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allcoding1 (@allcoding1) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 22 575 obunachidan iborat bo'lib, Taʼlim toifasida 8 822-o'rinni va Hindiston mintaqasida 19 518-o'rinni egallagan.
📊 Auditoriya ko‘rsatkichlari va dinamika
невідомо sanasidan buyon loyiha tez o‘sib, 22 575 obunachiga ega bo‘ldi.
12 Iyun, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -437 ga, so‘nggi 24 soatda esa -6 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.
- Tasdiqlash holati: Tasdiqlanmagan
- Jalb etish (ER): Auditoriya o‘rtacha 5.99% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 1.25% ini tashkil etuvchi reaksiyalarni to‘playdi.
- Post qamrovi: Har bir post o‘rtacha 1 353 marta ko‘riladi; birinchi sutkada odatda 283 ta ko‘rish yig‘iladi.
- Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 2 ta reaksiya keladi.
- Tematik yo‘nalishlar: Kontent dsa, stack, namaste, javascript, learning kabi asosiy mavzularga jamlangan.
📝 Tavsif va kontent siyosati
Kanal uchun tavsif kiritilmagan.
Yuqori yangilanish chastotasi (oxirgi ma’lumot 13 Iyun, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.
22 575
Obunachilar
-624 soatlar
-967 kunlar
-43730 kunlar
Postlar arxiv
22 575
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
int n = scanner.nextInt();
int[] left = new int[n];
int[] right = new int[n];
for (int i = 0; i < n; i++) {
left[i] = scanner.nextInt();
right[i] = scanner.nextInt();
}
int sumLeft = 0;
int sumRight = 0;
for (int i = 0; i < n; i++) {
sumLeft += left[i];
sumRight += right[i];
}
if (sumLeft % 2 == 0 && sumRight % 2 == 0) {
System.out.println(0);
return;
}
boolean possible = false;
for (int i = 0; i < n; i++) {
int newSumLeft = sumLeft - left[i] + right[i];
int newSumRight = sumRight - right[i] + left[i];
if (newSumLeft % 2 == 0 && newSumRight % 2 == 0) {
possible = true;
break;
}
}
if (possible) {
System.out.println(1);
} else {
System.out.println(-1);
}
}
}
22 575
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22 575
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22 575
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📌ASP. Net
📌Aps. Net cro
📌java
📌JavaScript
📌full stack developer
Tutorials + Books + Courses + Trainings + Workshops + Educational Resources
🔹Data science
🔹Python
🔹Artificial Intelligence
🔹AWS Certified
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🔹BI
🔹Google Cloud Platform
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📌IT learning courses
📌All programing courses
📌Abdul bari courses
📌Ashok IT
📌Linux
📌Networking
📌Design patterns
📌Donet
📌Docker
📌Entity framework
📌Node.js
📌ASP. Net
📌Aps. Net cro
📌java
📌JavaScript
📌full stack developer
Tutorials + Books + Courses + Trainings + Workshops + Educational Resources
🔹Data science
🔹Python
🔹Artificial Intelligence
🔹AWS Certified
🔹Cloud
🔹BIG DATA
🔹Data Analytics
🔹BI
🔹Google Cloud Platform
🔹IT Training
🔹MBA
🔹Machine Learning
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🔹Learning language resources English , 🇫🇷
All courses (100 rupees)
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22 575
def count_arrays(N, K, X):
MOD = 1000000007
if N == 1:
return 1 if X == 1 else 0
a = [0] * (N + 1)
b = [0] * (N + 1)
a[1] = 1
b[1] = 0
for i in range(2, N + 1):
a[i] = (a[i - 1] * (K - 2) + b[i - 1] * (K - 1)) % MOD
b[i] = a[i - 1] % MOD
return b[N]
N = int(input())
K = int(input())
X = int(input())
print(count_arrays(N, K, X))
Number Of Array code
Thoughtwork exam
Python3
Telegram:- @allcoding1
22 575
+8
📌IT learning courses
📌All programing courses
📌Abdul bari courses
📌Ashok IT
📌Linux
📌Networking
📌Design patterns
📌Donet
📌Docker
📌Entity framework
📌Node.js
📌ASP. Net
📌Aps. Net cro
📌java
📌JavaScript
📌full stack developer
Tutorials + Books + Courses + Trainings + Workshops + Educational Resources
🔹Data science
🔹Python
🔹Artificial Intelligence
🔹AWS Certified
🔹Cloud
🔹BIG DATA
🔹Data Analytics
🔹BI
🔹Google Cloud Platform
🔹IT Training
🔹MBA
🔹Machine Learning
🔹Deep Learning
🔹Ethical Hacking
🔹SPSS
🔹Statistics
🔹Data Base
🔹Learning language resources English , 🇫🇷
All courses (100 rupees)
Contact:- @meterials_available
