LeetCode, GeeksForGeeks Problem of the day solution
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Complete daily challenges from LeetCode, GeeksForGeeks and redeem their rewards Channel link : https://t.me/leetcode_gfg_potd
إظهار المزيد1 250
المشتركون
+224 ساعات
+147 أيام
+2930 أيام
أرشيف المشاركات
class Solution {
public:
int minimumOneBitOperations(int n) {
vector bits(32,0);
for(int i = 31; i >= 0; i--){
if(n & (1 << i)) bits[i] = 1;
}
int ret = 0;
if(bits[31]) ret += (1 << 31);
for(int i = 30; i >= 0; i--){
bits[i] ^= bits[i+1];
if(bits[i]) ret += (1 << i);
}
return ret;
}
};
class Solution{
public:
int minimumStep(int n){
int ans = 0;
while(n != 1) {
n = (n%3) ? n-1 : n/3;
ans++;
}
return ans;
}
};
class Solution {
public:
int hammingWeight(uint32_t n) {
int cnt=0;
while(n>0){
if(n%2==1){
cnt++;
}
n=n>>1;
}
return cnt;
}
};
class Solution {
public:
int isEulerCircuit(int V, vectoradj[]){
int cnt=0;
for(int i=0;i
class Solution {
public:
int numberOfWays(string corridor) {
int ans=1,module=1000000007;
vector seatIndex;
for(int index=0;index
class Solution {
public:
int sumOfDependencies(vector adj[], int V) {
int res = 0;
for(int i = 0; i < V; i++)
res += adj[i].size();
return res;
}
};
class Solution {
public:
int mod = 1e9+7;
vector> dp;
int call(int n , map>& m , int pos){
if(n==0)return 1;
if(dp[pos][n] != -1)return dp[pos][n];
int ans = 0;
for(int j =0;j> m;
m[1] = {6,8};
m[2] = {7,9};
m[3] = {4,8};
m[4] = {3,9,0};
m[5] = {};
m[6] = {1,7,0};
m[7] = {2,6};
m[8] = {1,3};
m[9] = {2,4};
m[0] = {4,6};
dp = vector>(11 , vector(n+1,-1));
int ans = 0;
for(int i=0;i<=9;i++){
ans = (ans%mod + call(n-1,m,i)%mod)%mod;
}
return ans;
}
};
class Solution
{
public:
//Function to detect cycle using DSU in an undirected graph.
vector parent;
vector rank;
int find(int x)
{
if(parent[x] == x)
{
return x;
}
parent[x] = find(parent[x]);
return parent[x];
}
void union1(int x, int y)
{
int x_rep = find(x);
int y_rep = find(y);
if(x_rep == y_rep)
{
return;
}
if(rank[x_rep] < rank[y_rep])
{
parent[x_rep] = y_rep;
}
else if(rank[x_rep] > rank[y_rep])
{
parent[y_rep] = x_rep;
}
else
{
parent[y_rep] = x_rep;
rank[x_rep]++;
}
}
int detectCycle(int V, vectoradj[])
{
parent.resize(V);
rank.resize(V);
for(int i = 0; i < V; i++)
{
parent[i] = i;
rank[i] = 0;
}
set> s;
for(int v = 0; v < V; v++)
{
for(auto u : adj[v])
{
if(s.find({u, v}) != s.end() or s.find({v, u}) != s.end())
{
continue;
}
s.insert({u, v});
int u_rep = find(u);
int v_rep = find(v);
if(u_rep == v_rep)
{
return true;
}
union1(u, v);
}
}
return false;
}
};
class Solution
{
public:
int largestSubmatrix(vector>& matrix)
{
int m = matrix.size(), n = matrix[0].size();
int ans = 0;
for(int j = 0; j < n; j++)
for(int i = 1; i < m; i++)
if(matrix[i][j] == 1)
matrix[i][j] += matrix[i-1][j];
for(int i = 0; i < m; i++)
{
sort(matrix[i].begin(), matrix[i].end());
reverse(matrix[i].begin(), matrix[i].end());
for(int j = 0; j < n; j++)
ans = max(ans, matrix[i][j]*(j+1));
}
return ans;
}
};
class Solution{
public:
vector ans;
vector pattern(int N){
if(N<=0){
ans.push_back(N);
return ans;
}
ans.push_back(N);
pattern(N-5);
ans.push_back(N);
return ans;
}
};
