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Data Analysis Books | Python | SQL | Excel | Artificial Intelligence | Power BI | Tableau | AI Resources (@learndataanalysis) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 51 814 obunachidan iborat bo'lib, Taสผlim toifasida 3 359-o'rinni va Hindiston mintaqasida 7 261-o'rinni egallagan.
๐ Auditoriya koโrsatkichlari va dinamika
ะฝะตะฒัะดะพะผะพ sanasidan buyon loyiha tez oโsib, 51 814 obunachiga ega boโldi.
13 Iyun, 2026 dagi oxirgi maโlumotlarga koโra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni 494 ga, soโnggi 24 soatda esa 39 ga oโzgardi va umumiy qamrov yuqori darajada qolmoqda.
- Tasdiqlash holati: Tasdiqlanmagan
- Jalb etish (ER): Auditoriya oโrtacha 7.77% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 1.34% ini tashkil etuvchi reaksiyalarni toโplaydi.
- Post qamrovi: Har bir post oโrtacha 4 024 marta koโriladi; birinchi sutkada odatda 693 ta koโrish yigโiladi.
- Reaksiyalar va oโzaro taโsir: Auditoriya faol: har bir postga oโrtacha 8 ta reaksiya keladi.
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๐ Tavsif va kontent siyosati
Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida taโriflaydi:
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#dataanalysis
#dataanalysisbooks
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Yuqori yangilanish chastotasi (oxirgi maโlumot 14 Iyun, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli boโlib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taสผlim toifasidagi muhim taโsir nuqtasiga aylantirishini koโrsatadi.
def is_palindrome(s):
return s == s[::-1]
print(is_palindrome("madam")) # True
print(is_palindrome("hello")) # False
2. How to find the factorial of a number using recursion?
def factorial(n):
if n == 0 or n == 1:
return 1
return n * factorial(n - 1)
print(factorial(5)) # 120
3. How to merge two dictionaries in Python?
dict1 = {'a': 1, 'b': 2}
dict2 = {'c': 3, 'd': 4}
# Method 1 (Python 3.5+)
merged_dict = {**dict1, **dict2}
# Method 2 (Python 3.9+)
merged_dict = dict1 | dict2
print(merged_dict)
4. How to find the intersection of two lists?
list1 = [1, 2, 3, 4]
list2 = [3, 4, 5, 6]
intersection = list(set(list1) & set(list2))
print(intersection) # [3, 4]
5. How to generate a list of even numbers from 1 to 100?
even_numbers = [i for i in range(1, 101) if i % 2 == 0]
print(even_numbers)
6. How to find the longest word in a sentence?
def longest_word(sentence):
words = sentence.split()
return max(words, key=len)
print(longest_word("Python is a powerful language")) # "powerful"
7. How to count the frequency of elements in a list?
from collections import Counter
my_list = [1, 2, 2, 3, 3, 3, 4]
frequency = Counter(my_list)
print(frequency) # Counter({3: 3, 2: 2, 1: 1, 4: 1})
8. How to remove duplicates from a list while maintaining the order?
def remove_duplicates(lst):
return list(dict.fromkeys(lst))
my_list = [1, 2, 2, 3, 4, 4, 5]
print(remove_duplicates(my_list)) # [1, 2, 3, 4, 5]
9. How to reverse a linked list in Python?
class Node:
def __init__(self, data):
self.data = data
self.next = None
def reverse_linked_list(head):
prev = None
current = head
while current:
next_node = current.next
current.next = prev
prev = current
current = next_node
return prev
# Create linked list: 1 -> 2 -> 3
head = Node(1)
head.next = Node(2)
head.next.next = Node(3)
# Reverse and print the list
reversed_head = reverse_linked_list(head)
while reversed_head:
print(reversed_head.data, end=" -> ")
reversed_head = reversed_head.next
10. How to implement a simple binary search algorithm?
def binary_search(arr, target):
low, high = 0, len(arr) - 1
while low <= high:
mid = (low + high) // 2
if arr[mid] == target:
return mid
elif arr[mid] < target:
low = mid + 1
else:
high = mid - 1
return -1
print(binary_search([1, 2, 3, 4, 5, 6, 7], 4)) # 3
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Hope it helps :)SELECT name, email FROM users;
This fetches only the name and email columns from the users table.
โ๏ธ Used when you donโt want all columns from a table.
2๏ธโฃ Filter Records with WHERE
SELECT * FROM users WHERE age > 30;
The WHERE clause filters rows where age is greater than 30.
โ๏ธ Used for applying conditions on data.
3๏ธโฃ ORDER BY Clause
SELECT * FROM users ORDER BY registered_at DESC;
Sorts all users based on registered_at in descending order.
โ๏ธ Helpful to get latest data first.
4๏ธโฃ Aggregate Functions (COUNT, AVG)
SELECT COUNT(*) AS total_users, AVG(age) AS avg_age FROM users;
Explanation:
- COUNT(*) counts total rows (users).
- AVG(age) calculates the average age.
โ๏ธ Used for quick stats from tables.
5๏ธโฃ GROUP BY Usage
SELECT city, COUNT(*) AS user_count FROM users GROUP BY city;
Groups data by city and counts users in each group.
โ๏ธ Use when you want grouped summaries.
6๏ธโฃ JOIN Tables
SELECT users.name, orders.amount
FROM users
JOIN orders ON users.id = orders.user_id;
Fetches user names along with order amounts by joining users and orders on matching IDs.
โ๏ธ Essential when combining data from multiple tables.
7๏ธโฃ Use of HAVING
SELECT city, COUNT(*) AS total
FROM users
GROUP BY city
HAVING COUNT(*) > 5;
Like WHERE, but used with aggregates. This filters cities with more than 5 users.
โ๏ธ **Use HAVING after GROUP BY.**
8๏ธโฃ Subqueries
SELECT * FROM users
WHERE salary > (SELECT AVG(salary) FROM users);
Finds users whose salary is above the average. The subquery calculates the average salary first.
โ๏ธ Nested queries for dynamic filtering9๏ธโฃ CASE Statementnt**
SELECT name,
CASE
WHEN age < 18 THEN 'Teen'
WHEN age <= 40 THEN 'Adult'
ELSE 'Senior'
END AS age_group
FROM users;
Adds a new column that classifies users into categories based on age.
โ๏ธ Powerful for conditional logic.
๐ Window Functions (Advanced)
SELECT name, city, score,
RANK() OVER (PARTITION BY city ORDER BY score DESC) AS rank
FROM users;
Ranks users by score *within each city*.
SQL Learning Series: https://whatsapp.com/channel/0029VanC5rODzgT6TiTGoa1v/1075
Endi mavjud! Telegram Tadqiqoti 2025 โ yilning asosiy insaytlari 
