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AI Coding & CSE Fundamentals

AI Coding & CSE Fundamentals

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🚀 Explore AI, Coding & Computer Science Fundamentals. 💻 Programming • DSA • DBMS • OS • Networks 🤖 AI & Emerging Technologies 🛠️ Projects • Tutorials • Learning Resources 📚 Your freedom to gain knowledge for free.

Ko'proq ko'rsatish

📈 Telegram kanali AI Coding & CSE Fundamentals analitikasi

AI Coding & CSE Fundamentals (@aicoding_csefundamentals) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 12 310 obunachidan iborat bo'lib, Texnologiyalar & Aralashmalar toifasida 10 235-o'rinni va Hindiston mintaqasida 31 257-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 12 310 obunachiga ega bo‘ldi.

13 Noyabr, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -236 ga, so‘nggi 24 soatda esa -9 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 10.85% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining N/A% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 1 337 marta ko‘riladi; birinchi sutkada odatda 0 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 11 ta reaksiya keladi.
  • Tematik yo‘nalishlar: Kontent input, string, scanf("%d, array, element kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida ta’riflaydi:
“🚀 Explore AI, Coding & Computer Science Fundamentals. 💻 Programming • DSA • DBMS • OS • Networks 🤖 AI & Emerging Technologies 🛠️ Projects • Tutorials • Learning Resources 📚 Your freedom to gain knowledge for free.”

Yuqori yangilanish chastotasi (oxirgi ma’lumot 14 Noyabr, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Texnologiyalar & Aralashmalar toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

12 310
Obunachilar
-924 soatlar
-837 kun
-23630 kun
Postlar arxiv
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//program to print leap years from m to n'th year #include<stdio.h> int main() { int m,n; printf("Enter the year m:"); scanf("%d",&m); printf("Enter the year n:"); scanf("%d",&n); do { if((m%4==0 && m%100!=0) || (m%400==0)) { printf("%d is a leap year\n",m); } else{ printf("%d is not a leap year\n",m); } m+=1; }while(m<=n); return 0; }

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C PROGRAMMING LANGUAGE 💻: https://docs.google.com/forms/d/e/1FAIpQLScJTzmc6K94aL0LQxxaLp_mN5jlcBWc8QJ0S_ZNGXDX13tSJQ/viewform?usp=sf_link ☝️every one fill the form guys it will no take more than 2 minutes

//calculate power of a number without using pow() function #include<stdio.h> int main() { int base,exp,res=1,i; printf("Enter the base:"); scanf("%d",&base); printf("Enter the exponent:"); scanf("%d",&exp); for(i=1;i<=exp;i++) { res=res*base; } printf("%d to the power of %d is :%d",base,exp,res); return 0; }

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