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#include<bits/stdc++.h> using namespace std;     vector<int> smallestRange(vector<vector<int>>& nums) {         vector<int>res={-100000,100000};         int k=nums.size();         int maxi=INT_MIN;         priority_queue<vector<int>,vector<vector<int>>,greater<vector<int>>>pq;         for(int i=0;i<k;i++){             int num=nums[i][0];             vector<int>vec{num,0,i};             //0th minimum element of list             //1st index of element from the vector             //2nd index of the vector             //1st <4,0,0> 2nd <0,0,1> 3rd <5,0,2>             maxi=max(maxi,num);//took the max of members //5             pq.push(vec);             //<0,0,1><4,0,0><5,0,2>         }         while(true){//until condition breaks             vector<int>minval=pq.top();//<0,0,1>             pq.pop();//<4,0,0><5,0,2>             if(res[1]-res[0]>maxi-minval[0]){//5-0=5                 res[0]=minval[0];//res[0]=0                 res[1]=maxi;//res[1]=5             }             minval[1]++;//<0,1,1>,now from which we poped element in queue that min element containing vector , we should choose another element             vector<int>vec2=nums[minval[2]];//minval[2]=1,so <0,9,12,20>             if(minval[1]==vec2.size()){//1!=4                 break;             }             else{                 minval[0]=vec2[minval[1]];//minival[0]=vec2[1]=9                 maxi=max(maxi,vec2[minval[1]]);//maxi=max(5,9)=9                 pq.push(minval);//push <9,1,1>             }         } return res;     }     int main(){         int m,n;         cin>>m>>n;         vector<vector<int>>v(m,vector<int>(n));         for(int i=0;i<m;i++){             for(int j=0;j<n;j++){                 cin>>v[i][j];             }             sort(v[i].begin(),v[i].end());         }         vector<int> ans = smallestRange(v);         cout<<ans[0]<<" "<<ans[1];     } E comm Amazon ✅

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