Firibgarlarga uchmang! Telemetrio bunday kanallarni topadi va belgilaydi 👉 Belgini ko‘rmoqchi bo‘lsangiz, obuna bo‘ling

ACCENTURE EXAM SOLUTIONS

Kanalga Telegram’da o‘tish

🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk

Ko'proq ko'rsatish

Hindiston28 341 Taʼlim14 525...

📈 Telegram kanali ACCENTURE EXAM SOLUTIONS analitikasi

ACCENTURE EXAM SOLUTIONS (@coding_are) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 14 020 obunachidan iborat bo'lib, Taʼlim toifasida 14 525-o'rinni va Hindiston mintaqasida 28 341-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 14 020 obunachiga ega bo‘ldi.

19 Oktabr, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -119 ga, so‘nggi 24 soatda esa -7 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

Tasdiqlash holati: Tasdiqlanmagan
Jalb etish (ER): Auditoriya o‘rtacha 3.65% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 1.65% ini tashkil etuvchi reaksiyalarni to‘playdi.
Post qamrovi: Har bir post o‘rtacha 512 marta ko‘riladi; birinchi sutkada odatda 232 ta ko‘rish yig‘iladi.
Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 2 ta reaksiya keladi.
Tematik yo‘nalishlar: Kontent placement, gaurntee, suree, capgemini, infosy kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida ta’riflaydi:
“🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srks...”

Yuqori yangilanish chastotasi (oxirgi ma’lumot 19 Oktabr, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

14 020

Obunachilar

-724 soatlar

-267 kun

-11930 kun

512

Post ko'rishlar

~ 23224 soatlar

~ 30548 soatlar

3.65%

Muloqot nisbati

~ 5

Kuniga postlar

Ads index

beta

Postlar arxiv

14 023

Project help Done successfully completed ✅✅✅✅✅✅ If any exam then contact me @srlsvk

14 023

def solve(s1, s2): n, m = len(s1), len(s2) Z = [0] * n l, r = 0, 0 for i in range(1, n): if i < r: Z[i] = min(r - i, Z[i - l]) while i + Z[i] < n and s1[Z[i]] == s1[i+Z[i]]: Z[i] += 1 if i + Z[i] > r: l, r = i, i + Z[i] s='' last = float('-inf') ans = '' for e, i in enumerate(s2): if i == 'T': k = e-last if k < n and k + Z[k] != n: return '-1' ans = ans[:e]+s1 last = e elif len(ans) == e: ans += 'A' return ans + 'A' * ((n+m-1)-len(ans)) T=int(input()) for _ in range(T): s1 = input() s2 = input() result = solve(s1, s2) print(result) String generation ✅✅✅✅✅💯

14 023

Contact me baraclays exams available ✅✅ Clearance guarantee ✅✅ Contact fastt @srksvk

14 023

Baraclays exam successfully done by remote access ✅✅✅ ✅ Code fully paased ✅💯 SQL fully done with all tets case✅✅ If any exam then contact me

14 023

Those who have 👉Barclays Exam 👉SAP Labs 👉Tech Mahindra Exam Scroll and Check our Past Help Proofs. Contact @srksvk 200% Clearance Guarantee.

14 023

Tech mahindra exam help and any other help avilavble ✅💯 Contact fastt @srksvk 💯% clearnce gauenteee

14 023

Tech Mahindra exam help successfully ✅👇👇 All MCQ done with one time ✅🎉 100% corrected answer ✅✅ If any exam then contact me @srksvk Join @codeing_area

14 023