ch
Feedback

不要被骗子欺骗!Telemetrio 会找到并标记这些频道 👉 如果想查看标记,请订阅

PythonCoder Official

PythonCoder Official

前往频道在 Telegram

• 𝗕𝗲𝘀𝘁 𝗽𝗹𝗮𝗰𝗲 𝗳𝗼𝗿 𝗣𝘆𝘁𝗵𝗼𝗻 𝗖𝗼𝗱𝗲𝗿𝘀 😀 • 𝗙𝗿𝗲𝗲 𝗣𝗿𝗼𝗴𝗿𝗮𝗺𝗺𝗶𝗻𝗴 𝗖𝗼𝘂𝗿𝘀𝗲𝘀 & 𝗧𝘂𝘁𝗼𝗿𝗶𝗮𝗹𝘀📒 • 𝗗𝗮𝘁𝗮 𝗦𝗰𝗶𝗲𝗻𝗰𝗲📊 | 𝗠𝗮𝗰𝗵𝗶𝗻𝗲 𝗟𝗲𝗮𝗿𝗻𝗶𝗻𝗴 | 𝗔𝗜 🤖 • 𝗗𝗮𝗶𝗹𝘆 𝗗𝗼𝘇𝗲 𝗼𝗳 𝗣𝗿𝗼𝗷𝗲𝗰𝘁𝘀 🧠

显示更多

📈 Telegram 频道 PythonCoder Official 的分析概览

频道 PythonCoder Official (@pythoncoder92) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 71 862 名订阅者,在 技术与应用 类别中位列第 1 792,并在 印度 地区排名第 4 397 位。

📊 受众指标与增长动态

自 невідомо 创建以来,项目保持高速增长,吸引了 71 862 名订阅者。

根据 27 十月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 -1 354,过去 24 小时变化为 -23,整体触达仍然可观。

  • 认证状态: 未认证
  • 互动率 (ER): 平均受众互动率为 7.11%。内容发布后 24 小时内通常能获得 1.45% 的反应,占订阅者总量。
  • 帖子覆盖: 每篇帖子平均可获得 0 次浏览,首日通常累积 1 041 次浏览。
  • 互动与反馈: 受众积极参与,单帖平均反应数为 0。
  • 主题关注点: 内容集中在 programming, certification, stack, s_curve, t.left(90 等核心主题上。

📝 描述与内容策略

作者将该频道定位为表达主观观点的平台:
“• 𝗕𝗲𝘀𝘁 𝗽𝗹𝗮𝗰𝗲 𝗳𝗼𝗿 𝗣𝘆𝘁𝗵𝗼𝗻 𝗖𝗼𝗱𝗲𝗿𝘀 😀 • 𝗙𝗿𝗲𝗲 𝗣𝗿𝗼𝗴𝗿𝗮𝗺𝗺𝗶𝗻𝗴 𝗖𝗼𝘂𝗿𝘀𝗲𝘀 & 𝗧𝘂𝘁𝗼𝗿𝗶𝗮𝗹𝘀📒 • 𝗗𝗮𝘁𝗮 𝗦𝗰𝗶𝗲𝗻𝗰𝗲📊 | 𝗠𝗮𝗰𝗵𝗶𝗻𝗲 𝗟𝗲𝗮𝗿𝗻𝗶𝗻𝗴 | 𝗔𝗜 🤖 • 𝗗𝗮𝗶𝗹𝘆 𝗗𝗼𝘇𝗲 𝗼𝗳 𝗣𝗿𝗼𝗷𝗲𝗰𝘁𝘀 🧠”

凭借高频更新(最新数据采集于 28 十月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 技术与应用 类别中的关键影响点。

71 862
订阅者
-2324 小时
-3377 天
-1 35430 天
帖子存档
face-recognition-python-code.zip1.92 KB

⚠️ Already 2000+ People have Joined ⚠️ Learn Programming at Free of cost & Make Money 🤑💰 also 💯 Join Free Course now ✅ Cli
⚠️ Already 2000+ People have Joined ⚠️ Learn Programming at Free of cost & Make Money 🤑💰 also 💯 Join Free Course now ✅ Click here, SignUp Free              👇👇👇 https://bit.ly/python-ai-Free ⚠️ Last 500 Seats Left ⚠️

Have you Joined Free Programming 💻 Course with Money 💰 Making Opportunity 🤔🤔
Anonymous voting

💥💥 ATTENTION  GUYS 💥💥 Learn Programming at Free of cost 💻 & Earn Money also 💸🚀 Join Free Course now ✅ 👉 Get Free --------->>> • Free Programming Courses with Projects Codes & Notes 📑 • Learn Python, Data Science , ChatGPT, AI , Web 3 Projects at Free of cost 🆓 Earn Money 💸 also while Learning 💯 Certificate to everyone ✅ Click here, SignUp Free               👇 👇👇 https://bit.ly/learn-python-ai ⚠️ Free for First 1000 People ⚠️

Opportunity to learn Programming at Free of cost with Earning Money Opportunity ✅
Anonymous voting

Do you want to Make Money 💰🤑 🤔
Anonymous voting

Python Handwritten Notes 📝

70 Toughest interivew questions.pdf4.73 KB

⭐ 🔥 Golden Opportunity  🔥⭐ Want to learn Frontend development, which is high in demand with Good package -  Join now Free Masterclass 🚀 - • Learn Html, CSS, JavaScript ✅ • Web Development Course Click here, Register Free           👇👇👇👇 https://forms.gle/MKYJ2W9adhS53cXg8 ⚠️ Don't miss this Opportunity ⚠️

Want to learn Frontend Development ( Html, CSS, JavaScript ) 🤔
Anonymous voting

✅ WhatsApp Bot Project ( Make fun of Friend using Python) Complete Tutorial Video 👇 https://youtu.be/IawipNUB4pg

Coding Games In Python .pdf30.48 MB

Python notes (1) (1).pdf6.29 KB

⚠️ Last 200 Seats Left ⚠️ Don't miss this Opportunity 🙏

🚀🔥 Last 500 Seats Left 🚀🔥 Learn Programming at Free of cost & also you can Make Money 💰 💻 Get Access of All Courses, No
🚀🔥 Last 500 Seats Left 🚀🔥 Learn Programming at Free of cost & also you can Make Money 💰 💻 Get Access of All Courses, Notes & Projects Codes at Free of cost 💯 Start learning & Earning today 🚀 Click here, SignUp Free         👇👇👇👇 https://go.stackup.dev/rztHw ...................................................................

IMG_20240219_122137_922.jpg1.58 KB

💥 🚀 Breaking News 💥🚀 Learn Programming at Free of cost and Earn Money 💯 Join Free Course Now 🎁 ✅ You'll get : • Programming Courses with Projects and Notes • Learn Python, Data Science , ChatGPT, AI , Web 3 Projects • Learn Coding and Earn Money by solving assignments & quizzes 💰 Certification to everyone ✅ Click here, SignUp Free 👇 https://go.stackup.dev/rztHw ⚠️ Only for first 500 People ⚠️

Want to learn Coding 💻 at Free of cost & Earn Money also💰 🤔
Anonymous voting

--- Python Logo Source Code --- import turtle t = turtle.Turtle() s = turtle.Screen() s.bgcolor("black") t.speed(10) t.pensize(2) t.pencolor("white") def s_curve(): for i in range(90): t.left(1) t.forward(1) def r_curve(): for i in range(90): t.right(1) t.forward(1) def l_curve(): s_curve() t.forward(80) s_curve() def l_curve1(): s_curve() t.forward(90) s_curve() def half(): t.forward(50) s_curve() t.forward(90) l_curve() t.forward(40) t.left(90) t.forward(80) t.right(90) t.forward(10) t.right(90) t.forward(120) #on test l_curve1() t.forward(30) t.left(90) t.forward(50) r_curve() t.forward(40) t.end_fill() def get_pos(): t.penup() t.forward(20) t.right(90) t.forward(10) t.right(90) t.pendown() def eye(): t.penup() t.right(90) t.forward(160) t.left(90) t.forward(70) t.pencolor("black") t.dot(35) def sec_dot(): t.left(90) t.penup() t.forward(310) t.left(90) t.forward(120) t.pendown() t.dot(35) t.fillcolor("#306998") t.begin_fill() half() t.end_fill() get_pos() t.fillcolor("#FFD43B") t.begin_fill() half() t.end_fill() eye() sec_dot() def pause(): t.speed(2) for i in range(100): t.left(90) pause()

- Location of Mobile Number Code - import phonenumbers from phonenumbers import timezone from phonenumbers import geocoder from phonenumbers import carrier number = input("Enter the phone number with country code : ") # Parsing String to the Phone number phoneNumber = phonenumbers.parse(number) # printing the timezone using the timezone module timeZone = timezone.time_zones_for_number(phoneNumber) print("timezone : "+str(timeZone)) # printing the geolocation of the given number using the geocoder module geolocation = geocoder.description_for_number(phoneNumber,"en") print("location : "+geolocation) # printing the service provider name using the carrier module service = carrier.name_for_number(phoneNumber,"en") print("service provider : "+service)