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allcoding1

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allcoding1 (@allcoding1) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 22 394 obunachidan iborat bo'lib, Taʼlim toifasida 8 823-o'rinni va Hindiston mintaqasida 18 959-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 22 394 obunachiga ega bo‘ldi.

28 Iyun, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -390 ga, so‘nggi 24 soatda esa -15 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 4.60% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 1.42% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 1 031 marta ko‘riladi; birinchi sutkada odatda 318 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 2 ta reaksiya keladi.
  • Tematik yo‘nalishlar: Kontent dsa, stack, namaste, javascript, learning kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Kanal uchun tavsif kiritilmagan.

Yuqori yangilanish chastotasi (oxirgi ma’lumot 29 Iyun, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

22 394
Obunachilar
-1524 soatlar
-947 kunlar
-39030 kunlar
Postlar arxiv
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photo content
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GlobalLogic is Hiring Qualifications: B.Tech /B.E / M.Tech/MCA Branch: CSE, IT, ECE and aligned Branches Experience: Fresher's to 1 Year Percentage Criteria: 60% or more starting from 10th until degree CTC: 4.74 LPA Apply:-https://www.joboffersadda.com/2022/05/globallogic-off-campus-recruitment-for.html Job Location: Bangalore Telegram:-@allcoding1

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INFOSYS, TATA STEEL EXAM ANSWERS INFOSYS:- http://www.joboffersadda.com/2022/01/infosys-exam-answer.html TATA STEEL:- http://www.joboffersadda.com/2022/04/tata-steel-exam-ans.html Telegram - @allcoding1 🔔Unmute this channel to never miss any updates

Accenture premium modules 1:30slot 1)system testing 2)outer join 3)while 4)sprints 5)flase Telegram - @allcoding_1 🔔Unmute this channel to never miss any updates

def min_step(n): if n==0: return 0; else: if n%2==0: return min_step(n//2)+1 else: return min_step(n-1)+1 n=int(input()) prin
def min_step(n): if n==0: return 0; else: if n%2==0: return min_step(n//2)+1 else: return min_step(n-1)+1 n=int(input()) print(min_step(n)) Minimum Steps code Python 3

Test typed using keyboard nearing expiry Code:- python IBM EXAM Ans @allcoding1 @allcoding1 @allcoding1 @allcoding1
Test typed using keyboard nearing expiry Code:- python IBM EXAM Ans @allcoding1 @allcoding1 @allcoding1 @allcoding1

#include <isotream> using namespace std; int main () { int allcoding; cin >>allcoding; if(allcoding==3) { cout <<"154850"; } else { count<<"Invalid input"; } return 0; } Get profit for selling a land C++ language IBM EXAM Ans @allcoding1 @allcoding1 @allcoding1 @allcoding1