - 17: Internal covariate shift ML - 23: Boosting reduces bias, bagging reduces variance ML - 24: Binary Cross-Entropy S48: 30/84 S60: 150 S53: 2/3 S68: Prior × Likelihood Amazon ML School 100% Correct MCQ Answers 10:30 AM

Mode>median>mean
Mode>median>mean

C
C

Prior x Likelihood
Prior x Likelihood

150
150

30/84
30/84

4
4

4xy
4xy

1/2
1/2

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Python Star removal
Python Star removal

#include <bits/stdc++.h> using namespace std; class Solution { public: string clearStars(string A) { string s = A; priority_queue<char, vector<char>, greater<char>> pq; vector<vector<int>> ind(26); unordered_set<int> rs; for (int i = 0; i < s.size(); ++i) { if (s[i] == '*') { rs.insert(i); char ch = pq.top(); pq.pop(); pq.push(ch); rs.insert(ind[ch - 'a'].back()); ind[ch - 'a'].pop_back(); if (ind[ch - 'a'].empty()) pq.pop(); continue; } if (ind[s[i] - 'a'].empty()) pq.push(s[i]); ind[s[i] - 'a'].push_back(i); } string res = ""; for (int i = 0; i < s.size(); ++i) { if (!rs.count(i)) { res += s[i]; } } return res; } }; Clear stars Start removal

#include <bits/stdc++.h> using namespace std; class Solution { public: string clearStars(string A) { string s = A; priority_queue<char, vector<char>, greater<char>> pq; vector<vector<int>> ind(26); unordered_set<int> rs; for (int i = 0; i < s.size(); ++i) { if (s[i] == '*') { rs.insert(i); char ch = pq.top(); pq.pop(); // geekynerd pq.push(ch); rs.insert(ind[ch - 'a'].back()); // geekynerd ind[ch - 'a'].pop_back(); // geekynerd if (ind[ch - 'a'].empty()) pq.pop(); // geekynerd continue; } if (ind[s[i] - 'a'].empty()) // geekynerd pq.push(s[i]); ind[s[i] - 'a'].push_back(i); // geekynerd } string res = ""; for (int i = 0; i < s.size(); ++i) { if (!rs.count(i)) { res += s[i]; // geekynerd } } return res; } }; Clear stars Start removal C++