allcoding1

Kanalga Telegram’da o‘tish

Ko'proq ko'rsatish

📈 Telegram kanali allcoding1 analitikasi

allcoding1 (@allcoding1) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 22 469 obunachidan iborat bo'lib, Taʼlim toifasida 8 831-o'rinni va Hindiston mintaqasida 19 197-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 22 469 obunachiga ega bo‘ldi.

21 Iyun, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -372 ga, so‘nggi 24 soatda esa -13 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

Tasdiqlash holati: Tasdiqlanmagan
Jalb etish (ER): Auditoriya o‘rtacha 5.50% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 1.28% ini tashkil etuvchi reaksiyalarni to‘playdi.
Post qamrovi: Har bir post o‘rtacha 1 236 marta ko‘riladi; birinchi sutkada odatda 288 ta ko‘rish yig‘iladi.
Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 1 ta reaksiya keladi.
Tematik yo‘nalishlar: Kontent dsa, stack, namaste, javascript, learning kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Kanal uchun tavsif kiritilmagan.

Yuqori yangilanish chastotasi (oxirgi ma’lumot 22 Iyun, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

22 469

Obunachilar

-1324 soatlar

-737 kunlar

-37230 kunlar

1 236

Post ko'rishlar

~ 28824 soatlar

~ 38748 soatlar

5.50%

Muloqot nisbati

Ma'lumot yo'q

Kuniga postlar

Ads index

beta

Postlar arxiv

22 469

TCS NQT 6pm 1)2772 2)10 3)2 4)280 5)720 6)B=A 7)294674 8)12% 9)1:2 13)22 14)13 15)9 16)32 17)15.67% Telegram:- @allcoding1

22 469

TCS NQT 6pm 1)2772 2)10 3)2 4)280 5)720 6)B=A 7)294674 8)12% 9)1:2 13)22 14)13 15)9 16)32 Telegram:- @allcoding1

22 469

TCS NQT 6pm 1)2772 2)10 3)2 4)280 5)720 6)B=A 7)294674 8)12% 9)1:2 13)22 14)13 15)9 Telegram:- @allcoding1

22 469

TCS NQT 6pm 1)2772 2)10 3)2 4)280 5)720 6)B=A 7)294674 8)10 Telegram:- @allcoding1

22 469

TCS NQT 6pm 1)2772 2)10 3)2 4)280 5)720 6)B=A 7)294674 Telegram:- @allcoding1

22 469

TCS NQT 6pm 1)2772 2)10 3)2 4)280 5)720 6)B=a Telegram:- @allcoding1

22 469

TCS NQT 6pm 1)2772 2)10 3)2 4)280 5)720 Telegram:- @allcoding1

22 469

TCS NQT 6pm 1)2772 2)10 3)2 4)280 Telegram:- @allcoding1

22 469

TCS NQT 6pm 1)2772 2)10 3)2 Telegram:- @allcoding1

22 469

Tcs nqt 6pm 1)2772 2)10 Telegram:- @allcoding1

22 469

John c++ Telegram:- @allcoding1

22 469

Python Jack and Jill Code Telegram - @allcoding1

22 469

n=int(input()) jk=list(map(int,input().split())) jl=list(map(int,input().split())) l=len(jk) jksum=0 jlsum=0 lind=[] while l!=0: b=[] ind=jk.index(max(jk)) jksum+=max(jk) lind.append(ind) for i in range(0,len(jl)): if i not in lind: b.append(jl[i]) l-=1 jlsum+=max(b) if jksum>jlsum: print("jack") elif jksum==jlsum: print("Tie") else: print("jill") Python Jack and Jill Code Telegram - @allcoding1

22 469

Python Jack and Jill Code Telegram - @allcoding1

22 469

Advance apti answers 1. 5/24 2. 352 3. 48x^2-273x+338=0 4. 30,30 5. 120 6. 15 7. 1080 8. II and III only 9. I and II only 10. I and IV only Telegram :- @allcoding1

22 469

Advanced apitude 1)5/24 2)228 3)48X^2+21X+102=0 4) 30,30 5) 14 6) 41 7) 12870 8) ii and iii 9) 2 and 3 10)1 and 4 only Telegram:- @allcoding1

22 469

Advanced apitude 1)5/24 2)228 3)48X^2+21X+102=0 4) 30,30 5) 14 6) 41 7) 12870 8) ii and iii 9) 2 and 3 only Telegram:- @allcoding1

22 469

Advanced apitude 1)5/24 2)228 3)48X^2+21X+102=0 4) 30,30 5) 14 6) 41 7) 12870 8) ii and iii Telegram:- @allcoding1

22 469

Advanced apitude 1)5/24 2)228 3)48X^2+21X+102=0 4) 30,30 5) 14 6) 41 7) 12870 Telegram @allcoding1