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allcoding1

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allcoding1 (@allcoding1) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 22 460 obunachidan iborat bo'lib, Taʼlim toifasida 8 832-o'rinni va Hindiston mintaqasida 19 143-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 22 460 obunachiga ega bo‘ldi.

22 Iyun, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -381 ga, so‘nggi 24 soatda esa -19 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 5.20% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 1.24% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 1 169 marta ko‘riladi; birinchi sutkada odatda 278 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 1 ta reaksiya keladi.
  • Tematik yo‘nalishlar: Kontent dsa, stack, namaste, javascript, learning kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Kanal uchun tavsif kiritilmagan.

Yuqori yangilanish chastotasi (oxirgi ma’lumot 23 Iyun, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

22 460
Obunachilar
-1924 soatlar
-797 kunlar
-38130 kunlar
Postlar arxiv
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// An efficient C program to find // sum of diagonals #include #include   const int M = 4; const int N = 4;   void
// An efficient C program to find // sum of diagonals #include <stdio.h> #include <stdlib.h>   const int M = 4; const int N = 4;   void printDiagonalSums(int mat[M][N]) {     int principal = 0, secondary = 0;     for (int i = 0; i < N; i++)     {         principal += mat[i][i];         secondary += mat[i][N - i - 1];            }       printf("%s","Principal Diagonal:");     printf("%d\n", principal);     printf("%s", "Secondary Diagonal:");     printf("%d\n", secondary); }   // Driver code int main() {     int a[4][4] = {{1, 2, 3, 4},                    {5, 6, 7, 8},                    {1, 2, 3, 4},                    {5, 6, 7, 8}};     printDiagonalSums(a);     return 0; } C language Telegram:- @allcoding1

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Tim code TCS exam Telegram:- @allcoding1
Tim code TCS exam Telegram:- @allcoding1

Dr strange code python TCS Exam Telegram:- @allcoding1
Dr strange code python TCS Exam Telegram:- @allcoding1

Frequency code Python TCS Exam Telegram:- @allcoding1
Frequency code Python TCS Exam Telegram:- @allcoding1

Frequency code TCS Exam Telegram:- @allcoding1
Frequency code TCS Exam Telegram:- @allcoding1

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Java Telegram:- @allcoding1
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One copying our Answer's Telegram:- @allcoding1
One copying our Answer's Telegram:- @allcoding1

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One copying our Answer's Telegram:- @allcoding1
One copying our Answer's Telegram:- @allcoding1

TCS Exam Telegram:- @allcoding1
TCS Exam Telegram:- @allcoding1

1)Both statements A and B are true 2)5/7 3)12.5 5)12/23 n 7)8% 8)3225 9)1200 10)4500 11)12.5 12)150 13)4 14)1:2:24 16)15:7 17)72 18)54:77 19)sin 92 20) 260 Telegram:- @allcoding1

Tcs NQT ANSWERS Numerical: 1)Both statements A and B are true 2)5/7 3)12.5 5)12/23 n 7)8% 8)3225 9)1200 10)4500 11)12.5 12)150 13)4 14)1:2:24 16)15:7 17)72 18)54:77 Telegram:- @allcoding1

Tcs NQT ANSWERS Numerical 1)Both statements A and B are true 2)5/7 3)12.5 5)12/23 n 7)8% 8)₹2800 Telegram:- @allcoding1

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