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Code With Virus

Code With Virus

前往频道在 Telegram

Coding channel @codewithvirus. 👈 Main group @avirustech 👈 Accenture @Accenturavirustech 👈 IBM. @IBMavirustech 👈 Tech Mahindra. @TechMavirustech 👈

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📈 Telegram 频道 Code With Virus 的分析概览

频道 Code With Virus (@codewithvirus) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 10 559 名订阅者,在 技术与应用 类别中位列第 10 501,并在 印度 地区排名第 43 593 位。

📊 受众指标与增长动态

自 невідомо 创建以来,项目保持高速增长,吸引了 10 559 名订阅者。

根据 04 十二月, 2025 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 -87,过去 24 小时变化为 0,整体触达仍然可观。

  • 认证状态: 未认证
  • 互动率 (ER): 平均受众互动率为 0%。内容发布后 24 小时内通常能获得 N/A% 的反应,占订阅者总量。
  • 帖子覆盖: 每篇帖子平均可获得 0 次浏览,首日通常累积 0 次浏览。
  • 互动与反馈: 受众积极参与,单帖平均反应数为 0。

📝 描述与内容策略

作者将该频道定位为表达主观观点的平台:
“Coding channel @codewithvirus. 👈 Main group @avirustech 👈 Accenture @Accenturavirustech 👈 IBM. @IBMavirustech 👈 Tech Mahindra. @TechMavirustech 👈”

凭借高频更新(最新数据采集于 05 十二月, 2025),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 技术与应用 类别中的关键影响点。

10 559
订阅者
无数据24 小时
-227 天
-8730 天
帖子存档
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Guys in IRA exam in don't expect solution When I'm sharing solution then everyone one get plagiarism and Which candidate I'm writing he Also get plagiarism So please I will share only logic If you get anything logical error then I will help you 👍

Coding channel @codewithvirus. 👈 Main group @avirustech 🔴 👈 Accenture. @Accenturavirustech👈 IBM. @IBMavirustech 👈 Tech Mahindra. @TechMavirustech 👈 Infosys. @Infosyavirustech 👈 TCS. @TCSavirustech 👈.

Coding channel @codewithvirus. 👈 Main group @avirustech 🔴 👈 Accenture. @Accenturavirustech👈 IBM. @IBMavirustech 👈 Tech Mahindra. @TechMavirustech 👈 Infosys. @Infosyavirustech 👈 TCS. @TCSavirustech 👈.

#include <iostream> using namespace std; struct student { string name; int English; int Histroy; int computers; int Math; int scinece; int Econmaincs; }; struct result { string subject; int marks; }; int main() { cout << "Enter a total Student number" << endl; int n; cin >> n; struct student Sname[n]; for (int i = 0; i < n; i++) { cout << "Enter a Student name" << endl; cin >> Sname[i].name; cout << "Enter " << Sname[i].name << "all subject marks" << endl; cin >> Sname[i].English; cin >> Sname[i].Histroy; cin >> Sname[i].computers; cin >> Sname[i].Math; cin >> Sname[i].scinece; cin >> Sname[i].Econmaincs; } int TEnglish; int THistroy; int Tcomputers; int TMath; int Tscinece; int TEconmaincs; for (int i = 0; i < n; i++) { TEnglish += Sname[i].English; THistroy += Sname[i].Histroy; Tcomputers += Sname[i].computers; TMath += Sname[i].Math; Tscinece += Sname[i].scinece; TEconmaincs += Sname[i].Econmaincs; } struct result codewithvirus[6]; codewithvirus[0].subject = "English"; codewithvirus[0].marks = TEnglish / n; codewithvirus[0].subject = "Histroy"; codewithvirus[0].marks = THistroy / n; codewithvirus[0].subject = "Computers"; codewithvirus[0].marks = Tcomputers / n; codewithvirus[0].subject = "Math"; codewithvirus[0].marks = TMath / n; codewithvirus[0].subject = "Scinece"; codewithvirus[0].marks = Tscinece / n; codewithvirus[0].subject = "Econmaincs"; codewithvirus[0].marks = TEconmaincs / n; for (int i = 0; i < 6; i++) { for (int j = i + 1; j < 6; j++) { int tmp = 0; string s = 0; if (codewithvirus[i].marks > codewithvirus[j].marks) { tmp = codewithvirus[i].marks; s = codewithvirus[i].subject; codewithvirus[i].marks = codewithvirus[j].marks; codewithvirus[i].subject = codewithvirus[j].subject; codewithvirus[j].marks = tmp; codewithvirus[j].subject = s; } } cout << "Student difficult subject is a: " << codewithvirus[0].subject; return 0; }

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Coding channel @codewithvirus. 👈 Main group @avirustech 🔴 👈 Accenture. @Accenturavirustech👈 IBM. @IBMavirustech 👈 Tech Mahindra. @TechMavirustech 👈 Infosys. @Infosyavirustech 👈 TCS. @TCSavirustech 👈.

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Guys just print only 4 In 2nd Code to much logic is going on

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Send me 2nd question guys

2nd question ?? 🤔

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