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allcoding1

allcoding1

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allcoding1 (@allcoding1) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 22 431 obunachidan iborat bo'lib, Taʼlim toifasida 8 829-o'rinni va Hindiston mintaqasida 19 037-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 22 431 obunachiga ega bo‘ldi.

25 Iyun, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -366 ga, so‘nggi 24 soatda esa -7 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 4.55% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 1.43% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 1 020 marta ko‘riladi; birinchi sutkada odatda 321 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 1 ta reaksiya keladi.
  • Tematik yo‘nalishlar: Kontent dsa, stack, namaste, javascript, learning kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Kanal uchun tavsif kiritilmagan.

Yuqori yangilanish chastotasi (oxirgi ma’lumot 26 Iyun, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

22 431
Obunachilar
-724 soatlar
-747 kunlar
-36630 kunlar
Postlar arxiv
1) 10 2) 0.4 3) 196 4) 0.18 5) 60 6) 34 7) 195 8.716 9. 6: 44: 33 Telegram - @allcoding1

1) 10 2) 0.4 3) 196 4) 0.18 5) 60 6) 34 7) 195 8.716 Telegram - @allcoding1

1) 10 2) 0.4 3) 196 4) 0.18 5) 60 6) 34 7) 195 Telegram - @allcoding1

1) 10 2) 0.4 3) 196 4) 0.18 5.60 Telegram - @allcoding1

1) 10 2) 0.4 3) 196 4) 0.18 Telegram - @allcoding1

Joe code Python Test cases passed Telegram:- @allcoding1
+2
Joe code Python Test cases passed Telegram:- @allcoding1

n=int(input()) lst1=list(map(int,input().split())) lst2=[] subs=[] st=[] def find(inp,out):     if(len(inp)==0):         if(len(out)!=0):             st.append(out)         return     find(inp[1:],out[:])     if(len(out)==0):         find(inp[1:],inp[:1])     elif(inp[0]>out[-1]):         out.append(int[0])         find(inp[1:],out[:]) find(lst1,lst2) print(lst1) for i in st:     print(*i) print(st) Python James code Telegram - @allcoding1

✅✅ Joe code Python3 Telegram:- @allcoding1
✅✅ Joe code Python3 Telegram:- @allcoding1

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Python Joe code Telegram - @allcoding1
Python Joe code Telegram - @allcoding1

1)refer to CMD 2)Ajmal 3) 4E1F Telegram:- @allcoding1

Reasoning 1) NL 2) A, b and d 5)Data in statement ii Alon..... 6)Either statement 7) Mother's 8)X for 9) Social 10) the case is to be a post graduate 11) rejected 12) Both 1 and 2 13) Both Telegram:- @allcoding1

Reasoning 1) NL 2) A, b and d 5)Data in statement ii 6)Either statement 7) Mother's 8)X for 9) Social Telegram:- @allcoding1

Verbal 1) A computer 2) nor 3) through 4) A) developed b ) esteemed 5)CDAB 6) Ah 7) run off the shore 8) jackpot 9)2431 10) DCBAE 11)DCEAB 12)S and P 13) Generally regarded as synthesis; while expression are more 14) need not Q15) Kleptomania 16) Entourage 17) Eabdc 18) Rs 19) chulibili mausie seems Telegram:- @allcoding1

TCS Aptitude 1) 8400 2)2000 3)99 2/√2 4) 51 5)12 6-30% 7-2500 8- 2698 9+ 112500 10- 5515.35kg 11- 50:105:54 12 - 988 13- 2 23/38 14- 2:3 15- 25hrs 36 min 16) 21.4 17) 16 18) 500 19) 1400 20)5.565

TCS Aptitude 1) 8400 2)2000 3)99 4) 51 5)12 6-30% 7-2500 8- 2698 9+ 112500 10- 5515.35kg 11- 50:105:54 12 - 988 13- 2 23/38 14- 2:3

TCS Aptitude @allcoding1 1) 8400 2)2000 3)99 4) 51 5)12 6-30% 7-2500 8- 2698 9+ 111500 10- 5515.35kg 11- 50:105:54 12 - 988 Telegram:- @allcoding1

1) 8500 2) 2000 3) 99 /2√2 4) 51 5) 12 6) 30% 7) 2500 8) 2066 Telegram:- @allcoding1

1) 8500 2) 2000 3) 99 4) 51 Telegram - @allcoding1

🎯WIPRO CTC  - 3.5LPA Role  - GRADUTE TRAINEE ENGINEER | TESTING Location  -    pan india Experience -  freshers Batch - 2022 /2021 /2020 /2019 /2018 Date -  22August 2022 APPLY - www.allcoding1.com