allcoding1
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allcoding1 (@allcoding1) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 21 584 obunachidan iborat bo'lib, Taʼlim toifasida 9 062-o'rinni va Hindiston mintaqasida 19 025-o'rinni egallagan.
📊 Auditoriya ko‘rsatkichlari va dinamika
невідомо sanasidan buyon loyiha tez o‘sib, 21 584 obunachiga ega bo‘ldi.
29 Avgust, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -360 ga, so‘nggi 24 soatda esa -8 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.
- Tasdiqlash holati: Tasdiqlanmagan
- Jalb etish (ER): Auditoriya o‘rtacha 5.78% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 1.10% ini tashkil etuvchi reaksiyalarni to‘playdi.
- Post qamrovi: Har bir post o‘rtacha 1 247 marta ko‘riladi; birinchi sutkada odatda 238 ta ko‘rish yig‘iladi.
- Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 0 ta reaksiya keladi.
- Tematik yo‘nalishlar: Kontent dsa, stack, namaste, javascript, learning kabi asosiy mavzularga jamlangan.
📝 Tavsif va kontent siyosati
Kanal uchun tavsif kiritilmagan.
Yuqori yangilanish chastotasi (oxirgi ma’lumot 30 Avgust, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.
21 584
Obunachilar
-824 soatlar
-787 kunlar
-36030 kunlar
Postlar arxiv
21 578
All codes are available
To easily find out ur codes
Once check it 👇👇
https://www.instagram.com/allcoding1_official?igsh=ZHJpNXdpeWh1d2No
21 578
///find largest swuare linked in
public static int findLargestSquareSize(int[][] samples) {
if (samples == null || samples.length == 0) return 0;
int n = samples.length;
int maxSize = 0;
int[][] dp = new int[n][n];
for (int i = 0; i < n; i++) {
dp[i][0] = samples[i][0];
dp[0][i] = samples[0][i];
maxSize = Math.max(maxSize, dp[i][0]);
maxSize = Math.max(maxSize, dp[0][i]);
}
for (int i = 1; i < n; i++) {
for (int j = 1; j < n; j++) {
if (samples[i][j] == 1) {
dp[i][j] = Math.min(Math.min(dp[i-1][j], dp[i][j-1]), dp[i-1][j-1]) + 1;
maxSize = Math.max(maxSize, dp[i][j]);
} else {
dp[i][j] = 0;
}
}
}
return maxSize;
}
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//Equilibrium path
#include <bits/stdc++.h>
using namespace std;
string trim(string str) {
str.erase(0, str.find_first_not_of(' '));
str.erase(str.find_last_not_of(' ') + 1);
return str;
}
int solve(int N, vector<int> A) {
int total_sum = accumulate(A.begin(), A.end(), 0);
int left_sum = 0;
int equilibrium_count = 0;
for (int i = 0; i < N; ++i) {
int right_sum = total_sum - left_sum - A[i];
if (left_sum == right_sum) {
equilibrium_count++;
}
left_sum += A[i];
}
return equilibrium_count;
}
int main() {
ios::sync_with_stdio(0);
cin.tie(0); cout.tie(0);
string inputline;
getline(cin, inputline);
int N = stoi(trim(inputline));
vector<int> A(N);
for (int j = 0; j < N; j++) {
getline(cin, inputline);
A[j] = stoi(trim(inputline));
}
int result = solve(N, A);
cout << result << endl;
return 0;
}
21 578
// coins game
import java.util.*;
class HelloWorld {
static int helper(int a, int b, int i ,int[]x,int n){
if(i==x.length) return 0;
int left=(x[i]>n)?0:Math.abs(x[i]-a)+helper(x[i],b,i+1,x,n);
int right=(x[i]>n)?0:Math.abs(x[i]-b)+helper(a,x[i],i+1,x,n);
return Math.min(left,right);
}
public static void main(String[] args) {
Scanner sc=new Scanner(System.in);
int N=sc.nextInt();
int Q=sc.nextInt();
int A=sc.nextInt();
int B=sc.nextInt();
int[]x=new int[Q];
for(int i=0;i<Q;i++){
x[i]=sc.nextInt();
}
System.out.println(helper(A,B,0,x,N));
}
}
21 578
All codes are available
Once check it 👇👇
https://www.instagram.com/allcoding1_official?igsh=ZHJpNXdpeWh1d2No
21 578
import sys
def get_ans(N, K, A):
def main():
N = int(sys.stdin.readline().strip())
K = int(sys.stdin.readline().strip())
A = []
for _ in range(N):
A.append(int(sys.stdin.readline().strip()))
result = get_ans(N, K, A)
print(result)
if name == "main":
main()
Subset with LCM code in python
