Firibgarlarga uchmang! Telemetrio bunday kanallarni topadi va belgilaydi 👉 Belgini ko‘rmoqchi bo‘lsangiz, obuna bo‘ling

AI Coding & CSE Fundamentals

Kanalga Telegram’da o‘tish

🚀 Explore AI, Coding & Computer Science Fundamentals. 💻 Programming • DSA • DBMS • OS • Networks 🤖 AI & Emerging Technologies 🛠️ Projects • Tutorials • Learning Resources 📚 Your freedom to gain knowledge for free.

Ko'proq ko'rsatish

Hindiston31 257Texnologiyalar & Aralashmalar10 235...

📈 Telegram kanali AI Coding & CSE Fundamentals analitikasi

AI Coding & CSE Fundamentals (@aicoding_csefundamentals) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 12 310 obunachidan iborat bo'lib, Texnologiyalar & Aralashmalar toifasida 10 235-o'rinni va Hindiston mintaqasida 31 257-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 12 310 obunachiga ega bo‘ldi.

13 Noyabr, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -236 ga, so‘nggi 24 soatda esa -9 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

Tasdiqlash holati: Tasdiqlanmagan
Jalb etish (ER): Auditoriya o‘rtacha 10.85% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining N/A% ini tashkil etuvchi reaksiyalarni to‘playdi.
Post qamrovi: Har bir post o‘rtacha 1 337 marta ko‘riladi; birinchi sutkada odatda 0 ta ko‘rish yig‘iladi.
Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 11 ta reaksiya keladi.
Tematik yo‘nalishlar: Kontent input, string, scanf("%d, array, element kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida ta’riflaydi:
“🚀 Explore AI, Coding & Computer Science Fundamentals. 💻 Programming • DSA • DBMS • OS • Networks 🤖 AI & Emerging Technologies 🛠️ Projects • Tutorials • Learning Resources 📚 Your freedom to gain knowledge for free.”

Yuqori yangilanish chastotasi (oxirgi ma’lumot 14 Noyabr, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Texnologiyalar & Aralashmalar toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

12 310

Obunachilar

-924 soatlar

-837 kun

-23630 kun

1 337

Post ko'rishlar

Ma'lumot yo'q24 soatlar

Ma'lumot yo'q48 soatlar

10.85%

Muloqot nisbati

Ma'lumot yo'q

Kuniga postlar

Ads index

Postlar arxiv

12 310

https://t.me/deals_flipkart_amazon_loots

12 310

all of you join the below channel, you can find Flipkart deals which are of low price, be the first to grab the loots 👇👇👇👇👇👇👇👇👇👇👇

12 310

☝️☝️☝️all of you join the above channel you can find Flipkart deals which are of low price be the first to grab the loots

12 310

https://t.me/deals_flipkart_amazon_loots

12 310

☝️☝️☝️all of you join the above channel you can find Flipkart deals which are of low price be the first to grab the loots

12 310

https://t.me/deals_flipkart_amazon_loots

12 310

☝️☝️☝️all of you join the above channel you can find Flipkart deals which are of low price be the first to grab the loots

12 310

https://t.me/deals_flipkart_amazon_loots

12 310

Program to check whether a number is palindrome or not using for loop. ------------------------------ #include <stdio.h> int main() { int num, reversedNum = 0, remainder, originalNum; printf("Enter an integer: "); scanf("%d", &num); originalNum = num; // reverse the number for (; num != 0; num /= 10) { remainder = num % 10; reversedNum = reversedNum * 10 + remainder; } if (originalNum == reversedNum) { printf("%d is a palindrome number.", originalNum); } else { printf("%d is not a palindrome number.", originalNum); } return 0; } ------------------------------- #for_loop