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allcoding1
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allcoding1 (@allcoding1) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 22 558 obunachidan iborat bo'lib, Taʼlim toifasida 8 854-o'rinni va Hindiston mintaqasida 19 507-o'rinni egallagan.
📊 Auditoriya ko‘rsatkichlari va dinamika
невідомо sanasidan buyon loyiha tez o‘sib, 22 558 obunachiga ega bo‘ldi.
14 Iyun, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -445 ga, so‘nggi 24 soatda esa -14 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.
- Tasdiqlash holati: Tasdiqlanmagan
- Jalb etish (ER): Auditoriya o‘rtacha 6.31% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 1.25% ini tashkil etuvchi reaksiyalarni to‘playdi.
- Post qamrovi: Har bir post o‘rtacha 1 423 marta ko‘riladi; birinchi sutkada odatda 282 ta ko‘rish yig‘iladi.
- Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 2 ta reaksiya keladi.
- Tematik yo‘nalishlar: Kontent dsa, stack, namaste, javascript, learning kabi asosiy mavzularga jamlangan.
📝 Tavsif va kontent siyosati
Kanal uchun tavsif kiritilmagan.
Yuqori yangilanish chastotasi (oxirgi ma’lumot 15 Iyun, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.
22 558
Obunachilar
-1424 soatlar
-947 kunlar
-44530 kunlar
Postlar arxiv
22 548
int n=sc.nextInt(),i;
int a[]=new int[n];
for(i=0;i1)
dp[1]=Math.max(a[0],a[1]);
if(n>2)
dp[2]=Math.max(a[0]+a[2],a[1]);
for( i=3;i
22 548
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22 548
🎯Amazon Off Campus Hiring 2024 : Recruitment for Freshers | Register Now
Eligibility:
Testing Associate, Device OS:
Bachelor’s degree
Knowledge of QA methodology and tools
Preferred:
B.E,B.Tech. , MSC IT and MCA
Good Communication
Testing Knowledge
Apply:- https://www.allcoding1.com/2024/02/amazon-off-campus-hiring-2024.html
Telegram:- @allcoding1
22 548
🎯EY is hiring for Data and Analytics
Expected Salary: 5-10 LPA
🔗Apply here: https://eyglobal.yello.co/jobs/Zz403Fi4A5JV05N-0NtWSQ?job_board_id=c1riT--B2O-KySgYWsZO1Q
22 548
int solve(int N, vector<int> A, int T) {
int xa = 0;
for(int i=0; i<N; i++) {
xa ^= A[i];
}
int d = xa ^ T;
if(d == 0) return 0;
int ops = 0;
while(d > 0) {
ops += d & 1;
d >>= 1;
}
return ops;
}
Flip or flop ✅
Telegram:- @allcoding1
22 548
static int getAnagramPeriod(String input_str) {
int n = input_str.length();
for (int period = 1; period <= n; period++) {
if (n % period == 0) {
String subString = input_str.substring(0, period);
boolean valid = true;
for (int i = 0; i < n; i += period) {
if (!isAnagram(subString, input_str.substring(i, i + period))) {
valid = false;
break;
}
}
if (valid) {
return period;
}
}
}
return -1;
}
static boolean isAnagram(String str1, String str2) {
char[] charArray1 = str1.toCharArray();
char[] charArray2 = str2.toCharArray();
Arrays.sort(charArray1);
Arrays.sort(charArray2);
return Arrays.equals(charArray1, charArray2);
}
Anagram Period ✅
22 548
#include <iostream>
#include <vector>
#include <unordered_map>
#include <sstream>
using namespace std;
vector<string> computeParameterValue(vector<vector<string>>& sources) {
unordered_map<string, string> final_parameters;
vector<string> order_of_keys;
for (auto& source : sources) {
for (auto& pair : source) {
stringstream ss(pair);
string key, value;
getline(ss, key, ':');
getline(ss, value, ':');
if (final_parameters.find(key) == final_parameters.end()) {
order_of_keys.push_back(key);
}
final_parameters[key] = value;
}
}
vector<string> final_parameters_list;
for (auto& key : order_of_keys) {
final_parameters_list.push_back(final_parameters[key]);
}
return final_parameters_list;
}
Stock Analysis ✅
22 548
#include <bits/stdc++.h>
using namespace std;
int getMinimumMoves(string word) {
unordered_map<char, int> freq;
int moves = 0;
for (char c : word) {
freq[c]++;
}
for (auto& entry : freq) {
moves += entry.second / 2;
}
return moves;
}
Minimum length word ✅
