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Code With Virus

Code With Virus

前往频道在 Telegram

Coding channel @codewithvirus. 👈 Main group @avirustech 👈 Accenture @Accenturavirustech 👈 IBM. @IBMavirustech 👈 Tech Mahindra. @TechMavirustech 👈

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📈 Telegram 频道 Code With Virus 的分析概览

频道 Code With Virus (@codewithvirus) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 10 559 名订阅者,在 技术与应用 类别中位列第 10 501,并在 印度 地区排名第 43 593 位。

📊 受众指标与增长动态

自 невідомо 创建以来,项目保持高速增长,吸引了 10 559 名订阅者。

根据 04 十二月, 2025 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 -87,过去 24 小时变化为 0,整体触达仍然可观。

  • 认证状态: 未认证
  • 互动率 (ER): 平均受众互动率为 0%。内容发布后 24 小时内通常能获得 N/A% 的反应,占订阅者总量。
  • 帖子覆盖: 每篇帖子平均可获得 0 次浏览,首日通常累积 0 次浏览。
  • 互动与反馈: 受众积极参与,单帖平均反应数为 0。

📝 描述与内容策略

作者将该频道定位为表达主观观点的平台:
“Coding channel @codewithvirus. 👈 Main group @avirustech 👈 Accenture @Accenturavirustech 👈 IBM. @IBMavirustech 👈 Tech Mahindra. @TechMavirustech 👈”

凭借高频更新(最新数据采集于 05 十二月, 2025),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 技术与应用 类别中的关键影响点。

10 559
订阅者
无数据24 小时
-227 天
-8730 天
帖子存档
Start your IBM exam Guys 🔥

Who have tomorrow IBM coding ?? If you interested to i will write your IBM coding exam then message me on my Instagram 🔥

Coding channel @codewithvirus. 👈 Main group @avirustech 🔴 👈 Accenture. @Accenturavirustech👈 IBM. @IBMavirustech 👈 Tech Mahindra. @TechMavirustech 👈 Infosys. @Infosyavirustech 👈 TCS. @TCSavirustech 👈 Amazon. @Amazonavirustech 👈

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HackOn with Amazon Coding Challenge

You have PRA 1 on 31 May ?? 🤔

Coding channel @codewithvirus. 👈 Main group @avirustech 🔴 👈 Accenture. @Accenturavirustech👈 IBM. @IBMavirustech 👈 Tech Mahindra. @TechMavirustech 👈 Infosys. @Infosyavirustech 👈 TCS. @TCSavirustech 👈 Amazon. @Amazonavirustech 👈

#include <bits/stdc++.h> using namespace std; /* * Complete the 'decodeIP' function below. * * The function accepts STRING hexaIP as parameter. */ int codewithvirus(string n) { return stoi(n,0,16); } void decodeIP(string hexaIP) { string s="",s1="",s2="",s3="",s4=""; s+=hexaIP[0]; s+=hexaIP[1]; s1+=hexaIP[2]; s1+=hexaIP[3]; s2+=hexaIP[4]; s2+=hexaIP[5]; s3+=hexaIP[6]; s3+=hexaIP[7]; s4+=hexaIP[8]; s4+=hexaIP[9]; int n=codewithvirus(s); if(hexaIP.size()<=7) cout<<"Invalid input"; else { if(n>1 && n<=127) { cout<<codewithvirus(s)<<"."<<codewithvirus(s1)<<"."<<codewithvirus(s2)<<"."<<codewithvirus(s3)<<endl; cout<<"A"; } else if(n>=128 && n<=191) { cout<<codewithvirus(s)<<"."<<codewithvirus(s1)<<"."<<codewithvirus(s2)<<"."<<codewithvirus(s3)<<endl; cout<<"B"; } else if(n>=192 && n<=223) { cout<<codewithvirus(s)<<"."<<codewithvirus(s1)<<"."<<codewithvirus(s2)<<"."<<codewithvirus(s3)<<endl; cout<<"C"; } else if(n>=224 && n<=239) { cout<<codewithvirus(s)<<"."<<codewithvirus(s1)<<"."<<codewithvirus(s2)<<"."<<codewithvirus(s3)<<endl; cout<<"D"; } else if(n>=240 && n<=255) { cout<<codewithvirus(s)<<"."<<codewithvirus(s1)<<"."<<codewithvirus(s2)<<"."<<codewithvirus(s3)<<endl; cout<<"D"; } } } int main() { string hexaIP; getline(cin, hexaIP); decodeIP(hexaIP); return 0; }

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Guys try to send me proper question and make sure it is visible for me If you send me fast then i will post solution fast 😃

Guys in IBM coding exam if you passed at least 3 test case then you are eligible for next round 🔥 So try to paas at least 3 test case okay If you don't know how to pass then i will post solution And this solution will be passed at least 3 test case If you get any error then just think you are doing something Worong anywhere and check your code again and try to sloved

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I will post all solution here

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