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AI Coding & CSE Fundamentals

AI Coding & CSE Fundamentals

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🚀 Explore AI, Coding & Computer Science Fundamentals. 💻 Programming • DSA • DBMS • OS • Networks 🤖 AI & Emerging Technologies 🛠️ Projects • Tutorials • Learning Resources 📚 Your freedom to gain knowledge for free.

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📈 Telegram kanali AI Coding & CSE Fundamentals analitikasi

AI Coding & CSE Fundamentals (@aicoding_csefundamentals) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 12 318 obunachidan iborat bo'lib, Texnologiyalar & Aralashmalar toifasida 10 235-o'rinni va Hindiston mintaqasida 31 257-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 12 318 obunachiga ega bo‘ldi.

13 Noyabr, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -236 ga, so‘nggi 24 soatda esa -9 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 10.85% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining N/A% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 1 337 marta ko‘riladi; birinchi sutkada odatda 0 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 11 ta reaksiya keladi.
  • Tematik yo‘nalishlar: Kontent input, string, scanf("%d, array, element kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida ta’riflaydi:
“🚀 Explore AI, Coding & Computer Science Fundamentals. 💻 Programming • DSA • DBMS • OS • Networks 🤖 AI & Emerging Technologies 🛠️ Projects • Tutorials • Learning Resources 📚 Your freedom to gain knowledge for free.”

Yuqori yangilanish chastotasi (oxirgi ma’lumot 14 Noyabr, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Texnologiyalar & Aralashmalar toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

12 318
Obunachilar
-924 soatlar
-837 kun
-23630 kun
Postlar arxiv
#Relations #Reflexive #Symmetric #Transitive 📢 Make sure you’ve started the bot @quizz_poster_bot Click below for explanation 👇

If a relation R is defined on ℝ by aRb ⇔ |a − b| ≤ 1, then R is:
Anonymous voting

#Sets #Counting #LogicalReasoning 📢 Make sure you’ve started the bot @quizz_poster_bot Click below for explanation 👇

In a college of 300 students, every student reads 5 newspapers and every newspaper is read by 60 students. How many newspapers are there?
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#Sets #Intersection #Geometry #JEE 📢 Make sure you’ve started the bot @quizz_poster_bot Click below for explanation 👇

How many points are there in the intersection of A = {(x, y): x² + y² = 25} and B = {(x, y): x²/144 + y²/16 = 1}?
Anonymous voting

#C #Conditional #Ternary 📢 Make sure you’ve started the bot @quizz_poster_bot Click below for explanation 👇

Which of these correctly uses a ternary operator?
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int x = 5;
printf("%s", x > 3 ? "Yes" : "No");

#C #Bitwise #ShiftOperator 📢 Make sure you’ve started the bot @quizz_poster_bot Click below for explanation 👇

What is the output of this statement?
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int a = 10;
int b = 2;
printf("%d", a >> b);

#C #Operators #Bitwise 📢 Make sure you’ve started the bot @quizz_poster_bot Click below for explanation 👇

Which of the following is a bitwise operator?
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#C #Operators #ExpressionEvaluation 📢 Make sure you’ve started the bot @quizz_poster_bot Click below for explanation 👇

What is the output of this expression?
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int x = 3;
int y = x++ + ++x;
printf("%d", y);

#C #Operators #Equality 📢 Make sure you’ve started the bot @quizz_poster_bot Click below for explanation 👇

What does the '==' operator do in C?
Anonymous voting

#C #Operators #Increment #Postfix 📢 Make sure you’ve started the bot @quizz_poster_bot Click below for explanation 👇