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Pythonlearnerr

Pythonlearnerr

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πŸ“ˆ Telegram kanali Pythonlearnerr analitikasi

Pythonlearnerr (@pythonlearnerr) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 106 243 obunachidan iborat bo'lib, TaΚΌlim toifasida 1 297-o'rinni va Hindiston mintaqasida 2 385-o'rinni egallagan.

πŸ“Š Auditoriya koβ€˜rsatkichlari va dinamika

Π½Π΅Π²Ρ–Π΄ΠΎΠΌΠΎ sanasidan buyon loyiha tez oβ€˜sib, 106 243 obunachiga ega boβ€˜ldi.

26 Oktabr, 2026 dagi oxirgi ma’lumotlarga koβ€˜ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -1 906 ga, soβ€˜nggi 24 soatda esa -63 ga oβ€˜zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya oβ€˜rtacha 9.25% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 1.72% ini tashkil etuvchi reaksiyalarni toβ€˜playdi.
  • Post qamrovi: Har bir post oβ€˜rtacha 0 marta koβ€˜riladi; birinchi sutkada odatda 1 828 ta koβ€˜rish yigβ€˜iladi.
  • Reaksiyalar va oβ€˜zaro ta’sir: Auditoriya faol: har bir postga oβ€˜rtacha 0 ta reaksiya keladi.
  • Tematik yoβ€˜nalishlar: Kontent certification, stack, physicswallah, internship, sql kabi asosiy mavzularga jamlangan.

πŸ“ Tavsif va kontent siyosati

Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida ta’riflaydi:
β€œLearn Python Programming at Free of cost With Projects β˜‘οΈβ€

Yuqori yangilanish chastotasi (oxirgi ma’lumot 27 Oktabr, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli boβ€˜lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni TaΚΌlim toifasidagi muhim ta’sir nuqtasiga aylantirishini koβ€˜rsatadi.

106 243
Obunachilar
-6324 soatlar
-5087 kun
-1 90630 kun
Postlar arxiv
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--- Do you like me Source Code --- import tkinter as tk import random def show_popup():     popup = tk.Toplevel(root)     popup.title("Popup")     label = tk.Label(popup, text="Thanks for Accepting")     label.pack(padx=20, pady=20) def move_button(event):     x = random.randint(0, 350)     y = random.randint(0, 350)     no_button.place(x=x, y=y) root = tk.Tk() root.title("instagram: @pythonlearnerr") root.geometry("400x400") question_label = tk.Label(root, text="Do you like me?") question_label.pack(pady=20) yes_button = tk.Button(root, text="Yes", command=show_popup) yes_button.pack() no_button = tk.Button(root, text="No") no_button.pack() no_button.bind("<Enter>", move_button) root.mainloop()

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Which Programming language notes do you want ?
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Legend Form Complete Source Code πŸ‘‡ ----------------------------------------------------- <html> <head> <style> .outer{  margin:auto; height:300px; width:400px; border:2px solid black; position:relative } p{ margin-left:80px; } .in{ margin-left:80px; padding:10px } #bt{ margin-top:20px; position:absolute; left:150px; } #bt:hover{ background:green; font-size:13px; cursor:pointer; color:white; } </style> <script> function fa(){ if(a.value=="" || b.value==""){ f() document.getElementById("a").style.border="3px solid red" document.getElementById("b").style.border="3px solid red" bt.value="Pahila data tak" } else{ document.getElementById("a").style.border="3px solid green" document.getElementById("b").style.border="3px solid green" bt.value="Ha thik ahe ata" bt.style.left="120px"; } } flag=1 function f(){ if(flag==1){ bt.style.left="210px" flag=2 } else if(flag==2){ bt.style.left="80px" flag=1 } } </script> </head> <body> <div class="outer"> <h1 style="text-align:center">Legend form</h1> <p>Enter Id</p> <input class="in" type="text" placeholder="Enter id" id="a"/> <p>Enter Confirm Pass</p> <input class="in" type="password" placeholder="Enter password" id="b"/> <br> <input type="submit" onmouseenter="fa()" onclick="alert('waaaa')" id="bt" /> </div> </body> </html>

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SnakeGame.py (1).txt0.03 KB

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Which of the following is used to define a block of code in Python language?
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