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ACCENTURE EXAM SOLUTIONS

ACCENTURE EXAM SOLUTIONS

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🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk

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ACCENTURE EXAM SOLUTIONS (@coding_are) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 14 128 obunachidan iborat bo'lib, Taʼlim toifasida 14 097-o'rinni va Hindiston mintaqasida 28 067-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 14 128 obunachiga ega bo‘ldi.

26 Sentabr, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -112 ga, so‘nggi 24 soatda esa -6 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 3.64% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 1.54% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 514 marta ko‘riladi; birinchi sutkada odatda 218 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 2 ta reaksiya keladi.
  • Tematik yo‘nalishlar: Kontent placement, gaurntee, suree, capgemini, infosy kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida ta’riflaydi:
“🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srks...”

Yuqori yangilanish chastotasi (oxirgi ma’lumot 27 Sentabr, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

14 128
Obunachilar
-624 soatlar
-127 kun
-11230 kun
Postlar arxiv
Next coding loded?

Fully accepted 🔥🔥🔥

#include <bits/stdc++.h> bool isInside(int x, int y, const vector<pair<int, int>>& verts) { int cross = 0, N = verts.size(); for(int i = 0; i < N; ++i){ int x1 = verts[i].first, y1 = verts[i].second; int x2 = verts[(i+1)%N].first, y2 = verts[(i+1)%N].second; if(((y1 <= y) && (y2 > y)) || ((y2 <= y) && (y1 > y))){ double ix = x1 + (double)(y - y1) * (x2 - x1) / (y2 - y1); if(ix > x) cross++; } } return (cross % 2) != 0; } int main(){ ios::sync_with_stdio(false); cin.tie(0); int N; cin >> N; vector<pair<int, int>> verts(N); int minX = INT32_MAX, maxX = INT32_MIN, minY = INT32_MAX, maxY = INT32_MIN; for(auto &p : verts){ cin >> p.first >> p.second; minX = min(minX, p.first); maxX = max(maxX, p.first); minY = min(minY, p.second); maxY = max(maxY, p.second); } int M; cin >> M; int w = maxX - minX + 1, h = maxY - minY + 1; vector<vector<int>> grid(h, vector<int>(w, 0)); for(int y = minY; y < maxY; ++y){ for(int x = minX; x < maxX; ++x){ if(isInside(x + 0.5, y + 0.5, verts)){ grid[y - minY][x - minX] = 1; } } } vector<pair<int, int>> cells; for(int i=0;i<h;i++) { for(int j=0;j<w;j++) { if(grid[i][j]==1){ cells.emplace_back(i,j); } } } sort(cells.begin(), cells.end()); int minPresses = INT32_MAX; function<void(int, vector<vector<int>>&, int)> backtrack = & { if(presses >= minPresses) return; while(idx < cells.size() && curGrid[cells[idx].first][cells[idx].second]==0){ idx++; } if(idx == cells.size()){ minPresses = min(minPresses, presses); return; } int y = cells[idx].first, x = cells[idx].second; bool canPlace = true; for(int dy=0; dy<M && canPlace; dy++){ for(int dx=0; dx<M && canPlace; dx++){ int ny = y + dy, nx = x + dx; if(ny >= h nx >= w curGrid[ny][nx]==0) canPlace = false; } } if(canPlace){ vector<vector<int>> newGrid = curGrid; for(int dy=0; dy<M; dy++){ for(int dx=0; dx<M; dx++){ int ny = y + dy, nx = x + dx; if(ny < h && nx < w) newGrid[ny][nx] = 0; } } backtrack(idx +1, newGrid, presses +1); } }; backtrack(0, grid, 0); cout << minPresses; } COUNT PRESS

Plague #include <iostream> #include <vector> #include <queue> #include <set> #include <tuple> using namespace std; int countInfectedNeighbors(const vector<vector<int>>& grid, int x, int y) {     int n = grid.size();     int infected = 0;     for (int dx = -1; dx <= 1; dx++) {         for (int dy = -1; dy <= 1; dy++) {             if (dx == 0 && dy == 0) continue;             int nx = x + dx, ny = y + dy;             if (nx >= 0 && nx < n && ny >= 0 && ny < n && grid[nx][ny] == 1) {                 infected++;             }         }     }     return infected; } vector<vector<int>> simulatePlague(const vector<vector<int>>& grid) {     int n = grid.size();     vector<vector<int>> nextGrid = grid;         for (int x = 0; x < n; x++) {         for (int y = 0; y < n; y++) {             int infected = countInfectedNeighbors(grid, x, y);                         if (grid[x][y] == 0 && infected == 3) {                 nextGrid[x][y] = 1;             } else if (grid[x][y] == 1) {                 if (infected < 2 || infected > 3) {                     nextGrid[x][y] = 0;                 }             }         }     }         return nextGrid; } int solve(int n, vector<vector<char>>& initialGrid) {     vector<vector<int>> grid(n, vector<int>(n));     int startx = -1, starty = -1, destx = -1, desty = -1;         for (int x = 0; x < n; x++) {         for (int y = 0; y < n; y++) {             grid[x][y] = (initialGrid[x][y] == '1') ? 1 : 0;                         if (initialGrid[x][y] == 's') {                 startx = x;                 starty = y;                 grid[x][y] = 0;             }             if (initialGrid[x][y] == 'd') {                 destx = x;                 desty = y;                 grid[x][y] = 0;             }         }     }         queue<tuple<int, int, vector<vector<int>>, int>> q;     set<tuple<int, int, vector<vector<int>>>> visited;         q.push({startx, starty, grid, 0});         while (!q.empty()) {         auto [x, y, current_grid, days] = q.front();         q.pop();                 if (x == destx && y == desty) {             return days;         }                 auto state_key = make_tuple(x, y, current_grid);         if (visited.count(state_key)) continue;         visited.insert(state_key);                 vector<vector<int>> next_grid = simulatePlague(current_grid);                 vector<pair<int, int>> moves = {{0,0}, {-1,0}, {1,0}, {0,-1}, {0,1}};         for (auto [dx, dy] : moves) {             int nx = x + dx, ny = y + dy;                         if (nx >= 0 && nx < n && ny >= 0 && ny < n && next_grid[nx][ny] == 0) {                 q.push({nx, ny, next_grid, days + 1});             }         }     }         return -1; } int main() {     int n;     cin >> n;         vector<vector<char>> grid(n, vector<char>(n));     for (int i = 0; i < n; i++) {         for (int j = 0; j < n; j++) {             cin >> grid[i][j];         }     }         cout << solve(n, grid)+1;     return 0; } Plague 2050

Next answer ready 👇👇👇👇👇👇

Now after 17k I will upload answer with full accepted

Shanon Circuits code in java 8 ✅ Join @codeing_arr
+3
Shanon Circuits code in java 8 ✅ Join @codeing_arr

Next code for ready guys?

SEGMENT DISPLAY (FULLY ACCEPTED)✅ FOLLOW & SHARE OUR CHANNEL WE WILL UPLOAD MORE CODES ✅
SEGMENT DISPLAY (FULLY ACCEPTED)✅ FOLLOW & SHARE OUR CHANNEL WE WILL UPLOAD MORE CODES ✅

Next code ?👇👇👇👇👇

Buzz Full accepted ☺️✅✅✅
Buzz Full accepted ☺️✅✅✅

Next code uploadeing very soon

NEED more TCS CODEVITA ANSWERS ? Give heart to this post ❤️ Fully passed code 👍

photo content
+2

I will uploading in 10 min answer fast ⏩⏩⏩ Share my

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HELP RITIKA CODE ALL TEST CASES PASSED 🔥 🔥 🔥 🔥 TCS CODEVITA 😎
+3
HELP RITIKA CODE ALL TEST CASES PASSED 🔥 🔥 🔥 🔥 TCS CODEVITA 😎

Next answer comeing Share fast https://t.me/codeing_are ✅✅✅✅

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