Data Analyst Interview Resources
Join our telegram channel to learn how data analysis can reveal fascinating patterns, trends, and stories hidden within the numbers! 📊 For ads & suggestions: @love_data
Ko'proq ko'rsatish📈 Telegram kanali Data Analyst Interview Resources analitikasi
Data Analyst Interview Resources (@dataanalystinterview) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 52 353 obunachidan iborat bo'lib, Taʼlim toifasida 3 331-o'rinni va Hindiston mintaqasida 7 149-o'rinni egallagan.
📊 Auditoriya ko‘rsatkichlari va dinamika
невідомо sanasidan buyon loyiha tez o‘sib, 52 353 obunachiga ega bo‘ldi.
15 Iyun, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni 304 ga, so‘nggi 24 soatda esa 0 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.
- Tasdiqlash holati: Tasdiqlanmagan
- Jalb etish (ER): Auditoriya o‘rtacha 2.24% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 0.96% ini tashkil etuvchi reaksiyalarni to‘playdi.
- Post qamrovi: Har bir post o‘rtacha 1 172 marta ko‘riladi; birinchi sutkada odatda 505 ta ko‘rish yig‘iladi.
- Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 3 ta reaksiya keladi.
- Tematik yo‘nalishlar: Kontent sql, row, |--, dataset, visualization kabi asosiy mavzularga jamlangan.
📝 Tavsif va kontent siyosati
Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida ta’riflaydi:
“Join our telegram channel to learn how data analysis can reveal fascinating patterns, trends, and stories hidden within the numbers! 📊
For ads & suggestions: @love_data”
Yuqori yangilanish chastotasi (oxirgi ma’lumot 16 Iyun, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.
DATA100
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SELECT c.CustomerID, c. Name, AVG(o.Amount) AS AveragePurchase FROM Customers c JOIN Orders o ON c.CustomerID = o.CustomerID GROUP BY c.CustomerID, c. Name;📍2. Write a query to find the employee with the minimum salary in each department from a table Employees with columns EmployeeID, Name, DepartmentID, and Salary.
SELECT e1.DepartmentID, e1.EmployeeID, e1 .Name, e1.Salary FROM Employees e1 WHERE Salary = (SELECT MIN(Salary) FROM Employees e2 WHERE e2.DepartmentID = e1.DepartmentID);📍3. Write a SQL query to find all products that have never been sold. Assume you have a table Products (ProductID, ProductName) and a table Sales (SaleID, ProductID, Quantity).
SELECT p.ProductID, p.ProductName FROM Products p LEFT JOIN Sales s ON p.ProductID = s.ProductID WHERE s.ProductID IS NULL;📍4. Given a table Orders with columns OrderID, CustomerID, OrderDate, and a table OrderItems with columns OrderID, ItemID, Quantity, write a query to find the customer with the highest total order quantity.
SELECT o.CustomerID, SUM(oi.Quantity) AS TotalQuantity FROM Orders o JOIN OrderItems oi ON o.OrderID = oi.OrderID GROUP BY o.CustomerID ORDER BY TotalQuantity DESC LIMIT 1;📍5. Write a SQL query to find the earliest order date for each customer from a table Orders (OrderID, CustomerID, OrderDate).
SELECT CustomerID, MIN(OrderDate) AS EarliestOrderDate FROM Orders GROUP BY CustomerID;
DATA100
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