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LeetCode, GeeksForGeeks Problem of the day solution

LeetCode, GeeksForGeeks Problem of the day solution

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Complete daily challenges from LeetCode, GeeksForGeeks and redeem their rewards Channel link : https://t.me/leetcode_gfg_potd

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أرشيف المشاركات
GFG | Problem of the day :

class Solution { public: vector getSumAbsoluteDifferences(vector& nums) { int total_sum=0; int n=nums.size(); for(int i=0; i ans; int curr_sum=0; for(int i=0; i

LeetCode | Daily challenge :

class Solution{ public: void shuffleArray(int arr[],int n) { int maxi=1e5; int i=0; int j=n/2; while(j<n) { arr[i]=(arr[j]*maxi)+arr[i]; i++; j++; } i=(n/2)-1; j=n-1; while(i>=0) { arr[j]=arr[i]/maxi; arr[j-1]=arr[i]%maxi; j-=2; i--; } } };

GFG | Problem of the day :

class Solution { int findSecondMaxi(int i, int j, int k, int maxi){ if(maxi == i && k < j) return j; else if(maxi == j && i < k) return k; else return i; } public: int maxCoins(vector& piles) { sort(piles.begin(),piles.end()); int i = 0; int j = piles.size()-1; int k = piles.size()-2; int res = 0; while(i < j && i < k && k < j){ int maxi = max(piles[i], max(piles[j],piles[k])); int secondMaxi = findSecondMaxi(piles[i],piles[j], piles[k], maxi); res += secondMaxi; i++; j -= 2; k -= 2; } return res; } };

LeetCode | Daily challenge :

class Solution{ public: vector nthRowOfPascalTriangle(int n) { int mod = 1000000007; vector> pT(n); for(int i=0;i

GFG | Problem of the day :

class Solution { public: bool isvalid(int start,int end,vectornums){ vectortemp; for(int i=start;i<=end;i++){ temp.push_back(nums[i]); } sort(temp.begin(),temp.end()); int Size=temp.size(); int curr=temp[1]-temp[0]; for(int i=1;i checkArithmeticSubarrays(vector& nums, vector& l, vector& r) { int lSize=l.size(); int rSize=r.size(); int i=0; // l int j=0; // r vectorans; while(i

LeetCode | Daily challenge :

class Solution{ public: int height(Node* N){ if(N==NULL){ return 0; } return N->height; } int getBalance(Node* N){ if(N==NULL){ return 0; } return height(N->left)-height(N->right); } Node* leftRotation(Node* x){ Node* y = x->right; Node* T2 = y->left; y->left = x; x->right = T2; x->height = 1+max(height(x->left),height(x->right)); y->height = 1+max(height(y->left),height(y->right)); return y; } Node* rightRotation(Node* x){ Node* y = x->left; Node* T2 = y->right; y->right = x; x->left = T2; x->height = 1+max(height(x->left),height(x->right)); y->height = 1+max(height(y->left),height(y->right)); return y; } /*You are required to complete this method */ Node* insertToAVL(Node* node, int data) { if(node==NULL){ return new Node(data); }else if(data > node->data){ node->right = insertToAVL(node->right,data); }else if(data < node->data){ node->left = insertToAVL(node->left,data); }else{ return node; } node->height = 1+max(height(node->left),height(node->right)); int balance = getBalance(node); if(balance>1 && data < node->left->data){ return rightRotation(node); } if(balance<-1 && data>node->right->data){ return leftRotation(node); } if(balance>1 && data>node->left->data){ node->left = leftRotation(node->left); return rightRotation(node); } if(balance<-1 && dataright->data){ node->right = rightRotation(node->right); return leftRotation(node); } return node; } };

GFG | Problem of the day :

class Solution { public: vector findDiagonalOrder(vector>& nums) { vector> v; for(int i=0;i a, pair b)->bool{ if(a.first != b.first)return a.first < b.first; return a.second < b.second; }; sort(v.begin(),v.end(),cmp); vector ans; for(auto i: v){ ans.push_back(nums[i.first-i.second][i.second]); } return ans; } };

LeetCode | Daily challenge :

class Solution{ public: bool solve(struct Node* root, struct Node* root1) { if(root == nullptr && root1 == nullptr ) { return true; } if(root == nullptr or root1 == nullptr or root->data != root1->data) { return false; } bool left = solve(root->left, root1->right); bool right = solve(root->right, root1->left); return left && right; } // return true/false denoting whether the tree is Symmetric or not bool isSymmetric(struct Node* root) {if(root == nullptr) { return true; } // Code here return solve(root->left , root->right); } };

GFG | Problem of the day :

class Solution { public: int rev(int n){ int ans = 0; while(n){ ans = ans * 10 + (n%10); n = n/10; } return ans; } int countNicePairs(vector& nums) { unordered_map mp; int mod = 1e9+7; int count = 0; for(int i=0;i

LeetCode | Daily challenge :

class Solution { public: //Function to check if two trees are identical. bool isIdentical(Node *r1, Node *r2) { if( r1== NULL && r2 == NULL){ return true; } else if( r1== NULL && r2 != NULL){ return false; } else if( r1 != NULL && r2 == NULL){ return false; } bool left = isIdentical(r1->left, r2->left); bool right = isIdentical(r1->right, r2->right); bool val = r1->data == r2->data; if( left && right && val){ return true; } else{ return false; } } };