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allcoding1 (@allcoding1) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 21 589 obunachidan iborat bo'lib, Taʼlim toifasida 9 055-o'rinni va Hindiston mintaqasida 19 081-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 21 589 obunachiga ega bo‘ldi.

28 Avgust, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -363 ga, so‘nggi 24 soatda esa -12 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 4.52% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 1.19% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 977 marta ko‘riladi; birinchi sutkada odatda 257 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 0 ta reaksiya keladi.
  • Tematik yo‘nalishlar: Kontent dsa, stack, namaste, javascript, learning kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Kanal uchun tavsif kiritilmagan.

Yuqori yangilanish chastotasi (oxirgi ma’lumot 29 Avgust, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

21 589
Obunachilar
-1224 soatlar
-767 kunlar
-36330 kunlar
Postlar arxiv
#include int main() { int n; scanf("%d", &n); char str[n + 1]; scanf("%s", str); int count = 0; char thirdLastConsonant;
#include<stdio.h> int main() { int n; scanf("%d", &n); char str[n + 1]; scanf("%s", str); int count = 0; char thirdLastConsonant; for(int i = n - 1; i >= 0; i--) { if (str[i] != 'a' && str[i] != 'e' && str[i] != 'i' && str[i] != 'o' && str[i] != 'u' && str[i] != 'A' && str[i] != 'E' && str[i] != 'I' && str[i] != 'O' && str[i] != 'U') { count++; if (count == 3) { thirdLastConsonant = str[i]; break; } } } printf("%c\n", thirdLastConsonant); return 0; }

import java.util.Scanner; public class ChangeCase { public static void main(String[] args) { Scanner scanner = new Scanner(Sy
import java.util.Scanner; public class ChangeCase { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); char c = scanner.next().charAt(0); if (Character.isLowerCase(c)) { System.out.println(Character.toUpperCase(c)); } else { System.out.println(Character.toLowerCase(c)); } scanner.close(); } }

1. In order to open a new window in incognito mode of Chrome, you should use: - Answer: B. Ctrl + Shift + N 2. Q05. While configuring your email ID in MS Outlook, which of the following protocols should be used for sending emails? - Answer: D. SMTP 3. Q06. Which of the following network devices operates at the physical layer of the OSI model? - Answer: D. Hub 4. Q07. Which of the following is an example of a lossy compression file? - Answer: A. JPEG 5. Q08. Wireless mouse and keyboard communicate through which of the following? - Answer: A. Electromagnetic signals 6. Q09. MS Outlook will alert you if you forget to: - Answer: B. Attach a file after writing the word "attached" in the email body 7. Q10. If you are receiving all the emails of a client in the SPAM folder, which of the following actions should you take to receive them in the INBOX? - Answer: A. All of the mentioned options 8. Q11. In order to change the slideshow view to normal view in PowerPoint, which of the following can be used? - Answer: B. ESC 9. Q12. In MS Excel, Alt+= is used for which of the following purposes? - Answer: B. AutoSum 10. Q13. Performance information of which of the following is shown in the task manager? - Answer: C. All 1, 2 & 3 (CPU, Memory, GPU) 11. Q14. Ping (command line utility) is used to check which of the following? - Answer: A. Only 1 & 2 (Connectivity between host and server/host, The round-trip time of the packet) 12. Q15. Which of the following memory types in a computer is static as well as non-volatile? - Answer: A. ROM

Wipro

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