SCZ Math&Add Math

Can anyone show the solution of question A

(a)coordinate of Q(h,-5) h=(-2+8)/2=3 coordinate of Q(3,-5) (b)a(x+2)(x-8)=a(x-3)²-5 ax²-6ax-16a=ax²-6ax+9a-5 -16a=9a-5 a=1/5

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It's a unit circle, so x² + y² = 1 x² + (-0.53)² = 1 x = ... Choose the positive value

Can throw the modulus , I didnt write it as vector

Does anyone know what is objective function

A = tetha Use cos A = 1 - 2sin²(A/2)

thanks

Pls correct me if I wrong ☺️

R is origin

Pls help (a)

a=3

k=6x2

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