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allcoding1
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allcoding1 (@allcoding1) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 22 543 obunachidan iborat bo'lib, Taʼlim toifasida 8 854-o'rinni va Hindiston mintaqasida 19 507-o'rinni egallagan.
📊 Auditoriya ko‘rsatkichlari va dinamika
невідомо sanasidan buyon loyiha tez o‘sib, 22 543 obunachiga ega bo‘ldi.
14 Iyun, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -445 ga, so‘nggi 24 soatda esa -14 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.
- Tasdiqlash holati: Tasdiqlanmagan
- Jalb etish (ER): Auditoriya o‘rtacha 6.31% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 1.25% ini tashkil etuvchi reaksiyalarni to‘playdi.
- Post qamrovi: Har bir post o‘rtacha 1 423 marta ko‘riladi; birinchi sutkada odatda 282 ta ko‘rish yig‘iladi.
- Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 2 ta reaksiya keladi.
- Tematik yo‘nalishlar: Kontent dsa, stack, namaste, javascript, learning kabi asosiy mavzularga jamlangan.
📝 Tavsif va kontent siyosati
Kanal uchun tavsif kiritilmagan.
Yuqori yangilanish chastotasi (oxirgi ma’lumot 16 Iyun, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.
22 543
Obunachilar
-1424 soatlar
-947 kunlar
-44530 kunlar
Postlar arxiv
22 548
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Qualification : B.E/B/Tech/M.E. / M.Tech
Experience : Freshers
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22 548
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22 548
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22 548
🎯Atos Is Hiring
Degree:- Any Graduate
Batch:- 2019, 2020, 2021, 2022, 2023 & 2024
Apply Now:- https://www.allcoding1.com/2024/02/atos-off-campus-drive-for-any-graduate.html
Telegram:- @allcoding1
22 548
def helper(reward):
nums = []
for i in reward:
heappush(nums, -i)
ans = -heappop(nums)
i = 1
while nums:
temp = -heappop(nums)
if temp - i <= 0: break
ans += temp - i
i += 1
return ans
@allcoding1
22 548
int
getMinlength(vector<int>a,int k)
{
int ans=1;
long long mul=1;
for(int i=0;i<a.size();i++){
if(mul*a[i]>k){
ans++;
mul=a[i];
}
else{
mul*=a[i];
}
}
return ans;
}
L&T
@allcoding1
Q) compressing array
22 548
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Telegram:- @allcoding1
22 548
public class Solution {
public static int longestArraySegment(int array_length, List<Integer> arr) {
int maxLength = 1;
int currentLength = 1;
for (int i = 1; i < array_length; i++) {
if (arr.get(i) > arr.get(i - 1)) {
currentLength++;
} else {
currentLength = 1;
}
maxLength = Math.max(maxLength, currentLength);
}
currentLength = 1;
for (int i = 1; i < array_length; i++) {
if (arr.get(i) < arr.get(i - 1)) {
currentLength++;
} else {
currentLength = 1;
}
maxLength = Math.max(maxLength, currentLength);
}
return maxLength;
}
Ever increasing and ever decreasing - L&T
Java
Telegram:- @allcoding1
22 548
+1int solve(vector<int>& arr) { int n = arr.size(); if (n == 0) return 0;
int maxLen = 1; int currLen = 1; bool f = true;
for (int i = 1; i < n; ++i) { if ((arr[i] > arr[i-1] && f) II (arr[i] < arr[i-1] && !f)) { ++currLen; } else {
maxLen = max(maxLen, currLen); currLen = 2; f = arr[i] > arr[i-1]; }
maxLen = max(maxLen, currLen); return maxLen; }
C++
Telegram:- @allcoding1
L&T
22 548
int solve(vector<int>& arr) { int narr.size(); if (n == 0) return 0;
int maxLen = 1;
int currLen = 1;
bool f = true;
for (int i = 1; i < n; ++i) { if ((arr[i] > arr[i-1] && f) || (arr[i] < arr[i-1] && !f)) { ++currLen; } else { maxLen = max(maxLen, currLen); currLen = 2;
f = arr[i] > arr[i-1]
}
}
maxLen = max(maxLen, currLen); return maxLen;
}
C++
Telegram:- @allcoding1
L&t
Q) Ever - increasing & ever decreasing array segments
22 548
int solve(vector<int>& A) { int s = 0; for (const auto&n: A) { string sn = to_string(n); char md = *max_element(sn.begin().
sn.end());
s += md-'0';
}
return s;
}
C++
Telegram:- @allcoding1
L&t
Q) Encryption by digits
22 548
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Experience: Fresher
Qualification: B.Com. 2023 passed out
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22 548
22 548
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Job Position:- IT Software Developer (UX/UI/Fullstack)
Job ID: 3058496
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Department: Software Engineering
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Job Type:- Full-time
Last Date:- ASAP
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Telegram:- @allcoding1_official
22 548
def check_first_and_last_char(Str):
if Str[0].isdigit() and not Str[-1].isdigit():
print("Yes")
elif Str[-1].isdigit() and not Str[0].isdigit():
print("No")
else:
print("Invalid input")
Str = input()
check_first_and_last_char(Str)
@allcoding1
