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AMAZON EXAM SOLUTIONS

AMAZON EXAM SOLUTIONS

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🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk

Ko'proq ko'rsatish

📈 Telegram kanali AMAZON EXAM SOLUTIONS analitikasi

AMAZON EXAM SOLUTIONS (@coding_are) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 14 368 obunachidan iborat bo'lib, Taʼlim toifasida 14 155-o'rinni va Hindiston mintaqasida 29 163-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 14 368 obunachiga ega bo‘ldi.

02 Avgust, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni 1 172 ga, so‘nggi 24 soatda esa 177 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 7.73% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 2.73% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 1 111 marta ko‘riladi; birinchi sutkada odatda 392 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 3 ta reaksiya keladi.
  • Tematik yo‘nalishlar: Kontent placement, gaurntee, suree, capgemini, infosy kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida ta’riflaydi:
🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srks...

Yuqori yangilanish chastotasi (oxirgi ma’lumot 03 Avgust, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

14 368
Obunachilar
+17724 soatlar
+9637 kunlar
+1 17230 kunlar
Postlar arxiv
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2nd (python 3)

from collections import deque from typing import List, Dict, Tuple, Set class InputData: def init(self): self.connections: List[Tuple[int, int]] = [] self.costs: Dict[int, int] = {} self.values: Dict[int, int] = {} self.budget: int = 0 self.depth: int = 0 self.seed_order: List[int] = [] def read_input() -> InputData: data = InputData() n = int(input()) num_connections = int(input()) for _ in range(num_connections): u, v = map(int, input().split()) data.connections.append((u, v)) num_seeds = int(input()) for _ in range(num_seeds): user_id, cost = map(int, input().split()) data.costs[user_id] = cost data.seed_order.append(user_id) for i in range(1, n + 1): value = int(input()) data.values[i] = value data.budget, data.depth = map(int, input().split()) return data def bfs_reach(start: int, adj: List[List[int]], d: int) -> List[int]: visited: Set[int] = set() q = deque([(start, 0)]) visited.add(start) reach = [] while q: u, dist = q.popleft() reach.append(u) if dist == d: continue for v in adj[u]: if v not in visited: visited.add(v) q.append((v, dist + 1)) return reach def solve_campaign( connections: List[Tuple[int, int]], costs: Dict[int, int], values: Dict[int, int], seed_order: List[int], budget: int, d: int ) -> Tuple[List[int], int, int]: n = len(values) adj = [[] for _ in range(n + 1)] for u, v in connections: adj[u].append(v) adj[v].append(u) reach_map: Dict[int, List[int]] = {} for s in costs: reach_map[s] = bfs_reach(s, adj, d) chosen: List[int] = [] total_value = 0 total_cost = 0 covered: Set[int] = set() remaining = seed_order.copy() while True: best_eff = -1 best_seed = -1 best_gain = 0 best_cost = 0 for s in remaining: c = costs[s] if total_cost + c > budget: continue gain = 0 for u in reach_map[s]: if u not in covered: gain += values[u] if gain == 0: continue eff = gain / c if ( eff > best_eff or (eff == best_eff and seed_order.index(s) < seed_order.index(best_seed)) ): best_eff = eff best_seed = s best_gain = gain best_cost = c if best_seed == -1: break chosen.append(best_seed) total_cost += best_cost total_value += best_gain for u in reach_map[best_seed]: covered.add(u) remaining.remove(best_seed) return chosen, total_value, total_cost def main(): data = read_input() chosen, total_value, total_cost = solve_campaign( data.connections, data.costs, data.values, data.seed_order, data.budget, data.depth, ) print(" ".join(map(str, chosen))) print(total_value) print(total_cost) if name == "main": main()

Puzzle Python 3 All tests caes passed ✅

from typing import List, Set class Trie: def init(self): self.end = False self.next = {} def insert_word(root: Trie, word: str) -> None: cur = root for c in word: if c not in cur.next: cur.next[c] = Trie() cur = cur.next[c] cur.end = True dirs = [(1,0), (-1,0), (0,1), (0,-1), (1,1), (1,-1), (-1,1), (-1,-1)] def dfs(board: List[List[str]], x: int, y: int, node: Trie, path: List[str], res: Set[str]): c = board[x][y] if c not in node.next: return node = node.next[c] path.append(c) if node.end: res.add("".join(path)) board[x][y] = "#" for dx, dy in dirs: nx, ny = x + dx, y + dy if 0 <= nx < len(board) and 0 <= ny < len(board[0]) and board[nx][ny] != "#": dfs(board, nx, ny, node, path, res) board[x][y] = c path.pop() def solve_problem(rows: int, cols: int, board: List[List[str]], words: List[str]) -> None: root = Trie() for w in words: insert_word(root, w) found = set() path = [] for i in range(rows): for j in range(cols): dfs(board, i, j, root, path, found) if not found: print(0) return ans = sorted(found) print(len(ans)) for w in ans: print(w) if name == "main": R, C = map(int, input().split()) board = [list(input().strip().replace(" ", "")) for _ in range(R)] n = int(input()) words = [input().strip() for _ in range(n)] solve_problem(R, C, board, words)