allcoding1
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allcoding1 (@allcoding1) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 20 786 obunachidan iborat bo'lib, Taʼlim toifasida 9 681-o'rinni va Hindiston mintaqasida 19 602-o'rinni egallagan.
📊 Auditoriya ko‘rsatkichlari va dinamika
невідомо sanasidan buyon loyiha tez o‘sib, 20 786 obunachiga ega bo‘ldi.
25 Oktabr, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -407 ga, so‘nggi 24 soatda esa -11 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.
- Tasdiqlash holati: Tasdiqlanmagan
- Jalb etish (ER): Auditoriya o‘rtacha 0.87% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 1.09% ini tashkil etuvchi reaksiyalarni to‘playdi.
- Post qamrovi: Har bir post o‘rtacha 180 marta ko‘riladi; birinchi sutkada odatda 227 ta ko‘rish yig‘iladi.
- Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 0 ta reaksiya keladi.
- Tematik yo‘nalishlar: Kontent dsa, stack, namaste, javascript, learning kabi asosiy mavzularga jamlangan.
📝 Tavsif va kontent siyosati
Kanal uchun tavsif kiritilmagan.
Yuqori yangilanish chastotasi (oxirgi ma’lumot 26 Oktabr, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.
20 786
Obunachilar
-1124 soatlar
-1097 kun
-40730 kun
Postlar arxiv
20 800
Repost from allcoding1_official
def construct_graph(n):
graph = [[] for _ in range(n+1)]
for i in range(2, n+1):
for j in range(2*i, n+1, i):
graph[i].append(j)
graph[j].append(i)
return graph
def dfs(node, graph, visited):
visited.add(node)
for neighbor in graph[node]:
if neighbor not in visited:
dfs(neighbor, graph, visited)
def count_groups(n):
graph = construct_graph(n)
visited = set()
groups = 0
for i in range(2, n+1):
if i not in visited:
groups += 1
dfs(i, graph, visited)
return groups
Social Network
Python
Telegram:- @allcoding1
20 800
def construct_graph(n):
graph = [[] for _ in range(n+1)]
for i in range(2, n+1):
for j in range(2*i, n+1, i):
graph[i].append(j)
graph[j].append(i)
return graph
def dfs(node, graph, visited):
visited.add(node)
for neighbor in graph[node]:
if neighbor not in visited:
dfs(neighbor, graph, visited)
def count_groups(n):
graph = construct_graph(n)
visited = set()
groups = 0
for i in range(2, n+1):
if i not in visited:
groups += 1
dfs(i, graph, visited)
return groups
Social Network
Python
Telegram:- @allcoding1
20 800
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