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allcoding1

allcoding1

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allcoding1 (@allcoding1) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 22 509 obunachidan iborat bo'lib, Taʼlim toifasida 8 844-o'rinni va Hindiston mintaqasida 19 350-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 22 509 obunachiga ega bo‘ldi.

18 Iyun, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -405 ga, so‘nggi 24 soatda esa -11 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 6.44% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 1.27% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 1 450 marta ko‘riladi; birinchi sutkada odatda 287 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 2 ta reaksiya keladi.
  • Tematik yo‘nalishlar: Kontent dsa, stack, namaste, javascript, learning kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Kanal uchun tavsif kiritilmagan.

Yuqori yangilanish chastotasi (oxirgi ma’lumot 19 Iyun, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

22 509
Obunachilar
-1124 soatlar
-887 kunlar
-40530 kunlar
Postlar arxiv
Guys 👉 I need money if you have interested send a money 💸💰 👉Send a your screen shot in @Priya_k Don't forget 👆 NOT:- I d
Guys 👉 I need  money  if you have interested send a money 💸💰 👉Send a your screen shot in @Priya_k Don't forget 👆 NOT:- I don't force anyone

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#include <bits/stdc++.h> using namespace std; vector<string> rows; char alphabet; string findPrecedingAlphabets() {     int r = -1, c = -1;     for (int i = 0; i < rows.size(); i++)     {         int idx = rows[i].find(alphabet);         if (idx != string::npos)         {             r = i;             c = idx;             break;         }     }     if (r == -1)         return "alphabet not found";     string a = "";     if (r > 0)         a += rows[r - 1][c];     if (c > 0)         a += rows[r][c - 1];     return a; } int main() {     int n;     cin >> n;     for (int i = 0; i < n; i++)     {         string row;         cin >> row;         rows.push_back(row);     }     cin >> alphabet;     cout << findPrecedingAlphabets() << endl;     return 0; } IBM Exam Ans Alphabets on Excel sheets code Python Telegram:- @allcoding1

Python Telegram:- @allcoding1
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Python Telegram:- @allcoding1

C++ IBM code Telegram:- @allcoding1
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C++ IBM code Telegram:- @allcoding1