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allcoding1

allcoding1

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allcoding1 (@allcoding1) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 20 652 obunachidan iborat bo'lib, Taʼlim toifasida 9 752-o'rinni va Hindiston mintaqasida 19 463-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 20 652 obunachiga ega bo‘ldi.

05 Noyabr, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -402 ga, so‘nggi 24 soatda esa -16 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 3.54% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 1.10% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 731 marta ko‘riladi; birinchi sutkada odatda 227 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 2 ta reaksiya keladi.
  • Tematik yo‘nalishlar: Kontent dsa, stack, namaste, javascript, learning kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Kanal uchun tavsif kiritilmagan.

Yuqori yangilanish chastotasi (oxirgi ma’lumot 06 Noyabr, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

20 652
Obunachilar
-1624 soatlar
-867 kun
-40230 kun
Postlar arxiv
TCS NQT 19TH AUG 1)625/126 2)1/15 3)1/5,-1/5 4)7 Telegram:- @allcoding1

Tcs 9 am answers 1) 625/126 2) 1/15 Telegram - @allcoding1

Losses and win Python
Losses and win Python

Number of Ways Read Books Thryve Digital Python 3 Telegram:- @allcoding1
Number of Ways Read Books Thryve Digital Python 3 Telegram:- @allcoding1

Reverse Digits Thryve Digital Python 3 Telegram:- @allcoding1
Reverse Digits Thryve Digital Python 3 Telegram:- @allcoding1

#include using namespace std; int main() { int t,n,rev=0; cin>>n; while(n--) { cin>>t; rev=0; int a; a=t; while(a
#include <iostream> using namespace std; int main() { int t,n,rev=0; cin>>n; while(n--) { cin>>t; rev=0; int a; a=t; while(a!=0) { int r=a%10; rev=rev*10+r; a=a/10; } if(rev==t) cout<<"wins"<<endl; else cout<<"losses"<<endl; } return 0; } The block game code C++

The block game code in python 3
+1
The block game code in python 3

Get the magic number code in python
+1
Get the magic number code in python

Last occurrence code in c++
+1
Last occurrence code in c++

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Private channel for Tomorrow TCS Exam Ans Ask your 10 friends to follow Instagram And subscribe🛑 & LIKE👍 youtube channel and send screenshot to He will add you to private channel for tomorrow Ans YouTube channel:- https://youtu.be/ofDvcsP3OWY https://youtu.be/ofDvcsP3OWY https://youtu.be/ofDvcsP3OWY Instagram:- https://instagram.com/allcoding1_official?igshid=YmMyMTA2M2Y= https://instagram.com/allcoding1_official?igshid=YmMyMTA2M2Y= https://instagram.com/allcoding1_official?igshid=YmMyMTA2M2Y= Send A screen shots in this group https://t.me/+FQoo8kIBWww2Y2Fl Share with your friends and college group's

def jogging_ways(n: int) -> int: a, b = 1, 1 for i in range(n): a, b = b, a+b return a %10000007 Run Walk and Run Python 3 Te
def jogging_ways(n: int) -> int:     a, b = 1, 1     for i in range(n):         a, b = b, a+b     return a %10000007 Run Walk and Run Python 3 Telegram:- @allcoding1

Sum of GP C++ Telegram:- @allcoding1
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Sum of GP C++ Telegram:- @allcoding1

Minimum no. Of jumps Python Telegram:- @allcoding1
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Minimum no. Of jumps Python Telegram:- @allcoding1

def santa(num,d): if d.get(num): return 1 rem = sum = 0; while(num > 0): rem = num%10; sum = sum + (rem*rem); num = num//10;
def santa(num,d): if d.get(num): return 1 rem = sum = 0; while(num > 0): rem = num%10; sum = sum + (rem*rem); num = num//10; return sum def gift(n): pre = [0 for i in range(n + 1)] d = {} for i in range(1, n + 1): result = i while(result != 1 and result != 4): result = santa(result,d); if(result == 1): d[i] = 1 pre[i] += i + pre[i-1] else: pre[i] = pre[i-1] return pre pre = findall(1000001) t = int(input()) for _ in range(t): l,r = map(int,input().split()) print(pre[r] - pre[l-1]) Python Telegram :-- @allcoding1

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